Can not use modPow() on int? (Java)
up vote
-2
down vote
favorite
My Code:
public static void verschluesseln(int m) {
if(m < n) {
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
}
Error:
.java:51: error: int cannot be dereferenced
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
^
This did run in another project of mine. This is why I am heavily confused by this error.
java math cryptography mod
asked Nov 11 at 12:30
ilukasschneider
171
add a comment |
up vote
-2
down vote
favorite
My Code:
public static void verschluesseln(int m) {
if(m < n) {
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
}
Error:
.java:51: error: int cannot be dereferenced
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
^
This did run in another project of mine. This is why I am heavily confused by this error.
java math cryptography mod
asked Nov 11 at 12:30
ilukasschneider
171
3
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
1
intis a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.
– Peter Lawrey
Nov 11 at 12:37
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
@JamesKPolk You would still not be able to call it on anintas in the displayed code.
– Maarten Bodewes
Nov 13 at 4:00
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
My Code:
public static void verschluesseln(int m) {
if(m < n) {
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
}
Error:
.java:51: error: int cannot be dereferenced
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
^
This did run in another project of mine. This is why I am heavily confused by this error.
java math cryptography mod
asked Nov 11 at 12:30
ilukasschneider
171
My Code:
public static void verschluesseln(int m) {
if(m < n) {
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
}
Error:
.java:51: error: int cannot be dereferenced
int c = m.modPow((int) n, oeffentlicherSchluessel[0]);
^
This did run in another project of mine. This is why I am heavily confused by this error.
java math cryptography mod
java math cryptography mod
asked Nov 11 at 12:30
ilukasschneider
171
asked Nov 11 at 12:30
ilukasschneider
171
asked Nov 11 at 12:30
ilukasschneider
171
asked Nov 11 at 12:30
ilukasschneider
171
asked Nov 11 at 12:30
ilukasschneider
171
171
3
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
1
intis a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.
– Peter Lawrey
Nov 11 at 12:37
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
@JamesKPolk You would still not be able to call it on anintas in the displayed code.
– Maarten Bodewes
Nov 13 at 4:00
add a comment |
3
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
1
intis a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.
– Peter Lawrey
Nov 11 at 12:37
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
@JamesKPolk You would still not be able to call it on anintas in the displayed code.
– Maarten Bodewes
Nov 13 at 4:00
3
3
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
1
1
int is a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.– Peter Lawrey
Nov 11 at 12:37
int is a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.– Peter Lawrey
Nov 11 at 12:37
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
@JamesKPolk You would still not be able to call it on an
int as in the displayed code.– Maarten Bodewes
Nov 13 at 4:00
@JamesKPolk You would still not be able to call it on an
int as in the displayed code.– Maarten Bodewes
Nov 13 at 4:00
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
modPow is BigInteger method, you can't use it with int. It also receives BigInteger as parameters, not int
BigInteger c = BigInteger.valueOf(m).modPow(BigInteger.valueOf(n), BigInteger.valueOf(oeffentlicherSchluessel[0]));
answered Nov 11 at 12:35
Guy
18.1k62149
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
modPow is BigInteger method, you can't use it with int. It also receives BigInteger as parameters, not int
BigInteger c = BigInteger.valueOf(m).modPow(BigInteger.valueOf(n), BigInteger.valueOf(oeffentlicherSchluessel[0]));
answered Nov 11 at 12:35
Guy
18.1k62149
add a comment |
up vote
1
down vote
modPow is BigInteger method, you can't use it with int. It also receives BigInteger as parameters, not int
BigInteger c = BigInteger.valueOf(m).modPow(BigInteger.valueOf(n), BigInteger.valueOf(oeffentlicherSchluessel[0]));
answered Nov 11 at 12:35
Guy
18.1k62149
add a comment |
up vote
1
down vote
up vote
1
down vote
modPow is BigInteger method, you can't use it with int. It also receives BigInteger as parameters, not int
BigInteger c = BigInteger.valueOf(m).modPow(BigInteger.valueOf(n), BigInteger.valueOf(oeffentlicherSchluessel[0]));
answered Nov 11 at 12:35
Guy
18.1k62149
modPow is BigInteger method, you can't use it with int. It also receives BigInteger as parameters, not int
BigInteger c = BigInteger.valueOf(m).modPow(BigInteger.valueOf(n), BigInteger.valueOf(oeffentlicherSchluessel[0]));
answered Nov 11 at 12:35
Guy
18.1k62149
edited Nov 11 at 12:49
answered Nov 11 at 12:35
Guy
18.1k62149
answered Nov 11 at 12:35
Guy
18.1k62149
answered Nov 11 at 12:35
Guy
18.1k62149
18.1k62149
add a comment |
add a comment |
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3
No, it didn't. You may not call methods on primitive types. modPow() is a method of the BigInteger class. You needs an instance of BigInteger to call it. docs.oracle.com/javase/8/docs/api/java/math/…
– JB Nizet
Nov 11 at 12:31
1
intis a primitive and no primitive has a method in Java. You might have been thinking of another language e.g. C# has this.– Peter Lawrey
Nov 11 at 12:37
Or, perhaps you wrote your own modPow method just for ints in your other program.
– James K Polk
Nov 11 at 22:13
@JamesKPolk You would still not be able to call it on an
intas in the displayed code.– Maarten Bodewes
Nov 13 at 4:00