Regular Expression bigquery












0















How do I extract from an email string only the following part:



john.smith@mytest.ux.ca

al.pacino@mytext.ca



Desired result:



ux.ca
ca


Basically, everything that comes later than @ AND the first 'dot'










share|improve this question





























    0















    How do I extract from an email string only the following part:



    john.smith@mytest.ux.ca

    al.pacino@mytext.ca



    Desired result:



    ux.ca
    ca


    Basically, everything that comes later than @ AND the first 'dot'










    share|improve this question



























      0












      0








      0








      How do I extract from an email string only the following part:



      john.smith@mytest.ux.ca

      al.pacino@mytext.ca



      Desired result:



      ux.ca
      ca


      Basically, everything that comes later than @ AND the first 'dot'










      share|improve this question
















      How do I extract from an email string only the following part:



      john.smith@mytest.ux.ca

      al.pacino@mytext.ca



      Desired result:



      ux.ca
      ca


      Basically, everything that comes later than @ AND the first 'dot'







      google-bigquery






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 22:08









      Wiktor Stribiżew

      317k16138220




      317k16138220










      asked Nov 14 '18 at 17:12









      AlexAlex

      3931418




      3931418
























          1 Answer
          1






          active

          oldest

          votes


















          2















          everything that comes later than @ AND the first 'dot'




          You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')



          for example



          #standardSQL
          WITH `project.dataset.table` AS (
          SELECT 'john.smith@mytest.ux.ca' email UNION ALL
          SELECT 'al.pacino@mytext.ca'
          )
          SELECT
          email,
          REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
          FROM `project.dataset.table`


          with result



          Row email                   f0_  
          1 john.smith@mytest.ux.ca ux.ca
          2 al.pacino@mytext.ca ca





          share|improve this answer
























          • Exactly what I was looking for. Thanks!!

            – Alex
            Nov 14 '18 at 17:35











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2















          everything that comes later than @ AND the first 'dot'




          You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')



          for example



          #standardSQL
          WITH `project.dataset.table` AS (
          SELECT 'john.smith@mytest.ux.ca' email UNION ALL
          SELECT 'al.pacino@mytext.ca'
          )
          SELECT
          email,
          REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
          FROM `project.dataset.table`


          with result



          Row email                   f0_  
          1 john.smith@mytest.ux.ca ux.ca
          2 al.pacino@mytext.ca ca





          share|improve this answer
























          • Exactly what I was looking for. Thanks!!

            – Alex
            Nov 14 '18 at 17:35
















          2















          everything that comes later than @ AND the first 'dot'




          You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')



          for example



          #standardSQL
          WITH `project.dataset.table` AS (
          SELECT 'john.smith@mytest.ux.ca' email UNION ALL
          SELECT 'al.pacino@mytext.ca'
          )
          SELECT
          email,
          REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
          FROM `project.dataset.table`


          with result



          Row email                   f0_  
          1 john.smith@mytest.ux.ca ux.ca
          2 al.pacino@mytext.ca ca





          share|improve this answer
























          • Exactly what I was looking for. Thanks!!

            – Alex
            Nov 14 '18 at 17:35














          2












          2








          2








          everything that comes later than @ AND the first 'dot'




          You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')



          for example



          #standardSQL
          WITH `project.dataset.table` AS (
          SELECT 'john.smith@mytest.ux.ca' email UNION ALL
          SELECT 'al.pacino@mytext.ca'
          )
          SELECT
          email,
          REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
          FROM `project.dataset.table`


          with result



          Row email                   f0_  
          1 john.smith@mytest.ux.ca ux.ca
          2 al.pacino@mytext.ca ca





          share|improve this answer














          everything that comes later than @ AND the first 'dot'




          You can use REGEXP_EXTRACT(email, r'@[^.]+.(.*)')



          for example



          #standardSQL
          WITH `project.dataset.table` AS (
          SELECT 'john.smith@mytest.ux.ca' email UNION ALL
          SELECT 'al.pacino@mytext.ca'
          )
          SELECT
          email,
          REGEXP_EXTRACT(email, r'@[^.]+.(.*)')
          FROM `project.dataset.table`


          with result



          Row email                   f0_  
          1 john.smith@mytest.ux.ca ux.ca
          2 al.pacino@mytext.ca ca






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 17:21









          Mikhail BerlyantMikhail Berlyant

          59.6k43671




          59.6k43671













          • Exactly what I was looking for. Thanks!!

            – Alex
            Nov 14 '18 at 17:35



















          • Exactly what I was looking for. Thanks!!

            – Alex
            Nov 14 '18 at 17:35

















          Exactly what I was looking for. Thanks!!

          – Alex
          Nov 14 '18 at 17:35





          Exactly what I was looking for. Thanks!!

          – Alex
          Nov 14 '18 at 17:35




















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