open and modify a value from another workbook











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Sub abrirotroworkbook()

Dim y As Workbook ' a donde se va a pegar
Dim vals As Variant

Set y = Workbooks.Open("C:Pathfilename.xlsm")

'Now, copy what you want from x:

vals = Sheet12.Range("A3:B3").Value


'Now, paste to y worksheet:

y.Sheets("Sheet1").Range(A5).Value = vals


End Sub


When I run this code it saves the information of the book I have opened in the variable vals, then it opens the other workbook, but when it tries to paste in it, the following error appears:




run time error '9' subscript out of range




I don't know what the problem is.










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  • 2




    I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
    – Storax
    Nov 10 at 16:06












  • Thank you so much. The problem was like you said that Sheet1 didn't exist.
    – Luis Claret
    Nov 11 at 16:08















up vote
0
down vote

favorite
1












Sub abrirotroworkbook()

Dim y As Workbook ' a donde se va a pegar
Dim vals As Variant

Set y = Workbooks.Open("C:Pathfilename.xlsm")

'Now, copy what you want from x:

vals = Sheet12.Range("A3:B3").Value


'Now, paste to y worksheet:

y.Sheets("Sheet1").Range(A5).Value = vals


End Sub


When I run this code it saves the information of the book I have opened in the variable vals, then it opens the other workbook, but when it tries to paste in it, the following error appears:




run time error '9' subscript out of range




I don't know what the problem is.










share|improve this question




















  • 2




    I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
    – Storax
    Nov 10 at 16:06












  • Thank you so much. The problem was like you said that Sheet1 didn't exist.
    – Luis Claret
    Nov 11 at 16:08













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





Sub abrirotroworkbook()

Dim y As Workbook ' a donde se va a pegar
Dim vals As Variant

Set y = Workbooks.Open("C:Pathfilename.xlsm")

'Now, copy what you want from x:

vals = Sheet12.Range("A3:B3").Value


'Now, paste to y worksheet:

y.Sheets("Sheet1").Range(A5).Value = vals


End Sub


When I run this code it saves the information of the book I have opened in the variable vals, then it opens the other workbook, but when it tries to paste in it, the following error appears:




run time error '9' subscript out of range




I don't know what the problem is.










share|improve this question















Sub abrirotroworkbook()

Dim y As Workbook ' a donde se va a pegar
Dim vals As Variant

Set y = Workbooks.Open("C:Pathfilename.xlsm")

'Now, copy what you want from x:

vals = Sheet12.Range("A3:B3").Value


'Now, paste to y worksheet:

y.Sheets("Sheet1").Range(A5).Value = vals


End Sub


When I run this code it saves the information of the book I have opened in the variable vals, then it opens the other workbook, but when it tries to paste in it, the following error appears:




run time error '9' subscript out of range




I don't know what the problem is.







excel vba excel-vba






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edited Nov 12 at 7:18









Pᴇʜ

18.7k42549




18.7k42549










asked Nov 10 at 15:34









Luis Claret

1




1








  • 2




    I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
    – Storax
    Nov 10 at 16:06












  • Thank you so much. The problem was like you said that Sheet1 didn't exist.
    – Luis Claret
    Nov 11 at 16:08














  • 2




    I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
    – Storax
    Nov 10 at 16:06












  • Thank you so much. The problem was like you said that Sheet1 didn't exist.
    – Luis Claret
    Nov 11 at 16:08








2




2




I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
– Storax
Nov 10 at 16:06






I assume you forgot to add quotes here y.Sheets("Sheet1").Range(A5).Value = vals. It should be y.Sheets("Sheet1").Range("A5").Value = vals, right? And does Sheet1exist in your workbook y you openend. That is usually the cause for runtime error 9 in such a case. Are you also aware that you create an array with vals = Sheet12.Range("A3:B3").Value and you only copy the first value of it with y.Sheets("Sheet1").Range(A5).Value = vals.
– Storax
Nov 10 at 16:06














Thank you so much. The problem was like you said that Sheet1 didn't exist.
– Luis Claret
Nov 11 at 16:08




Thank you so much. The problem was like you said that Sheet1 didn't exist.
– Luis Claret
Nov 11 at 16:08












1 Answer
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As @Storax said, your variable vals is not opening a workbook but creating an array.
You don't need an array for just copying two cells. You would have to loop through the array. The code below is basic. If you are copying from ThisWorkbook(the workbook your code is in) it will work. If it is another workbook then you can create another variable to open it, and use the variable instead of ThisWorkbook.



Dim wb1 As Workbook 'the source workbook
Set wb1 = Workbooks.Open("C:Pathsourcefilename.xlsm") 'change name and path as required

Dim wb2 As Workbook 'the destination workbook
Set wb2 = Workbooks.Open("C:Pathdestinationfilename.xlsm") 'change name and path as required

wb2.Sheets("Sheet1").Range("A5:B5").Value = ThisWorkbook.Sheets("Sheet12").Range("A3:B3").Value 'replace ThisWorkbook with `wb1`





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    As @Storax said, your variable vals is not opening a workbook but creating an array.
    You don't need an array for just copying two cells. You would have to loop through the array. The code below is basic. If you are copying from ThisWorkbook(the workbook your code is in) it will work. If it is another workbook then you can create another variable to open it, and use the variable instead of ThisWorkbook.



    Dim wb1 As Workbook 'the source workbook
    Set wb1 = Workbooks.Open("C:Pathsourcefilename.xlsm") 'change name and path as required

    Dim wb2 As Workbook 'the destination workbook
    Set wb2 = Workbooks.Open("C:Pathdestinationfilename.xlsm") 'change name and path as required

    wb2.Sheets("Sheet1").Range("A5:B5").Value = ThisWorkbook.Sheets("Sheet12").Range("A3:B3").Value 'replace ThisWorkbook with `wb1`





    share|improve this answer

























      up vote
      0
      down vote













      As @Storax said, your variable vals is not opening a workbook but creating an array.
      You don't need an array for just copying two cells. You would have to loop through the array. The code below is basic. If you are copying from ThisWorkbook(the workbook your code is in) it will work. If it is another workbook then you can create another variable to open it, and use the variable instead of ThisWorkbook.



      Dim wb1 As Workbook 'the source workbook
      Set wb1 = Workbooks.Open("C:Pathsourcefilename.xlsm") 'change name and path as required

      Dim wb2 As Workbook 'the destination workbook
      Set wb2 = Workbooks.Open("C:Pathdestinationfilename.xlsm") 'change name and path as required

      wb2.Sheets("Sheet1").Range("A5:B5").Value = ThisWorkbook.Sheets("Sheet12").Range("A3:B3").Value 'replace ThisWorkbook with `wb1`





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        As @Storax said, your variable vals is not opening a workbook but creating an array.
        You don't need an array for just copying two cells. You would have to loop through the array. The code below is basic. If you are copying from ThisWorkbook(the workbook your code is in) it will work. If it is another workbook then you can create another variable to open it, and use the variable instead of ThisWorkbook.



        Dim wb1 As Workbook 'the source workbook
        Set wb1 = Workbooks.Open("C:Pathsourcefilename.xlsm") 'change name and path as required

        Dim wb2 As Workbook 'the destination workbook
        Set wb2 = Workbooks.Open("C:Pathdestinationfilename.xlsm") 'change name and path as required

        wb2.Sheets("Sheet1").Range("A5:B5").Value = ThisWorkbook.Sheets("Sheet12").Range("A3:B3").Value 'replace ThisWorkbook with `wb1`





        share|improve this answer












        As @Storax said, your variable vals is not opening a workbook but creating an array.
        You don't need an array for just copying two cells. You would have to loop through the array. The code below is basic. If you are copying from ThisWorkbook(the workbook your code is in) it will work. If it is another workbook then you can create another variable to open it, and use the variable instead of ThisWorkbook.



        Dim wb1 As Workbook 'the source workbook
        Set wb1 = Workbooks.Open("C:Pathsourcefilename.xlsm") 'change name and path as required

        Dim wb2 As Workbook 'the destination workbook
        Set wb2 = Workbooks.Open("C:Pathdestinationfilename.xlsm") 'change name and path as required

        wb2.Sheets("Sheet1").Range("A5:B5").Value = ThisWorkbook.Sheets("Sheet12").Range("A3:B3").Value 'replace ThisWorkbook with `wb1`






        share|improve this answer












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        answered Nov 10 at 18:16









        GMalc

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