Removing the zip code from a python list (to obtain the state name from MapQuest output)











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This should be simple, but could not get it to work.



I have some strings returned to me by the geolocation MapQuest API. I want to isolate the state name from strings like these, which is kind of hard. Think of 'Pennsylvania Avenue' (which is in D.C.), then there is 'Washington', which can be a state, as well as a street name, and a city.



s = "Goldman Sachs Tower, 200, West Street, Battery Park City, Manhattan Community Board 1, New York County, NYC, New York, 10282, United States of America"
s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"
s = "Casper, Natrona County, Wyoming, United States of America"


But I noticed that MapQuest writes the state name just before the zip code, near the end of the string.



To obtain the state name, this works, that is, if there is a zip code:



s = s.split(",")
s = [x.strip() for x in s]
state = s[-3]


However, when there is no zip code, as in the third string, then I get the county (Natrona County).



I tried to eliminate the zip code by:



s = s.split(",")
s = [x.strip() for x in s if 'd{5}' not in x ]


But the regex 'd{5}' does not work - I want Wyoming, not Natrona County.










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  • are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
    – Jack Herer
    Nov 11 at 7:52










  • yep, I indeed import re
    – Martien Lubberink
    Nov 11 at 8:01

















up vote
1
down vote

favorite
1












This should be simple, but could not get it to work.



I have some strings returned to me by the geolocation MapQuest API. I want to isolate the state name from strings like these, which is kind of hard. Think of 'Pennsylvania Avenue' (which is in D.C.), then there is 'Washington', which can be a state, as well as a street name, and a city.



s = "Goldman Sachs Tower, 200, West Street, Battery Park City, Manhattan Community Board 1, New York County, NYC, New York, 10282, United States of America"
s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"
s = "Casper, Natrona County, Wyoming, United States of America"


But I noticed that MapQuest writes the state name just before the zip code, near the end of the string.



To obtain the state name, this works, that is, if there is a zip code:



s = s.split(",")
s = [x.strip() for x in s]
state = s[-3]


However, when there is no zip code, as in the third string, then I get the county (Natrona County).



I tried to eliminate the zip code by:



s = s.split(",")
s = [x.strip() for x in s if 'd{5}' not in x ]


But the regex 'd{5}' does not work - I want Wyoming, not Natrona County.










share|improve this question






















  • are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
    – Jack Herer
    Nov 11 at 7:52










  • yep, I indeed import re
    – Martien Lubberink
    Nov 11 at 8:01















up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





This should be simple, but could not get it to work.



I have some strings returned to me by the geolocation MapQuest API. I want to isolate the state name from strings like these, which is kind of hard. Think of 'Pennsylvania Avenue' (which is in D.C.), then there is 'Washington', which can be a state, as well as a street name, and a city.



s = "Goldman Sachs Tower, 200, West Street, Battery Park City, Manhattan Community Board 1, New York County, NYC, New York, 10282, United States of America"
s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"
s = "Casper, Natrona County, Wyoming, United States of America"


But I noticed that MapQuest writes the state name just before the zip code, near the end of the string.



To obtain the state name, this works, that is, if there is a zip code:



s = s.split(",")
s = [x.strip() for x in s]
state = s[-3]


However, when there is no zip code, as in the third string, then I get the county (Natrona County).



I tried to eliminate the zip code by:



s = s.split(",")
s = [x.strip() for x in s if 'd{5}' not in x ]


But the regex 'd{5}' does not work - I want Wyoming, not Natrona County.










share|improve this question













This should be simple, but could not get it to work.



I have some strings returned to me by the geolocation MapQuest API. I want to isolate the state name from strings like these, which is kind of hard. Think of 'Pennsylvania Avenue' (which is in D.C.), then there is 'Washington', which can be a state, as well as a street name, and a city.



s = "Goldman Sachs Tower, 200, West Street, Battery Park City, Manhattan Community Board 1, New York County, NYC, New York, 10282, United States of America"
s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"
s = "Casper, Natrona County, Wyoming, United States of America"


But I noticed that MapQuest writes the state name just before the zip code, near the end of the string.



To obtain the state name, this works, that is, if there is a zip code:



s = s.split(",")
s = [x.strip() for x in s]
state = s[-3]


However, when there is no zip code, as in the third string, then I get the county (Natrona County).



I tried to eliminate the zip code by:



s = s.split(",")
s = [x.strip() for x in s if 'd{5}' not in x ]


But the regex 'd{5}' does not work - I want Wyoming, not Natrona County.







python geolocation






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asked Nov 11 at 7:46









Martien Lubberink

600612




600612












  • are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
    – Jack Herer
    Nov 11 at 7:52










  • yep, I indeed import re
    – Martien Lubberink
    Nov 11 at 8:01




















  • are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
    – Jack Herer
    Nov 11 at 7:52










  • yep, I indeed import re
    – Martien Lubberink
    Nov 11 at 8:01


















are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
– Jack Herer
Nov 11 at 7:52




are you importing the re module? and then setting up your regex for searching etc? If not I suggest you read docs.python.org/3/library/re.html
– Jack Herer
Nov 11 at 7:52












yep, I indeed import re
– Martien Lubberink
Nov 11 at 8:01






yep, I indeed import re
– Martien Lubberink
Nov 11 at 8:01














1 Answer
1






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oldest

votes

















up vote
2
down vote



accepted










Use re:



import re

s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"

s = s.split(",")
number = re.compile(r"d{5}")
s = [x.strip() for x in s if not number.search(x)]
print s
print s[-2]


output:



['9th St NW', 'Logan Circle/Shaw', 'Washington', 'District of Columbia', 'United States of America']
District of Columbia


Here is some small easy tutorial on it: regex tutorial






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote



    accepted










    Use re:



    import re

    s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"

    s = s.split(",")
    number = re.compile(r"d{5}")
    s = [x.strip() for x in s if not number.search(x)]
    print s
    print s[-2]


    output:



    ['9th St NW', 'Logan Circle/Shaw', 'Washington', 'District of Columbia', 'United States of America']
    District of Columbia


    Here is some small easy tutorial on it: regex tutorial






    share|improve this answer

























      up vote
      2
      down vote



      accepted










      Use re:



      import re

      s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"

      s = s.split(",")
      number = re.compile(r"d{5}")
      s = [x.strip() for x in s if not number.search(x)]
      print s
      print s[-2]


      output:



      ['9th St NW', 'Logan Circle/Shaw', 'Washington', 'District of Columbia', 'United States of America']
      District of Columbia


      Here is some small easy tutorial on it: regex tutorial






      share|improve this answer























        up vote
        2
        down vote



        accepted







        up vote
        2
        down vote



        accepted






        Use re:



        import re

        s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"

        s = s.split(",")
        number = re.compile(r"d{5}")
        s = [x.strip() for x in s if not number.search(x)]
        print s
        print s[-2]


        output:



        ['9th St NW', 'Logan Circle/Shaw', 'Washington', 'District of Columbia', 'United States of America']
        District of Columbia


        Here is some small easy tutorial on it: regex tutorial






        share|improve this answer












        Use re:



        import re

        s = "9th St NW, Logan Circle/Shaw, Washington, District of Columbia, 20001, United States of America"

        s = s.split(",")
        number = re.compile(r"d{5}")
        s = [x.strip() for x in s if not number.search(x)]
        print s
        print s[-2]


        output:



        ['9th St NW', 'Logan Circle/Shaw', 'Washington', 'District of Columbia', 'United States of America']
        District of Columbia


        Here is some small easy tutorial on it: regex tutorial







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 8:08









        Dinari

        1,231322




        1,231322






























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