Regular Expression bigquery
How do I extract from an email string only the following part:
john.smith@mytest.ux.ca
al.pacino@mytext.ca
Desired result:
ux.ca
ca
Basically, everything that comes later than @ AND the first 'dot'
google-bigquery
add a comment |
How do I extract from an email string only the following part:
john.smith@mytest.ux.ca
al.pacino@mytext.ca
Desired result:
ux.ca
ca
Basically, everything that comes later than @ AND the first 'dot'
google-bigquery
add a comment |
How do I extract from an email string only the following part:
john.smith@mytest.ux.ca
al.pacino@mytext.ca
Desired result:
ux.ca
ca
Basically, everything that comes later than @ AND the first 'dot'
google-bigquery
How do I extract from an email string only the following part:
john.smith@mytest.ux.ca
al.pacino@mytext.ca
Desired result:
ux.ca
ca
Basically, everything that comes later than @ AND the first 'dot'
google-bigquery
google-bigquery
edited Nov 14 '18 at 22:08
Wiktor Stribiżew
317k16138220
317k16138220
asked Nov 14 '18 at 17:12
AlexAlex
3931418
3931418
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add a comment |
1 Answer
1
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oldest
votes
everything that comes later than @ AND the first 'dot'
You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
for example
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'john.smith@mytest.ux.ca' email UNION ALL
SELECT 'al.pacino@mytext.ca'
)
SELECT
email,
REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
FROM `project.dataset.table`
with result
Row email f0_
1 john.smith@mytest.ux.ca ux.ca
2 al.pacino@mytext.ca ca
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
everything that comes later than @ AND the first 'dot'
You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
for example
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'john.smith@mytest.ux.ca' email UNION ALL
SELECT 'al.pacino@mytext.ca'
)
SELECT
email,
REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
FROM `project.dataset.table`
with result
Row email f0_
1 john.smith@mytest.ux.ca ux.ca
2 al.pacino@mytext.ca ca
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
add a comment |
everything that comes later than @ AND the first 'dot'
You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
for example
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'john.smith@mytest.ux.ca' email UNION ALL
SELECT 'al.pacino@mytext.ca'
)
SELECT
email,
REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
FROM `project.dataset.table`
with result
Row email f0_
1 john.smith@mytest.ux.ca ux.ca
2 al.pacino@mytext.ca ca
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
add a comment |
everything that comes later than @ AND the first 'dot'
You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
for example
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'john.smith@mytest.ux.ca' email UNION ALL
SELECT 'al.pacino@mytext.ca'
)
SELECT
email,
REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
FROM `project.dataset.table`
with result
Row email f0_
1 john.smith@mytest.ux.ca ux.ca
2 al.pacino@mytext.ca ca
everything that comes later than @ AND the first 'dot'
You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
for example
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'john.smith@mytest.ux.ca' email UNION ALL
SELECT 'al.pacino@mytext.ca'
)
SELECT
email,
REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
FROM `project.dataset.table`
with result
Row email f0_
1 john.smith@mytest.ux.ca ux.ca
2 al.pacino@mytext.ca ca
answered Nov 14 '18 at 17:21
Mikhail BerlyantMikhail Berlyant
59.6k43671
59.6k43671
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
add a comment |
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
Exactly what I was looking for. Thanks!!
– Alex
Nov 14 '18 at 17:35
add a comment |
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