(Gnu) sed command to change a matching part of a line
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
Is there a way in (Gnu) sed to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed. But I'm curious if somebody find a way to solve the problem.
sed
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
add a comment |
Is there a way in (Gnu) sed to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed. But I'm curious if somebody find a way to solve the problem.
sed
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
add a comment |
Is there a way in (Gnu) sed to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed. But I'm curious if somebody find a way to solve the problem.
sed
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
Is there a way in (Gnu) sed to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed. But I'm curious if somebody find a way to solve the problem.
sed
sed
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
asked Nov 16 '18 at 15:13
bmkbmk
11.4k43036
11.4k43036
add a comment |
add a comment |
1 Answer
1
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oldest
votes
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#1!
s!(XXX[^ ]*)/!1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&n/g'
| sed -e '/XXX/y,/,#,'
| sed -e ':a;/ $/{N;s/n//;ba}'
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
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active
oldest
votes
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#1!
s!(XXX[^ ]*)/!1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&n/g'
| sed -e '/XXX/y,/,#,'
| sed -e ':a;/ $/{N;s/n//;ba}'
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
add a comment |
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#1!
s!(XXX[^ ]*)/!1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&n/g'
| sed -e '/XXX/y,/,#,'
| sed -e ':a;/ $/{N;s/n//;ba}'
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
add a comment |
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#1!
s!(XXX[^ ]*)/!1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&n/g'
| sed -e '/XXX/y,/,#,'
| sed -e ':a;/ $/{N;s/n//;ba}'
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#1!
s!(XXX[^ ]*)/!1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&n/g'
| sed -e '/XXX/y,/,#,'
| sed -e ':a;/ $/{N;s/n//;ba}'
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
edited Nov 16 '18 at 15:59
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
answered Nov 16 '18 at 15:48
Toby SpeightToby Speight
17.5k134469
17.5k134469
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
add a comment |
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
These are interesting solutions that work for me that way. Thank you.
– bmk
Nov 19 '18 at 9:36
add a comment |
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