How to index a subdictionary and creating a nested for loop

up vote
2
down vote

favorite

I have a list of lists just like below:

>> new_pd[:3]

[['PokedexNumber',

  'Name',

  'Type',

  'Total',

  'HP',

  'Attack',

  'Defense',

  'SpecialAttack',

  'SpecialDefense',

  'Speed'],

 [1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],

 [2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]

What I want to create is below:

{1.0: {'Attack': 49.0,

  'Defense': 49.0,

  'HP': 45.0,

  'Name': 'Bulbasaur',

  'PokedexNumber': 1.0,

  'SpecialAttack': 65.0,

  'SpecialDefense': 65.0,

  'Speed': 45.0,

  'Total': 318.0,

  'Type': 'GrassPoison'},

 2.0: {'Attack': 62.0,

  'Defense': 63.0,

  'HP': 60.0,

  'Name': 'Ivysaur',

So from list of lists, I want to have a big nested dictionary.

To create this, I have written the below code in Python:

new_pd_keys = 

for i in range(1, len(new_pd)):

    new_pd_keys.append(new_pd[i][0])

Above, I get all the keys from column 1 and save them to a list called new_pd_keys.

Then use the below code to assign each keys' values:

for i in range(1,len(new_pd)):

    new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4], 

          'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],

          'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3], 

          'Type':new_pd[i][2]} for key in new_pd_keys }

But what I have is the attributes from my last row. You can see the output below, which are all the same.

{1.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

 2.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

Can you suggest a way to perform the indexing in a better way than mine?

asked Nov 11 at 21:52

ykesen

555

if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10

add a comment |

up vote
2
down vote

favorite

I have a list of lists just like below:

>> new_pd[:3]

[['PokedexNumber',

  'Name',

  'Type',

  'Total',

  'HP',

  'Attack',

  'Defense',

  'SpecialAttack',

  'SpecialDefense',

  'Speed'],

 [1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],

 [2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]

What I want to create is below:

{1.0: {'Attack': 49.0,

  'Defense': 49.0,

  'HP': 45.0,

  'Name': 'Bulbasaur',

  'PokedexNumber': 1.0,

  'SpecialAttack': 65.0,

  'SpecialDefense': 65.0,

  'Speed': 45.0,

  'Total': 318.0,

  'Type': 'GrassPoison'},

 2.0: {'Attack': 62.0,

  'Defense': 63.0,

  'HP': 60.0,

  'Name': 'Ivysaur',

So from list of lists, I want to have a big nested dictionary.

To create this, I have written the below code in Python:

new_pd_keys = 

for i in range(1, len(new_pd)):

    new_pd_keys.append(new_pd[i][0])

Above, I get all the keys from column 1 and save them to a list called new_pd_keys.

Then use the below code to assign each keys' values:

for i in range(1,len(new_pd)):

    new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4], 

          'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],

          'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3], 

          'Type':new_pd[i][2]} for key in new_pd_keys }

But what I have is the attributes from my last row. You can see the output below, which are all the same.

{1.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

 2.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

Can you suggest a way to perform the indexing in a better way than mine?

asked Nov 11 at 21:52

ykesen

555

if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10

add a comment |

up vote
2
down vote

favorite

I have a list of lists just like below:

>> new_pd[:3]

[['PokedexNumber',

  'Name',

  'Type',

  'Total',

  'HP',

  'Attack',

  'Defense',

  'SpecialAttack',

  'SpecialDefense',

  'Speed'],

 [1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],

 [2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]

What I want to create is below:

{1.0: {'Attack': 49.0,

  'Defense': 49.0,

  'HP': 45.0,

  'Name': 'Bulbasaur',

  'PokedexNumber': 1.0,

  'SpecialAttack': 65.0,

  'SpecialDefense': 65.0,

  'Speed': 45.0,

  'Total': 318.0,

  'Type': 'GrassPoison'},

 2.0: {'Attack': 62.0,

  'Defense': 63.0,

  'HP': 60.0,

  'Name': 'Ivysaur',

So from list of lists, I want to have a big nested dictionary.

To create this, I have written the below code in Python:

new_pd_keys = 

for i in range(1, len(new_pd)):

    new_pd_keys.append(new_pd[i][0])

Above, I get all the keys from column 1 and save them to a list called new_pd_keys.

Then use the below code to assign each keys' values:

for i in range(1,len(new_pd)):

    new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4], 

          'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],

          'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3], 

          'Type':new_pd[i][2]} for key in new_pd_keys }

But what I have is the attributes from my last row. You can see the output below, which are all the same.

{1.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

 2.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

Can you suggest a way to perform the indexing in a better way than mine?

asked Nov 11 at 21:52

ykesen

555

I have a list of lists just like below:

>> new_pd[:3]

[['PokedexNumber',

  'Name',

  'Type',

  'Total',

  'HP',

  'Attack',

  'Defense',

  'SpecialAttack',

  'SpecialDefense',

  'Speed'],

 [1.0, 'Bulbasaur', 'GrassPoison', 318.0, 45.0, 49.0, 49.0, 65.0, 65.0, 45.0],

 [2.0, 'Ivysaur', 'GrassPoison', 405.0, 60.0, 62.0, 63.0, 80.0, 80.0, 60.0]]

What I want to create is below:

{1.0: {'Attack': 49.0,

  'Defense': 49.0,

  'HP': 45.0,

  'Name': 'Bulbasaur',

  'PokedexNumber': 1.0,

  'SpecialAttack': 65.0,

  'SpecialDefense': 65.0,

  'Speed': 45.0,

  'Total': 318.0,

  'Type': 'GrassPoison'},

 2.0: {'Attack': 62.0,

  'Defense': 63.0,

  'HP': 60.0,

  'Name': 'Ivysaur',

So from list of lists, I want to have a big nested dictionary.

To create this, I have written the below code in Python:

new_pd_keys = 

for i in range(1, len(new_pd)):

    new_pd_keys.append(new_pd[i][0])

Above, I get all the keys from column 1 and save them to a list called new_pd_keys.

Then use the below code to assign each keys' values:

for i in range(1,len(new_pd)):

    new_pd_dict = {key:{'Attack':new_pd[i][5], 'Defense':new_pd[i][6], 'HP':new_pd[i][4], 

          'Name':new_pd[i][1], 'PokedexNumber':new_pd[i][0], 'SpecialAttack':new_pd[i][7],

          'SpecialDefense':new_pd[i][8], 'Speed':new_pd[i][9], 'Total':new_pd[i][3], 

          'Type':new_pd[i][2]} for key in new_pd_keys }

But what I have is the attributes from my last row. You can see the output below, which are all the same.

{1.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

 2.0: {'Attack': 110.0,

  'Defense': 120.0,

  'HP': 80.0,

  'Name': 'Volcanion',

  'PokedexNumber': 721.0,

  'SpecialAttack': 130.0,

  'SpecialDefense': 90.0,

  'Speed': 70.0,

  'Total': 600.0,

  'Type': 'FireWater'},

Can you suggest a way to perform the indexing in a better way than mine?

python dictionary for-loop indexing

asked Nov 11 at 21:52

ykesen

555

asked Nov 11 at 21:52

ykesen

555

asked Nov 11 at 21:52

ykesen

555

asked Nov 11 at 21:52

ykesen

555

asked Nov 11 at 21:52

ykesen

555

if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10

add a comment |

if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10

if you are using a dict where the keys are ascending sequentially, you should be using a list. in this case a list of dicts
– aydow
Nov 11 at 22:10

add a comment |

1 Answer
1

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oldest

votes

up vote
2
down vote

new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

add a comment |

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1 Answer
1

active

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1 Answer
1

active

oldest

votes

up vote
2
down vote

new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

add a comment |

up vote
2
down vote

new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

add a comment |

up vote
2
down vote

new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

new_thing = {q[0]: dict(zip(thing[0], q[1:])) for q in thing[1:]}

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

edited Nov 11 at 22:04

answered Nov 11 at 21:58

MegaBluejay

33618

answered Nov 11 at 21:58

MegaBluejay

33618

answered Nov 11 at 21:58

MegaBluejay

33618

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

add a comment |

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

Thanks! It works, I will just make small changes to update the column order.
– ykesen
Nov 11 at 23:40

add a comment |

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