How to print x numbers with rand()%












-2














How can I print let's say 10 numbers using rand() then sort them by biggest?



#include <iostream>
using namespace std;

int main() {
int b;
cin >> b;
srand(b);

for (int i = 0; i < 10; i++){
cout << rand() % 100000 << " ";
}
}









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  • 3




    Store them in a vector and sort the vector.
    – FrankS101
    Nov 12 '18 at 17:18






  • 1




    You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
    – Mike Harris
    Nov 12 '18 at 17:26










  • @MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
    – Arne Vogel
    Nov 13 '18 at 18:40


















-2














How can I print let's say 10 numbers using rand() then sort them by biggest?



#include <iostream>
using namespace std;

int main() {
int b;
cin >> b;
srand(b);

for (int i = 0; i < 10; i++){
cout << rand() % 100000 << " ";
}
}









share|improve this question


















  • 3




    Store them in a vector and sort the vector.
    – FrankS101
    Nov 12 '18 at 17:18






  • 1




    You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
    – Mike Harris
    Nov 12 '18 at 17:26










  • @MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
    – Arne Vogel
    Nov 13 '18 at 18:40
















-2












-2








-2







How can I print let's say 10 numbers using rand() then sort them by biggest?



#include <iostream>
using namespace std;

int main() {
int b;
cin >> b;
srand(b);

for (int i = 0; i < 10; i++){
cout << rand() % 100000 << " ";
}
}









share|improve this question













How can I print let's say 10 numbers using rand() then sort them by biggest?



#include <iostream>
using namespace std;

int main() {
int b;
cin >> b;
srand(b);

for (int i = 0; i < 10; i++){
cout << rand() % 100000 << " ";
}
}






c++ c++11 c++14






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 '18 at 17:16









Gosho

64




64








  • 3




    Store them in a vector and sort the vector.
    – FrankS101
    Nov 12 '18 at 17:18






  • 1




    You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
    – Mike Harris
    Nov 12 '18 at 17:26










  • @MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
    – Arne Vogel
    Nov 13 '18 at 18:40
















  • 3




    Store them in a vector and sort the vector.
    – FrankS101
    Nov 12 '18 at 17:18






  • 1




    You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
    – Mike Harris
    Nov 12 '18 at 17:26










  • @MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
    – Arne Vogel
    Nov 13 '18 at 18:40










3




3




Store them in a vector and sort the vector.
– FrankS101
Nov 12 '18 at 17:18




Store them in a vector and sort the vector.
– FrankS101
Nov 12 '18 at 17:18




1




1




You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
– Mike Harris
Nov 12 '18 at 17:26




You could insert into a sorted structure (e.g., std::multiset) rather than sorting it after the fact. It's likely that this will be faster.
– Mike Harris
Nov 12 '18 at 17:26












@MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
– Arne Vogel
Nov 13 '18 at 18:40






@MikeHarris Actually, that's probably much slower on any common hardware… Even a (mostly unsuccessful) std::find() over an unsorted std::vector<int> consistently beats a std::set<int>::find() on my Ivy Bridge work laptop for N<=120. And, in your example, there isn't an asymptotic time advantage, so chances are the std::vector+std::sort will always win no matter how you choose N. "Processors love vectors – they send them flowers…" (Herb Sutter)
– Arne Vogel
Nov 13 '18 at 18:40














1 Answer
1






active

oldest

votes


















1














You can generate an array, print it, and then sort it (and reprint it?).



Note: if true randomness is an issue for you, rand() + % is not suited.



#include <array>
#include <algorithm>
#include <iostream>

int main()
{
std::array<int, 10> data;
std::generate(begin(data), end(data), rand);
for (auto n : data) {
std::cout << n << ", ";
}
std::cout << 'n';

std::sort(begin(data), end(data));
for (auto n : data) {
std::cout << n << ", ";
}
std::cout << 'n';
}


demo: http://coliru.stacked-crooked.com/a/2e62855189995ab0



Following: how could I define an operator to be able to write std::cout << data whatever the type of data is?.






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You can generate an array, print it, and then sort it (and reprint it?).



    Note: if true randomness is an issue for you, rand() + % is not suited.



    #include <array>
    #include <algorithm>
    #include <iostream>

    int main()
    {
    std::array<int, 10> data;
    std::generate(begin(data), end(data), rand);
    for (auto n : data) {
    std::cout << n << ", ";
    }
    std::cout << 'n';

    std::sort(begin(data), end(data));
    for (auto n : data) {
    std::cout << n << ", ";
    }
    std::cout << 'n';
    }


    demo: http://coliru.stacked-crooked.com/a/2e62855189995ab0



    Following: how could I define an operator to be able to write std::cout << data whatever the type of data is?.






    share|improve this answer




























      1














      You can generate an array, print it, and then sort it (and reprint it?).



      Note: if true randomness is an issue for you, rand() + % is not suited.



      #include <array>
      #include <algorithm>
      #include <iostream>

      int main()
      {
      std::array<int, 10> data;
      std::generate(begin(data), end(data), rand);
      for (auto n : data) {
      std::cout << n << ", ";
      }
      std::cout << 'n';

      std::sort(begin(data), end(data));
      for (auto n : data) {
      std::cout << n << ", ";
      }
      std::cout << 'n';
      }


      demo: http://coliru.stacked-crooked.com/a/2e62855189995ab0



      Following: how could I define an operator to be able to write std::cout << data whatever the type of data is?.






      share|improve this answer


























        1












        1








        1






        You can generate an array, print it, and then sort it (and reprint it?).



        Note: if true randomness is an issue for you, rand() + % is not suited.



        #include <array>
        #include <algorithm>
        #include <iostream>

        int main()
        {
        std::array<int, 10> data;
        std::generate(begin(data), end(data), rand);
        for (auto n : data) {
        std::cout << n << ", ";
        }
        std::cout << 'n';

        std::sort(begin(data), end(data));
        for (auto n : data) {
        std::cout << n << ", ";
        }
        std::cout << 'n';
        }


        demo: http://coliru.stacked-crooked.com/a/2e62855189995ab0



        Following: how could I define an operator to be able to write std::cout << data whatever the type of data is?.






        share|improve this answer














        You can generate an array, print it, and then sort it (and reprint it?).



        Note: if true randomness is an issue for you, rand() + % is not suited.



        #include <array>
        #include <algorithm>
        #include <iostream>

        int main()
        {
        std::array<int, 10> data;
        std::generate(begin(data), end(data), rand);
        for (auto n : data) {
        std::cout << n << ", ";
        }
        std::cout << 'n';

        std::sort(begin(data), end(data));
        for (auto n : data) {
        std::cout << n << ", ";
        }
        std::cout << 'n';
        }


        demo: http://coliru.stacked-crooked.com/a/2e62855189995ab0



        Following: how could I define an operator to be able to write std::cout << data whatever the type of data is?.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 13 '18 at 14:48

























        answered Nov 12 '18 at 17:23









        YSC

        20.8k34594




        20.8k34594






























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