How to split a string that contains a set in Ruby?





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4















I am new to the forum. I am currently trying to take this string:



65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010


and split it in order to get this:



65101km

Sedan

Manual

18131A

FWD

Used

5.5L/100km

Toyota

camry

SE

{AC, Heated Seats, Heated Mirrors, Keyless Entry}

2010


I have the following regex:



data_from_file.split(/[{},]+/)


But I am having a hard time keeping the set.



Any ideas?






ruby regex split







share|improve this question























  • Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

    – vovan
    Nov 16 '18 at 15:57











  • In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

    – Cary Swoveland
    Nov 17 '18 at 20:23




















4















I am new to the forum. I am currently trying to take this string:



65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010


and split it in order to get this:



65101km

Sedan

Manual

18131A

FWD

Used

5.5L/100km

Toyota

camry

SE

{AC, Heated Seats, Heated Mirrors, Keyless Entry}

2010


I have the following regex:



data_from_file.split(/[{},]+/)


But I am having a hard time keeping the set.



Any ideas?






ruby regex split







share|improve this question























  • Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

    – vovan
    Nov 16 '18 at 15:57











  • In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

    – Cary Swoveland
    Nov 17 '18 at 20:23
















4












4








4


1






I am new to the forum. I am currently trying to take this string:



65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010


and split it in order to get this:



65101km

Sedan

Manual

18131A

FWD

Used

5.5L/100km

Toyota

camry

SE

{AC, Heated Seats, Heated Mirrors, Keyless Entry}

2010


I have the following regex:



data_from_file.split(/[{},]+/)


But I am having a hard time keeping the set.



Any ideas?






ruby regex split







share|improve this question














I am new to the forum. I am currently trying to take this string:



65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010


and split it in order to get this:



65101km

Sedan

Manual

18131A

FWD

Used

5.5L/100km

Toyota

camry

SE

{AC, Heated Seats, Heated Mirrors, Keyless Entry}

2010


I have the following regex:



data_from_file.split(/[{},]+/)


But I am having a hard time keeping the set.



Any ideas?






ruby regex split




ruby regex split






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 16 '18 at 15:13









Andres V.Andres V.

234




234













  • Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

    – vovan
    Nov 16 '18 at 15:57











  • In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

    – Cary Swoveland
    Nov 17 '18 at 20:23





















  • Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

    – vovan
    Nov 16 '18 at 15:57











  • In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

    – Cary Swoveland
    Nov 17 '18 at 20:23



















Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

– vovan
Nov 16 '18 at 15:57





Maybe this answer will be useful: stackoverflow.com/questions/42475528/… will hel

– vovan
Nov 16 '18 at 15:57













In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

– Cary Swoveland
Nov 17 '18 at 20:23







In future, please ensure all values in examples are valid Ruby objects. Here that would mean putting the string in quotes and displaying the output as an array of strings (["65101km", "Sedan",..., "2010"]). Here your intent is clear, but if your array had been an input every reader who wanted to use it in code would have to convert it to a valid object. Also, it's helpful to assign a variable to all inputs (here just one) in your example (str = "65101km,..."), so readers can refer to those variables in answers and comments. In case you didn't know, you can upvote answers you checkmark.

– Cary Swoveland
Nov 17 '18 at 20:23














2 Answers
2






active

oldest

votes


















1














You may use



s.scan(/(?:{[^{}]*}|[^,])+/)


See the Rubular and Regex.101 demos.



Pattern details





  • (?: - start of a non-capturing group:



    • {[^{}]*} - {, 0 or more chars other than { and } and then }




  • | - or



    • [^,] - any 1 char other than ,




  • )+ - repeated 1 or more times.






share|improve this answer



















  • 1





    Simple and clean!

    – Cary Swoveland
    Nov 17 '18 at 3:05






  • 1





    This is really nice! Thank you so much

    – Andres V.
    Nov 17 '18 at 17:39



















1














str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"






r = /

    (?<=A|,)  # match the beginning of the string or a comma in a positive lookbehind

    (?:        # begin a non-capture group

      {.*?}    # match an open brace followed by any number of characters,

               # lazily, followed by a closed brace

      |        # or

      .*?      # match any number of characters, lazily 

    )          # close non-capture group

    (?=,|z)   # match a comma or the end of the string in a positive lookahead

    /x         # free-spacing regex definition mode



str.scan r

  #=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",

  #    "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]


Two notes follow. I'll illustrate these with a simpler string.



str = "65101km,Sedan,{AC,Heated Seats},2010"


{.*?} must precede .*? in (?:{.*?}|.*?)



If



r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/


then



str.scan r

  #=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]


The matches .* must be lazy (aka non-greedy)



If



r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/


then



str.scan r

  #=> ["65101km,Sedan,{AC,Heated Seats},2010"]


If



r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/


then



"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r

  #=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]





share|improve this answer


























  • Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

    – Andres V.
    Nov 16 '18 at 16:03






  • 1





    What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

    – Cary Swoveland
    Nov 16 '18 at 16:21






  • 1





    At Regex101, 2010 is matched.

    – Wiktor Stribiżew
    Nov 16 '18 at 16:53











  • just tried it out its perfect! Thanks guys. I had put a space like Gary said.

    – Andres V.
    Nov 17 '18 at 17:37












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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You may use



s.scan(/(?:{[^{}]*}|[^,])+/)


See the Rubular and Regex.101 demos.



Pattern details





  • (?: - start of a non-capturing group:



    • {[^{}]*} - {, 0 or more chars other than { and } and then }




  • | - or



    • [^,] - any 1 char other than ,




  • )+ - repeated 1 or more times.






share|improve this answer



















  • 1





    Simple and clean!

    – Cary Swoveland
    Nov 17 '18 at 3:05






  • 1





    This is really nice! Thank you so much

    – Andres V.
    Nov 17 '18 at 17:39
















1














You may use



s.scan(/(?:{[^{}]*}|[^,])+/)


See the Rubular and Regex.101 demos.



Pattern details





  • (?: - start of a non-capturing group:



    • {[^{}]*} - {, 0 or more chars other than { and } and then }




  • | - or



    • [^,] - any 1 char other than ,




  • )+ - repeated 1 or more times.






share|improve this answer



















  • 1





    Simple and clean!

    – Cary Swoveland
    Nov 17 '18 at 3:05






  • 1





    This is really nice! Thank you so much

    – Andres V.
    Nov 17 '18 at 17:39














1












1








1







You may use



s.scan(/(?:{[^{}]*}|[^,])+/)


See the Rubular and Regex.101 demos.



Pattern details





  • (?: - start of a non-capturing group:



    • {[^{}]*} - {, 0 or more chars other than { and } and then }




  • | - or



    • [^,] - any 1 char other than ,




  • )+ - repeated 1 or more times.






share|improve this answer













You may use



s.scan(/(?:{[^{}]*}|[^,])+/)


See the Rubular and Regex.101 demos.



Pattern details





  • (?: - start of a non-capturing group:



    • {[^{}]*} - {, 0 or more chars other than { and } and then }




  • | - or



    • [^,] - any 1 char other than ,




  • )+ - repeated 1 or more times.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 16 '18 at 16:55









Wiktor StribiżewWiktor Stribiżew

330k16149229




330k16149229








  • 1





    Simple and clean!

    – Cary Swoveland
    Nov 17 '18 at 3:05






  • 1





    This is really nice! Thank you so much

    – Andres V.
    Nov 17 '18 at 17:39














  • 1





    Simple and clean!

    – Cary Swoveland
    Nov 17 '18 at 3:05






  • 1





    This is really nice! Thank you so much

    – Andres V.
    Nov 17 '18 at 17:39








1




1





Simple and clean!

– Cary Swoveland
Nov 17 '18 at 3:05





Simple and clean!

– Cary Swoveland
Nov 17 '18 at 3:05




1




1





This is really nice! Thank you so much

– Andres V.
Nov 17 '18 at 17:39





This is really nice! Thank you so much

– Andres V.
Nov 17 '18 at 17:39













1














str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"






r = /

    (?<=A|,)  # match the beginning of the string or a comma in a positive lookbehind

    (?:        # begin a non-capture group

      {.*?}    # match an open brace followed by any number of characters,

               # lazily, followed by a closed brace

      |        # or

      .*?      # match any number of characters, lazily 

    )          # close non-capture group

    (?=,|z)   # match a comma or the end of the string in a positive lookahead

    /x         # free-spacing regex definition mode



str.scan r

  #=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",

  #    "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]


Two notes follow. I'll illustrate these with a simpler string.



str = "65101km,Sedan,{AC,Heated Seats},2010"


{.*?} must precede .*? in (?:{.*?}|.*?)



If



r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/


then



str.scan r

  #=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]


The matches .* must be lazy (aka non-greedy)



If



r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/


then



str.scan r

  #=> ["65101km,Sedan,{AC,Heated Seats},2010"]


If



r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/


then



"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r

  #=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]





share|improve this answer


























  • Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

    – Andres V.
    Nov 16 '18 at 16:03






  • 1





    What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

    – Cary Swoveland
    Nov 16 '18 at 16:21






  • 1





    At Regex101, 2010 is matched.

    – Wiktor Stribiżew
    Nov 16 '18 at 16:53











  • just tried it out its perfect! Thanks guys. I had put a space like Gary said.

    – Andres V.
    Nov 17 '18 at 17:37
















1














str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"






r = /

    (?<=A|,)  # match the beginning of the string or a comma in a positive lookbehind

    (?:        # begin a non-capture group

      {.*?}    # match an open brace followed by any number of characters,

               # lazily, followed by a closed brace

      |        # or

      .*?      # match any number of characters, lazily 

    )          # close non-capture group

    (?=,|z)   # match a comma or the end of the string in a positive lookahead

    /x         # free-spacing regex definition mode



str.scan r

  #=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",

  #    "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]


Two notes follow. I'll illustrate these with a simpler string.



str = "65101km,Sedan,{AC,Heated Seats},2010"


{.*?} must precede .*? in (?:{.*?}|.*?)



If



r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/


then



str.scan r

  #=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]


The matches .* must be lazy (aka non-greedy)



If



r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/


then



str.scan r

  #=> ["65101km,Sedan,{AC,Heated Seats},2010"]


If



r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/


then



"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r

  #=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]





share|improve this answer


























  • Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

    – Andres V.
    Nov 16 '18 at 16:03






  • 1





    What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

    – Cary Swoveland
    Nov 16 '18 at 16:21






  • 1





    At Regex101, 2010 is matched.

    – Wiktor Stribiżew
    Nov 16 '18 at 16:53











  • just tried it out its perfect! Thanks guys. I had put a space like Gary said.

    – Andres V.
    Nov 17 '18 at 17:37














1












1








1







str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"






r = /

    (?<=A|,)  # match the beginning of the string or a comma in a positive lookbehind

    (?:        # begin a non-capture group

      {.*?}    # match an open brace followed by any number of characters,

               # lazily, followed by a closed brace

      |        # or

      .*?      # match any number of characters, lazily 

    )          # close non-capture group

    (?=,|z)   # match a comma or the end of the string in a positive lookahead

    /x         # free-spacing regex definition mode



str.scan r

  #=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",

  #    "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]


Two notes follow. I'll illustrate these with a simpler string.



str = "65101km,Sedan,{AC,Heated Seats},2010"


{.*?} must precede .*? in (?:{.*?}|.*?)



If



r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/


then



str.scan r

  #=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]


The matches .* must be lazy (aka non-greedy)



If



r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/


then



str.scan r

  #=> ["65101km,Sedan,{AC,Heated Seats},2010"]


If



r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/


then



"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r

  #=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]





share|improve this answer















str = "65101km,Sedan,Manual,18131A,FWD,Used,5.5L/100km,Toyota,camry,SE,{AC,Heated Seats, Heated Mirrors, Keyless Entry},2010"






r = /

    (?<=A|,)  # match the beginning of the string or a comma in a positive lookbehind

    (?:        # begin a non-capture group

      {.*?}    # match an open brace followed by any number of characters,

               # lazily, followed by a closed brace

      |        # or

      .*?      # match any number of characters, lazily 

    )          # close non-capture group

    (?=,|z)   # match a comma or the end of the string in a positive lookahead

    /x         # free-spacing regex definition mode



str.scan r

  #=> ["65101km", "Sedan", "Manual", "18131A", "FWD", "Used", "5.5L/100km", "Toyota",

  #    "camry", "SE", "{AC,Heated Seats, Heated Mirrors, Keyless Entry}", "2010"]


Two notes follow. I'll illustrate these with a simpler string.



str = "65101km,Sedan,{AC,Heated Seats},2010"


{.*?} must precede .*? in (?:{.*?}|.*?)



If



r = /(?<=A|,)(?:.*?|{.*?})(?=,|z)/


then



str.scan r

  #=> ["65101km", "Sedan", "{AC", "Heated Seats}", "2010"]


The matches .* must be lazy (aka non-greedy)



If



r = /(?<=A|,)(?:{.*?}|.*)(?=,|z)/


then



str.scan r

  #=> ["65101km,Sedan,{AC,Heated Seats},2010"]


If



r = /(?<=A|,)(?:{.*}|.*?)(?=,|z)/


then



"65101km,Sedan,{AC,Heated Seats},2010,{starter motor, pneumatic tires}".scan r

  #=> ["65101km", "Sedan", "{AC,Heated Seats},2010,{starter motor, pneumatic tires}"]






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 16 '18 at 17:50

























answered Nov 16 '18 at 15:55









Cary SwovelandCary Swoveland

71.2k54167




71.2k54167













  • Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

    – Andres V.
    Nov 16 '18 at 16:03






  • 1





    What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

    – Cary Swoveland
    Nov 16 '18 at 16:21






  • 1





    At Regex101, 2010 is matched.

    – Wiktor Stribiżew
    Nov 16 '18 at 16:53











  • just tried it out its perfect! Thanks guys. I had put a space like Gary said.

    – Andres V.
    Nov 17 '18 at 17:37



















  • Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

    – Andres V.
    Nov 16 '18 at 16:03






  • 1





    What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

    – Cary Swoveland
    Nov 16 '18 at 16:21






  • 1





    At Regex101, 2010 is matched.

    – Wiktor Stribiżew
    Nov 16 '18 at 16:53











  • just tried it out its perfect! Thanks guys. I had put a space like Gary said.

    – Andres V.
    Nov 17 '18 at 17:37

















Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

– Andres V.
Nov 16 '18 at 16:03





Hey Cary, for some reason when I put this on regex101, it doesn't read the 2010 at the end. I thank you for the answer !

– Andres V.
Nov 16 '18 at 16:03




1




1





What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

– Cary Swoveland
Nov 16 '18 at 16:21





What can I say? Ruby matches "2010". Did you perchance test with a string that contains a space between the last comma and "2010"?

– Cary Swoveland
Nov 16 '18 at 16:21




1




1





At Regex101, 2010 is matched.

– Wiktor Stribiżew
Nov 16 '18 at 16:53





At Regex101, 2010 is matched.

– Wiktor Stribiżew
Nov 16 '18 at 16:53













just tried it out its perfect! Thanks guys. I had put a space like Gary said.

– Andres V.
Nov 17 '18 at 17:37





just tried it out its perfect! Thanks guys. I had put a space like Gary said.

– Andres V.
Nov 17 '18 at 17:37


















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