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In mathematics, a Mersenne prime is a prime number that is one less than a power of two. That is, it is a prime number of the form M_n = 2ⁿ − 1 for some integer n. They are named after Marin Mersenne, a French Minim friar, who studied them in the early 17th century.

The exponents n which give Mersenne primes are 2, 3, 5, 7, 13, 17, 19, 31, ... (sequence A000043 in the OEIS) and the resulting Mersenne primes are 3, 7, 31, 127, 8191, 131071, 524287, 2147483647, ... (sequence A000668 in the OEIS).

If n is a composite number then so is 2ⁿ − 1. (2^ab − 1 is divisible by both 2^a − 1 and 2^b − 1.) This definition is therefore equivalent to a definition as a prime number of the form M_p = 2^p − 1 for some prime p.

More generally, numbers of the form M_n = 2ⁿ − 1 without the primality requirement may be called Mersenne numbers. Sometimes, however, Mersenne numbers are defined to have the additional requirement that n be prime.
The smallest composite Mersenne number with prime exponent n is 2¹¹ − 1 = 2047 = 23 × 89.

Mersenne primes M_p are also noteworthy due to their connection to perfect numbers.

A new Mersenne prime was found in December 2017. As of January 2018^[ref], 50 are now known. The largest known prime number 2^77,232,917 − 1 is a Mersenne prime.^[2] Since 1997, all newly found Mersenne primes have been discovered by the Great Internet Mersenne Prime Search (GIMPS), a distributed computing project on the Internet.

About Mersenne primes

Unsolved problem in mathematics: Are there infinitely many Mersenne primes? (more unsolved problems in mathematics)

Many fundamental questions about Mersenne primes remain unresolved. It is not even known whether the set of Mersenne primes is finite or infinite. The Lenstra–Pomerance–Wagstaff conjecture asserts that there are infinitely many Mersenne primes and predicts their order of growth. It is also not known whether infinitely many Mersenne numbers with prime exponents are composite, although this would follow from widely believed conjectures about prime numbers, for example, the infinitude of Sophie Germain primes congruent to 3 (mod 4). For these primes p, 2p + 1 (which is also prime) will divide M_p, e.g., 23 | M₁₁, 47 | M₂₃, 167 | M₈₃, 263 | M₁₃₁, 359 | M₁₇₉, 383 | M₁₉₁, 479 | M₂₃₉, and 503 | M₂₅₁ (sequence A002515 in the OEIS). Since for these primes p, 2p + 1 is congruent to 7 mod 8, so 2 is a quadratic residue mod 2p + 1, and the multiplicative order of 2 mod 2p + 1 must divide (2p+1)−12{displaystyle {frac {(2p+1)-1}{2}}} = p. Since p is a prime, it must be p or 1. However, it cannot be 1 since Φ1(2)=1{displaystyle Phi _{1}(2)=1} and 1 has no prime factors, so it must be p. Hence, 2p + 1 divides Φp(2)=2p−1{displaystyle Phi _{p}(2)=2^{p}-1} and 2^p − 1 = M_p cannot be prime.

The first four Mersenne primes are M₂ = 3, M₃ = 7, M₅ = 31 and M₇ = 127 and because the first Mersenne prime starts at M₂, all Mersenne primes are congruent to 3 (mod 4). Other than M₀ = 0 and M₁ = 1, all other Mersenne numbers are also congruent to 3 (mod 4). Consequently, in the prime factorization of a Mersenne number ( ≥ M₂ ) there must be at least one prime factor congruent to 3 (mod 4).

A basic theorem about Mersenne numbers states that if M_p is prime, then the exponent p must also be prime. This follows from the identity

2ab−1=(2a−1)⋅(1+2a+22a+23a+⋯+2(b−1)a)=(2b−1)⋅(1+2b+22b+23b+⋯+2(a−1)b).{displaystyle {begin{aligned}2^{ab}-1&=(2^{a}-1)cdot left(1+2^{a}+2^{2a}+2^{3a}+cdots +2^{(b-1)a}right)\&=(2^{b}-1)cdot left(1+2^{b}+2^{2b}+2^{3b}+cdots +2^{(a-1)b}right).end{aligned}}}

This rules out primality for Mersenne numbers with composite exponent, such as M₄ = 2⁴ − 1 = 15 = 3 × 5 = (2² − 1) × (1 + 2²).

Though the above examples might suggest that M_p is prime for all primes p, this is not the case, and the smallest counterexample is the Mersenne number

M₁₁ = 2¹¹ − 1 = 2047 = 23 × 89.

The evidence at hand suggests that a randomly selected Mersenne number is much more likely to be prime than an arbitrary randomly selected odd integer of similar size.^{[citation needed]} Nonetheless, prime values of M_p appear to grow increasingly sparse as p increases. For example, eight of the first 11 primes p give rise to a Mersenne prime M_p (the correct terms on Mersenne's original list), while M_p is prime for only 43 of the first two million prime numbers (up to 32,452,843).

The lack of any simple test to determine whether a given Mersenne number is prime makes the search for Mersenne primes a difficult task, since Mersenne numbers grow very rapidly. The Lucas–Lehmer primality test (LLT) is an efficient primality test that greatly aids this task, making it much easier to test the primality of Mersenne numbers than that of most other numbers of the same size. The search for the largest known prime has somewhat of a cult following. Consequently, a lot of computer power has been expended searching for new Mersenne primes, much of which is now done using distributed computing.

Mersenne primes are used in pseudorandom number generators such as the Mersenne twister, Park–Miller random number generator, Generalized Shift Register and Fibonacci RNG.

Perfect numbers

Mersenne primes M_p are also noteworthy due to their connection with perfect numbers. In the 4th century BC, Euclid proved that if 2^p − 1 is prime, then 2^{p − 1}(2^p − 1) is a perfect number. This number, also expressible as M_p(M_p + 1)/2, is the M_pth triangular number and the 2^{p − 1}th hexagonal number. In the 18th century, Leonhard Euler proved that, conversely, all even perfect numbers have this form.^[3] This is known as the Euclid–Euler theorem. It is unknown whether there are any odd perfect numbers.

History

Mersenne primes take their name from the 17th-century French scholar Marin Mersenne, who compiled what was supposed to be a list of Mersenne primes with exponents up to 257. The exponents listed by Mersenne were as follows:

2, 3, 5, 7, 13, 17, 19, 31, 67, 127, 257.

His list replicated the known primes of his time with exponents up to 19. His next entry, 31, was correct, but the list then became largely incorrect, as Mersenne mistakenly included M₆₇ and M₂₅₇ (which are composite) and omitted M₆₁, M₈₉, and M₁₀₇ (which are prime). Mersenne gave little indication how he came up with his list.^[4]

Édouard Lucas proved in 1876 that M₁₂₇ is indeed prime, as Mersenne claimed. This was the largest known prime number for 75 years, and the largest ever found by hand. M₆₁ was determined to be prime in 1883 by Ivan Mikheevich Pervushin, though Mersenne claimed it was composite, and for this reason it is sometimes called Pervushin's number. This was the second-largest known prime number, and it remained so until 1911. Lucas had shown another error in Mersenne's list in 1876. Without finding a factor, Lucas demonstrated that M₆₇ is actually composite. No factor was found until a famous talk by Frank Nelson Cole in 1903.^[5] Without speaking a word, he went to a blackboard and raised 2 to the 67th power, then subtracted one. On the other side of the board, he multiplied 193,707,721 × 761,838,257,287 and got the same number, then returned to his seat (to applause) without speaking.^[6] He later said that the result had taken him "three years of Sundays" to find.^[7] A correct list of all Mersenne primes in this number range was completed and rigorously verified only about three centuries after Mersenne published his list.

Searching for Mersenne primes

Fast algorithms for finding Mersenne primes are available, and as of 2018^[update] the seven largest known prime numbers are Mersenne primes.

The first four Mersenne primes M₂ = 3, M₃ = 7, M₅ = 31 and M₇ = 127 were known in antiquity. The fifth, M₁₃ = 8191, was discovered anonymously before 1461; the next two (M₁₇ and M₁₉) were found by Pietro Cataldi in 1588. After nearly two centuries, M₃₁ was verified to be prime by Leonhard Euler in 1772. The next (in historical, not numerical order) was M₁₂₇, found by Édouard Lucas in 1876, then M₆₁ by Ivan Mikheevich Pervushin in 1883. Two more (M₈₉ and M₁₀₇) were found early in the 20th century, by R. E. Powers in 1911 and 1914, respectively.

The best method presently known for testing the primality of Mersenne numbers is the Lucas–Lehmer primality test. Specifically, it can be shown that for prime p > 2, M_p = 2^p − 1 is prime if and only if M_p divides S_{p − 2}, where S₀ = 4 and S_k = (S_{k − 1})² − 2 for k > 0.

During the era of manual calculation, all the exponents up to and including 257 were tested with the Lucas–Lehmer test and found to be composite. A notable contribution was made by retired Yale physics professor Horace Scudder Uhler, who did the calculations for exponents 157, 167, 193, 199, 227, and 229.^[8] Unfortunately for those investigators, the interval they were testing contains the largest known gap between Mersenne primes, in relative terms: the next Mersenne prime exponent, 521, would turn out to be more than four times larger than the previous record of 127.

Graph of number of digits in largest known Mersenne prime by year – electronic era. Note that the vertical scale, the number of digits, is doubly logarithmic in the value of the prime.

The search for Mersenne primes was revolutionized by the introduction of the electronic digital computer. Alan Turing searched for them on the Manchester Mark 1 in 1949,^[9] but the first successful identification of a Mersenne prime, M₅₂₁, by this means was achieved at 10:00 pm on January 30, 1952 using the U.S. National Bureau of Standards Western Automatic Computer (SWAC) at the Institute for Numerical Analysis at the University of California, Los Angeles, under the direction of Lehmer, with a computer search program written and run by Prof. R. M. Robinson. It was the first Mersenne prime to be identified in thirty-eight years; the next one, M₆₀₇, was found by the computer a little less than two hours later. Three more — M₁₂₇₉, M₂₂₀₃, M₂₂₈₁ — were found by the same program in the next several months. M₄₂₅₃ is the first Mersenne prime that is titanic, M_44,497 is the first gigantic, and M_6,972,593 was the first megaprime to be discovered, being a prime with at least 1,000,000 digits.^[10] All three were the first known prime of any kind of that size. The number of digits in the decimal representation of M_n equals ⌊n × log₁₀2⌋ + 1, where ⌊x⌋ denotes the floor function (or equivalently ⌊log₁₀M_n⌋ + 1).

In September 2008, mathematicians at UCLA participating in GIMPS won part of a $100,000 prize from the Electronic Frontier Foundation for their discovery of a very nearly 13-million-digit Mersenne prime. The prize, finally confirmed in October 2009, is for the first known prime with at least 10 million digits. The prime was found on a Dell OptiPlex 745 on August 23, 2008. This was the eighth Mersenne prime discovered at UCLA.^[11]

On April 12, 2009, a GIMPS server log reported that a 47th Mersenne prime had possibly been found. The find was verified on June 12, 2009. The prime is 2^42,643,801 − 1. Although it is chronologically the 47th Mersenne prime to be discovered, it is smaller than the largest known at the time, which was the 45th to be discovered.

On January 25, 2013, Curtis Cooper, a mathematician at the University of Central Missouri, discovered a 48th Mersenne prime, 2^57,885,161 − 1 (a number with 17,425,170 digits), as a result of a search executed by a GIMPS server network.^[12]

On January 19, 2016, Cooper published his discovery of a 49th Mersenne prime, 2^74,207,281 − 1 (a number with 22,338,618 digits), as a result of a search executed by a GIMPS server network.^[13][14][15] This was the fourth Mersenne prime discovered by Cooper and his team in the past ten years.

On January 3, 2018, it was announced that Jonathan Pace, a 51-year-old electrical engineer living in Germantown, Tennessee, had found a 50th Mersenne prime, 2^77,232,917 − 1 (a number with 23,249,425 digits), as a result of a search executed by a GIMPS server network.^[16]

Theorems about Mersenne numbers

1. If a and p are natural numbers such that a^p − 1 is prime, then a = 2 or p = 1.
   
   • 
     Proof: a ≡ 1 (mod a − 1). Then a^p ≡ 1 (mod a − 1), so a^p − 1 ≡ 0 (mod a − 1). Thus a − 1 | a^p − 1. However, a^p − 1 is prime, so a − 1 = a^p − 1 or a − 1 = ±1. In the former case, a = a^p, hence a = 0,1 (which is a contradiction, as neither −1 nor 0 is prime) or p = 1. In the latter case, a = 2 or a = 0. If a = 0, however, 0^p − 1 = 0 − 1 = −1 which is not prime. Therefore, a = 2.
   
   


2. If 2^p − 1 is prime, then p is prime.
   
   • 
     Proof: suppose that p is composite, hence can be written p = ab with a and b > 1. Then 2^p − 1 = 2^ab − 1 = (2^a)^b − 1 = (2^a − 1)((2^a)^{b − 1} + (2^a)^{b − 2} + … + 2^a + 1) so 2^p − 1 is composite. By contrapositive, if 2^p − 1 is prime then p is prime.
   
   


3. If p is an odd prime, then every prime q that divides 2^p − 1 must be 1 plus a multiple of 2p. This holds even when 2^p − 1 is prime.
   
   
   
   • For example, 2⁵ − 1 = 31 is prime, and 31 = 1 + 3 × (2 × 5). A composite example is 2¹¹ − 1 = 23 × 89, where 23 = 1 + (2 × 11) and 89 = 1 + 4 × (2 × 11).
   
   
   • 
     Proof: By Fermat's little theorem, q is a factor of 2^{q − 1} − 1. Since q is a factor of 2^p − 1, for all positive integers c, q is also a factor of 2^pc − 1. Since p is prime and q is not a factor of 2¹ − 1, p is also the smallest positive integer x such that q is a factor of 2^x − 1. As a result, for all positive integers x, q is a factor of 2^x − 1 if and only if p is a factor of x. Therefore, since q is a factor of 2^{q − 1} − 1, p is a factor of q − 1 so q ≡ 1 (mod p). Furthermore, since q is a factor of 2^p − 1, which is odd, q is odd. Therefore, q ≡ 1 (mod 2p).
   
   
   • This fact leads to a proof of Euclid's theorem, which asserts the infinitude of primes, distinct from the proof written by Euclid: for every odd prime p, all primes dividing 2^p − 1 are larger than p; thus there are always larger primes than any particular prime.
   
   
   • This fact also implies that for every prime p > 2, there is at least one prime of the form 2kp+1 less than or equal to M_p, for some integer k.
   
   
   
   


4. If p is an odd prime, then every prime q that divides 2^p − 1 is congruent to ±1 (mod 8).
   
   • 
     Proof: 2^{p + 1} ≡ 2 (mod q), so 2^{1/2(p + 1)} is a square root of 2 mod q. By quadratic reciprocity, every prime modulo in which the number 2 has a square root is congruent to ±1 (mod 8).
   
   


5. A Mersenne prime cannot be a Wieferich prime.
   
   • 
     Proof: We show if p = 2^m − 1 is a Mersenne prime, then the congruence 2^{p − 1} ≡ 1 (mod p²) does not hold. By Fermat's little theorem, m | p − 1. Therefore, one can write p − 1 = mλ. If the given congruence is satisfied, then p² | 2^mλ − 1, therefore 0 ≡ 2^mλ − 1/2^m − 1 = 1 + 2^m + 2^2m + ... + 2^{(λ − 1)m} ≡ −λ mod (2^m − 1). Hence 2^m − 1 | λ, and therefore λ ≥ 2^m − 1. This leads to p − 1 ≥ m(2^m − 1), which is impossible since m ≥ 2.
   
   


6. If m and n are natural numbers then m and n are coprime if and only if 2^m − 1 and 2ⁿ − 1 are coprime. Consequently, a prime number divides at most one prime-exponent Mersenne number,^[17] so in other words the set of pernicious Mersenne numbers is pairwise coprime.


7. If p and 2p + 1 are both prime (meaning that p is a Sophie Germain prime), and p is congruent to 3 (mod 4), then 2p + 1 divides 2^p − 1.^[18]
   
   
   • 
     Example: 11 and 23 are both prime, and 11 = 2 × 4 + 3, so 23 divides 2¹¹ − 1.
   
   
   • 
     Proof: Let q be 2p + 1. By Fermat's little theorem, 2^2p ≡ 1 (mod q), so either 2^p ≡ 1 (mod q) or 2^p ≡ −1 (mod q). Supposing latter true, then 2^{p + 1} = (2^{1/2(p + 1)})² ≡ −2 (mod q), so −2 would be a quadratic residue mod q. However, since p is congruent to 3 (mod 4), q is congruent to 7 (mod 8) and therefore 2 is a quadratic residue mod q. Also since q is congruent to 3 (mod 4), −1 is a quadratic nonresidue mod q, so −2 is the product of a residue and a nonresidue and hence it is a nonresidue, which is a contradiction. Hence, the former congruence must be true and 2p + 1 divides M_p.
   
   
   
   


8. All composite divisors of prime-exponent Mersenne numbers are strong pseudoprimes to the base 2.

List of known Mersenne primes

The table below lists all known Mersenne primes (sequence A000043 (p) and A000668 (M_p) in OEIS):

All Mersenne numbers below the 50th Mersenne prime (M_77,232,917) have been tested at least once but some have not been double-checked. Primes are not always discovered in increasing order. For example, the 29th Mersenne prime was discovered after the 30th and the 31st. Similarly, M_43,112,609 was followed by two smaller Mersenne primes, first 2 weeks later and then 8 months later.^[75]M_43,112,609 was the first discovered prime number with more than 10 million decimal digits.

The largest known Mersenne prime (2^77,232,917 − 1) is also the largest known prime number.^[2]

In modern times, the largest known prime has almost always been a Mersenne prime.^[76]

Factorization of composite Mersenne numbers

Since they are prime numbers, Mersenne primes are divisible only by 1 and by themselves. However, not all Mersenne numbers are Mersenne primes, and the composite Mersenne numbers may be factored nontrivially. Mersenne numbers are very good test cases for the special number field sieve algorithm, so often the largest number factorized with this algorithm has been a Mersenne number. As of August 2016^[update], 2^1,193 − 1 is the record-holder,^[77] having been factored with a variant of the special number field sieve that allows the factorization of several numbers at once. See integer factorization records for links to more information. The special number field sieve can factorize numbers with more than one large factor. If a number has only one very large factor then other algorithms can factorize larger numbers by first finding small factors and then making a primality test on the cofactor. As of March 2018^[update], the largest factorization with probable prime factors allowed is 2^7,313,983 − 1 = 305,492,080,276,193 × q, where q is a 2,201,714-digit probable prime. It was discovered by Oliver Kruse.^[78] As of June 2018^[update], the Mersenne number M₁₂₇₇ is the smallest composite Mersenne number with no known factors; it has no prime factors below 2⁶⁷.^[79]

The table below shows factorizations for the first 20 composite Mersenne numbers (sequence A244453 in the OEIS).

The number of factors for the first 500 Mersenne numbers can be found at (sequence A046800 in the OEIS).

Mersenne primitive part

The primitive part of Mersenne number M_n is Φ_n(2), the nth cyclotomic polynomial at 2, they are

1, 3, 7, 5, 31, 3, 127, 17, 73, 11, 2047, 13, 8191, 43, 151, 257, 131071, 57, 524287, 205, 2359, 683, 8388607, 241, 1082401, 2731, 262657, 3277, 536870911, 331, ... (sequence A019320 in the OEIS)

Besides, if we notice those prime factors, and delete "old prime factors", for example, 3 divides the 2nd, 6th, 18th, 54th, 162nd, ... terms of this sequence, we only allow the 2nd term divided by 3, if we do, they are

1, 3, 7, 5, 31, 1, 127, 17, 73, 11, 2047, 13, 8191, 43, 151, 257, 131071, 19, 524287, 41, 337, 683, 8388607, 241, 1082401, 2731, 262657, 3277, 536870911, 331, ... (sequence A064078 in the OEIS)

The numbers n for which Φ_n(2) is prime are

2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 13, 14, 15, 16, 17, 19, 22, 24, 26, 27, 30, 31, 32, 33, 34, 38, 40, 42, 46, 49, 56, 61, 62, 65, 69, 77, 78, 80, 85, 86, 89, 90, 93, 98, 107, 120, 122, 126, 127, 129, 133, 145, 150, ... (sequence A072226 in the OEIS)

The numbers n for which 2ⁿ − 1 has an only primitive prime factor are

2, 3, 4, 5, 7, 8, 9, 10, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 26, 27, 30, 31, 32, 33, 34, 38, 40, 42, 46, 49, 54, 56, 61, 62, 65, 69, 77, 78, 80, 85, 86, 89, 90, 93, 98, 107, 120, 122, 126, 127, 129, 133, 145, 147, 150, ... (sequence A161508 in the OEIS) (Differ from last sequence, this sequence does not have the term 6, but has the terms 18, 20, 21, 54, 147, 342, 602, and 889, and it is conjectured that no others)

Mersenne numbers in nature and elsewhere

In the mathematical problem Tower of Hanoi, solving a puzzle with an n-disc tower requires M_n steps, assuming no mistakes are made.^[80] The number of rice grains on the whole chessboard in the wheat and chessboard problem is M₆₄.

The asteroid with minor planet number 8191 is named 8191 Mersenne after Marin Mersenne, because 8191 is a Mersenne prime (3 Juno, 7 Iris, 31 Euphrosyne and 127 Johanna having been discovered and named during the 19th century).^[81]

In geometry, an integer right triangle that is primitive and has its even leg a power of 2 ( ≥ 4 ) generates a unique right triangle such that its inradius is always a Mersenne number. For example if the even leg is 2^n + 1 then because it is primitive it constrains the odd leg to be 4ⁿ − 1, the hypotenuse to be 4ⁿ + 1 and its inradius to be 2ⁿ − 1.^[82]

Mersenne–Fermat primes

A Mersenne–Fermat number is defined as 2^pr − 1/2^{pr − 1} − 1, with p prime, r natural number, and can be written as MF(p, r), when r = 1, it is a Mersenne number, and when p = 2, it is a Fermat number, the only known Mersenne–Fermat prime with r > 1 are

MF(2, 2), MF(3, 2), MF(7, 2), MF(59, 2), MF(2, 3), MF(3, 3), MF(2, 4), and MF(2, 5).^[83]

In fact, MF(p, r) = Φ_p^r(2), where Φ is the cyclotomic polynomial.

Generalizations

The simplest generalized Mersenne primes are prime numbers of the form f(2ⁿ), where f(x) is a low-degree polynomial with small integer coefficients.^[84] An example is 2⁶⁴ − 2³² + 1, in this case, n = 32, and f(x) = x² − x + 1; another example is 2¹⁹² − 2⁶⁴ − 1, in this case, n = 64, and f(x) = x³ − x − 1.

It is also natural to try to generalize primes of the form 2ⁿ − 1 to primes of the form bⁿ − 1 (for b ≠ 2 and n > 1). However (see also theorems above), bⁿ − 1 is always divisible by b − 1, so unless the latter is a unit, the former is not a prime. There are two ways to deal with that:

Complex numbers

In the ring of integers (on real numbers), if b − 1 is a unit, then b is either 2 or 0. But 2ⁿ − 1 are the usual Mersenne primes, and the formula 0ⁿ − 1 does not lead to anything interesting (since it is always −1 for all n > 0). Thus, we can regard a ring of "integers" on complex numbers instead of real numbers, like Gaussian integers and Eisenstein integers.

Gaussian Mersenne primes

If we regard the ring of Gaussian integers, we get the case b = 1 + i and b = 1 − i, and can ask (WLOG) for what n the number (1 + i)ⁿ − 1 is a Gaussian prime which will then be called a Gaussian Mersenne prime.^[85]

(1 + i)ⁿ − 1 is a Gaussian prime for the following n:

2, 3, 5, 7, 11, 19, 29, 47, 73, 79, 113, 151, 157, 163, 167, 239, 241, 283, 353, 367, 379, 457, 997, 1367, 3041, 10141, 14699, 27529, 49207, 77291, 85237, 106693, 160423, 203789, 364289, 991961, 1203793, 1667321, 3704053, 4792057, ... (sequence A057429 in the OEIS)

This sequence is in many ways similar to the list of exponents of ordinary Mersenne primes.

The norms (i.e. squares of absolute values) of these Gaussian primes are rational primes:

5, 13, 41, 113, 2113, 525313, 536903681, 140737471578113, ... (sequence A182300 in the OEIS).

Eisenstein Mersenne primes

We can also regard the ring of Eisenstein integers, we get the case b = 1 + ω and b = 1 − ω, and can ask for what n the number (1 + ω)ⁿ − 1 is an Eisenstein prime which will then be called a Eisenstein Mersenne prime.

(1 + ω)ⁿ − 1 is an Eisenstein prime for the following n:

2, 5, 7, 11, 17, 19, 79, 163, 193, 239, 317, 353, 659, 709, 1049, 1103, 1759, 2029, 5153, 7541, 9049, 10453, 23743, 255361, 534827, 2237561, ... (sequence A066408 in the OEIS)

The norms (i.e. squares of absolute values) of these Eisenstein primes are rational primes:

7, 271, 2269, 176419, 129159847, 1162320517, ... (sequence A066413 in the OEIS)

Divide an integer

Repunit primes

The other way to deal with the fact that bⁿ − 1 is always divisible by b − 1, it is to simply take out this factor and ask which values of n make

bn−1b−1{displaystyle {frac {b^{n}-1}{b-1}}}

be prime. (The integer b can be either positive or negative.) If for example we take b = 10, we get n values of:

2, 19, 23, 317, 1031, 49081, 86453, 109297, 270343, ... (sequence A004023 in the OEIS),
corresponding to primes 11, 1111111111111111111, 11111111111111111111111, ... (sequence A004022 in the OEIS).

These primes are called repunit primes. Another example is when we take b = −12, we get n values of:

2, 5, 11, 109, 193, 1483, 11353, 21419, 21911, 24071, 106859, 139739, ... (sequence A057178 in the OEIS),
corresponding to primes −11, 19141, 57154490053, ....

It is a conjecture that for every integer b which is not a perfect power, there are infinitely many values of n such that bⁿ − 1/b − 1 is prime. (When b is a perfect power, it can be shown that there is at most one n value such that bⁿ − 1/b − 1 is prime)

Least n such that bⁿ − 1/b − 1 is prime are (starting with b = 2, 0 if no such n exists)

2, 3, 2, 3, 2, 5, 3, 0, 2, 17, 2, 5, 3, 3, 2, 3, 2, 19, 3, 3, 2, 5, 3, 0, 7, 3, 2, 5, 2, 7, 0, 3, 13, 313, 2, 13, 3, 349, 2, 3, 2, 5, 5, 19, 2, 127, 19, 0, 3, 4229, 2, 11, 3, 17, 7, 3, 2, 3, 2, 7, 3, 5, 0, 19, 2, 19, 5, 3, 2, 3, 2, ... (sequence A084740 in the OEIS)

For negative bases b, they are (starting with b = −2, 0 if no such n exists)

3, 2, 2, 5, 2, 3, 2, 3, 5, 5, 2, 3, 2, 3, 3, 7, 2, 17, 2, 3, 3, 11, 2, 3, 11, 0, 3, 7, 2, 109, 2, 5, 3, 11, 31, 5, 2, 3, 53, 17, 2, 5, 2, 103, 7, 5, 2, 7, 1153, 3, 7, 21943, 2, 3, 37, 53, 3, 17, 2, 7, 2, 3, 0, 19, 7, 3, 2, 11, 3, 5, 2, ... (sequence A084742 in the OEIS) (notice this OEIS sequence does not allow n = 2)

Least base b such that b^prime(n) − 1/b − 1 is prime are

2, 2, 2, 2, 5, 2, 2, 2, 10, 6, 2, 61, 14, 15, 5, 24, 19, 2, 46, 3, 11, 22, 41, 2, 12, 22, 3, 2, 12, 86, 2, 7, 13, 11, 5, 29, 56, 30, 44, 60, 304, 5, 74, 118, 33, 156, 46, 183, 72, 606, 602, 223, 115, 37, 52, 104, 41, 6, 338, 217, ... (sequence A066180 in the OEIS)

For negative bases b, they are

3, 2, 2, 2, 2, 2, 2, 2, 2, 7, 2, 16, 61, 2, 6, 10, 6, 2, 5, 46, 18, 2, 49, 16, 70, 2, 5, 6, 12, 92, 2, 48, 89, 30, 16, 147, 19, 19, 2, 16, 11, 289, 2, 12, 52, 2, 66, 9, 22, 5, 489, 69, 137, 16, 36, 96, 76, 117, 26, 3, ... (sequence A103795 in the OEIS)

Other generalized Mersenne primes

Another generalized Mersenne number is

an−bna−b{displaystyle {frac {a^{n}-b^{n}}{a-b}}}

with a, b any coprime integers, a > 1 and −a < b < a. (Since aⁿ − bⁿ is always divisible by a − b, the division is necessary for there to be any chance of finding prime numbers. In fact, this number is the same as the Lucas number U_n(a + b, ab), since a and b are the roots of the quadratic equation x² − (a + b)x + ab = 0, and this number equals 1 when n = 1) We can ask which n makes this number prime. It can be shown that such n must be primes themselves or equal to 4, and n can be 4 if and only if a + b = 1 and a² + b² is prime. (Since a⁴ − b⁴/a − b = (a + b)(a² + b²). Thus, in this case the pair (a, b) must be (x + 1, −x) and x² + (x + 1)² must be prime. That is, x must be in  A027861.) It is a conjecture that for any pair (a, b) such that for every natural number r > 1, a and b are not both perfect rth powers, and −4ab is not a perfect fourth power. there are infinitely many values of n such that aⁿ − bⁿ/a − b is prime. (When a and b are both perfect rth powers for an r > 1 or when −4ab is a perfect fourth power, it can be shown that there are at most two n values with this property, since if so, then aⁿ − bⁿ/a − b can be factored algebraically) However, this has not been proved for any single value of (a, b).

^*Note: if b < 0 and n is even, then the numbers n are not included in the corresponding OEIS sequence.

A conjecture related to the generalized Mersenne primes:^[96][97] (the conjecture predicts where is the next generalized Mersenne prime, if the conjecture is true, then there are infinitely many primes for all such (a,b) pairs)

For any integers a and b which satisfy the conditions:

1. 
   a > 1, −a < b < a.


2. 
   a and b are coprime. (thus, b cannot be 0)


3. For every natural number r > 1, a and b are not both perfect rth powers. (since when a and b are both perfect rth powers, it can be shown that there are at most two n value such that aⁿ − bⁿ/a − b is prime, and these n values are r itself or a root of r, or 2)


4. 
   −4ab is not a perfect fourth power (if so, then the number has aurifeuillean factorization).

has prime numbers of the form

Rp(a,b)=ap−bpa−b{displaystyle R_{p}(a,b)={frac {a^{p}-b^{p}}{a-b}}}

for prime p, the prime numbers will be distributed near the best fit line

Y=G⋅loga⁡(loga⁡(R(a,b)(n)))+C{displaystyle Y=Gcdot log _{a}(log _{a}(R_{(a,b)}(n)))+C}

where

limn→∞G=1eγ=0.561459483566…{displaystyle lim _{nrightarrow infty }G={frac {1}{e^{gamma }}}=0.561459483566ldots }

and there are about

(loge⁡(N)+m⋅loge⁡(2)⋅loge⁡(loge⁡(N))+1N−δ)⋅eγloge⁡(a){displaystyle (log _{e}(N)+mcdot log _{e}(2)cdot log _{e}left(log _{e}(N))+{frac {1}{sqrt {N}}}-delta right)cdot {frac {e^{gamma }}{log _{e}(a)}}}

prime numbers of this form less than N.

• 
  e is the base of the natural logarithm.


• 
  γ is the Euler–Mascheroni constant.


• 
  log_a is the logarithm in base a.


• 
  R_(a,b)(n) is the nth prime number of the form a^p − b^p/a − b for prime p.


• 
  C is a data fit constant which varies with a and b.


• 
  δ is a data fit constant which varies with a and b.


• 
  m is the largest natural number such that a and −b are both 2^{m − 1}th powers.

We also have the following three properties:

1. The number of prime numbers of the form a^p − b^p/a − b (with prime p) less than or equal to n is about e^γ log_a(log_a(n)).


2. The expected number of prime numbers of the form a^p − b^p/a − b with prime p between n and an is about e^γ.


3. The probability that number of the form a^p − b^p/a − b is prime (for prime p) is about e^γ/p log_e(a).

If this conjecture is true, then for all such (a,b) pairs, let q be the nth prime of the form a^p − b^p/a − b, the graph of log_a(log_a(q)) versus n is almost linear. (See ^[96])

When a = b + 1, it is (b + 1)ⁿ − bⁿ, a difference of two consecutive perfect nth powers, and if aⁿ − bⁿ is prime, then a must be b + 1, because it is divisible by a − b.

Least n such that (b + 1)ⁿ − bⁿ is prime are

2, 2, 2, 3, 2, 2, 7, 2, 2, 3, 2, 17, 3, 2, 2, 5, 3, 2, 5, 2, 2, 229, 2, 3, 3, 2, 3, 3, 2, 2, 5, 3, 2, 3, 2, 2, 3, 3, 2, 7, 2, 3, 37, 2, 3, 5, 58543, 2, 3, 2, 2, 3, 2, 2, 3, 2, 5, 3, 4663, 54517, 17, 3, 2, 5, 2, 3, 3, 2, 2, 47, 61, 19, ... (sequence A058013 in the OEIS)

Least b such that (b + 1)^prime(n) − b^prime(n) is prime are

1, 1, 1, 1, 5, 1, 1, 1, 5, 2, 1, 39, 6, 4, 12, 2, 2, 1, 6, 17, 46, 7, 5, 1, 25, 2, 41, 1, 12, 7, 1, 7, 327, 7, 8, 44, 26, 12, 75, 14, 51, 110, 4, 14, 49, 286, 15, 4, 39, 22, 109, 367, 22, 67, 27, 95, 80, 149, 2, 142, 3, 11, ... (sequence A222119 in the OEIS)

See also

References

External links

Look up Mersenne prime in Wiktionary, the free dictionary.

Wikinews has related news: Record size 17.4 million-digit prime found Two largest known prime numbers discovered just two weeks apart, one qualifies for $100k prize Distributed computing discovers largest known prime number CMSU computing team discovers another record size prime

MathWorld links

• Weisstein, Eric W. "Mersenne number". MathWorld.


• Weisstein, Eric W. "Mersenne prime". MathWorld.


• 47th Mersenne Prime Found