Floating-point precision problems
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Using Microsoft Excel 2010.
Why do these two formulae produce different results?
= (0.5 - 0.4 - 0.1)
produces -2.775E-17
while
= 0.5 - 0.4 - 0.1
produces exactly 0.
The only difference is in the brackets. Does Excel try to do clever things with floating-point numbers that it thinks should be a certain value instead of another value in order to hide the usual problems of binary floating-point and make it look as though it's using decimal arithmetic? Is this documented?
excel floating-point precision
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
add a comment |
Using Microsoft Excel 2010.
Why do these two formulae produce different results?
= (0.5 - 0.4 - 0.1)
produces -2.775E-17
while
= 0.5 - 0.4 - 0.1
produces exactly 0.
The only difference is in the brackets. Does Excel try to do clever things with floating-point numbers that it thinks should be a certain value instead of another value in order to hide the usual problems of binary floating-point and make it look as though it's using decimal arithmetic? Is this documented?
excel floating-point precision
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
1
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
2
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37
add a comment |
Using Microsoft Excel 2010.
Why do these two formulae produce different results?
= (0.5 - 0.4 - 0.1)
produces -2.775E-17
while
= 0.5 - 0.4 - 0.1
produces exactly 0.
The only difference is in the brackets. Does Excel try to do clever things with floating-point numbers that it thinks should be a certain value instead of another value in order to hide the usual problems of binary floating-point and make it look as though it's using decimal arithmetic? Is this documented?
excel floating-point precision
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
Using Microsoft Excel 2010.
Why do these two formulae produce different results?
= (0.5 - 0.4 - 0.1)
produces -2.775E-17
while
= 0.5 - 0.4 - 0.1
produces exactly 0.
The only difference is in the brackets. Does Excel try to do clever things with floating-point numbers that it thinks should be a certain value instead of another value in order to hide the usual problems of binary floating-point and make it look as though it's using decimal arithmetic? Is this documented?
excel floating-point precision
excel floating-point precision
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
asked Nov 16 '18 at 11:48
DodgyCodeExceptionDodgyCodeException
3,6571426
3,6571426
1
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
2
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37
add a comment |
1
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
2
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37
1
1
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
2
2
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37
add a comment |
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1
Consider reading this: link.
– Pspl
Nov 16 '18 at 11:54
2
Related: stackoverflow.com/q/36452194/270986, stackoverflow.com/q/40293983/270986. The answers to your last two questions appear to be (1) Yes, and (2) Not really, no.
– Mark Dickinson
Nov 16 '18 at 16:48
@MarkDickinson thanks. I think those two linked posts together fully answer my question in a roundabout way.
– DodgyCodeException
Nov 19 '18 at 9:37