Ndtyjky

I have list of integers. In that list there are two dictionaries like so:

value_list = [1180, 1190, 1190, {'low': 1180}, 1130, 1130, 1180, {'low':1160}, 1130]

The output I am trying to get is the sum of the values in between the two dictionaries, as well as the values of the dictionaries. For example:

for item in value_list:

     # if item in list is a dict, sum its value

     # with value of next dict and values in between

In this case the output would be 5780

One method I thought of is finding the index number of the two dicts and using them like this:

value_list[3]['low'] + sum(value_list[4:7]) + value_list[7]['low']

But that seems way too convoluted

You could use the following code, assuming the only types you have are int and dict, and the dict will always have the same format:

total_sum = 0

dicts_num = 0 #flag for checking how many dicts have appeared  

for value in value_list:

    if isinstance(value, dict):

        dicts_num += 1

        total_sum += value["low"]

    elif (dicts_num == 1):

        total_sum += value

if you have the indices (indexes?) of the dict objects, you can use them in a list comprehension:

sum([x if type(x)==int else x['low'] for x in value_list[3:8]])


You can use a loop with a flag variable

found_dict = False

total = 0

for i in value_list:

    if found_dict:

        if type(i) is dict:

            total += i['low']

            break

        else:

            total += i

    elif type(i) is dict:

        total += i['low']

        found_dict = True

Quick and lazy solution, although I'm sure I'll catch some flak for not catching and handling exceptions properly

fl = 0

s = 0

for i in value_list:

    if fl == 0:

        if type(i) == dict:

             s += i['low']

             fl = 1

             continue

    if fl == 1:

        try:

            s += i

        except:

            s += i['low']

            fl = 0

You can extract the indices of the dicts and use a function to extract value if needed

def int_or_value(item, key='low'):

    if isinstance(item, int):

        return item

    else:

        return item[key]



value_list = [1180, 1190, 1190, {'low': 1180}, 1130, 1130, 1180, {'low':1160}, 1130]

indices = [index for index, value in enumerate(value_list) if isinstance(value, dict)]



# Use this if you have multiple instances of {dict} ... {dict} to sum in you value_list

for start, stop in (indices[n:n+2] for n in range(0, len(indices), 2)):

    print(sum(int_or_value(item) for item in value_list[start:stop+1]))



# If you are sure there is going to be a single instance of {dict} ... {dict} to sum just access indices directly

print(sum(int_or_value(item) fro item in value_list[indices[0]:indices[1]+1]))

Assuming there are only numeric values between the first and last dicts in the value_list:

value_list = [1180, 1190, 1190, {'low': 1180}, 1130, 1130, 1180, {'low':1160}, 1130]

dicts = [(i, list(d.values())[0]) for i, d in enumerate(value_list) if isinstance(d, dict)]

sum(value_list[dicts[0][0] + 1 : dicts[-1][0]]) + sum(t[-1] for t in dicts)

# Outputs: 5780

If the assumption is not correct this needs to be more complex.