Ndtyjky

I am trying to find the min and max of each list in a nested list, and the index of when the min or max occurred:

So that, for example:

l=[[5,6,7][6,10,9,6][2,3,1]]

Becomes:

maxl=[7,10,3]

indexl=[2,1,2]

I've tried this and it seems to get me the max list (no indexes yet) but not for min- does anyone know how best to do this?

maxHap=

for subL in happiness1:

    maxHap.append(max(subL))

print(maxHap)



minHap=

for subL in happiness1:

    minHap.append(min(subL))

print(minHap)

Thank you from a newbie

You can use the method index to get the index of a value of a list:
https://docs.python.org/3/tutorial/datastructures.html

maxl = 

indexl = 

for inner_list in l:

    max_value = max(inner_list)

    maxl.append(max(max_value))

    indexl.append(inner_list.index(max_value)

Other option:

l=[[5,6,7],[6,10,9,6],[2,3,1]]



maxs = [ max(s) for s in l ] #=> [7, 10, 3]

max_idxs = [ s.index(max(s)) for s in l ] #=> [2, 1, 1]

mins = [ min(s) for s in l ] #=> [5, 6, 1]

mins_idxs = [ s.index(min(s)) for s in l ] #=> [0, 0, 2]

mapp = map(lambda x: {'max': max(x), 'max_idxs': x.index(max(x)), 'min': min(x), 'min_idxs': x.index(min(x)) }, l)



for k in mapp:

  print(k)



#=> {'max': 7, 'max_idxs': 2, 'min': 5, 'min_idxs': 0}

#=> {'max': 10, 'max_idxs': 1, 'min': 6, 'min_idxs': 0}

#=> {'max': 3, 'max_idxs': 1, 'min': 1, 'min_idxs': 2}

You can use the following one-liner:

l=[[5,6,7],[6,10,9,6],[2,3,1]]

maxL, index = zip(*[(max(subList), subList.index(max(subList))) for subList in l])

print(maxL) # will output (7, 10, 3)

print(index) # will output (2, 1, 1)