Split a string into a list of strings
1
I have an input Json string like this:
var x= "[{"name":"ahmed","age":"26"},
{"name":"Sam","age":"25"}]"
I want to split it to a list of strings from{ to } as follows without removing a delimiter
var list;
list[0]= {"name":"ahmed","age":"26"}
list[1]= {"name":"Sam","age":"25"}
using the split method removes the delimiter and does not yield the correct format
x= x.replace(/[/]/g, '/'); //to remove [ and ]
x= x.replace( /},/ ,'}n' ); // does not split the string to list of strings
list = x; // type mismatch error since x is a string and list is array
javascript string replace split substring
asked Nov 13 '18 at 9:50
User MAUser MA
111
add a comment |
1
I have an input Json string like this:
var x= "[{"name":"ahmed","age":"26"},
{"name":"Sam","age":"25"}]"
I want to split it to a list of strings from{ to } as follows without removing a delimiter
var list;
list[0]= {"name":"ahmed","age":"26"}
list[1]= {"name":"Sam","age":"25"}
using the split method removes the delimiter and does not yield the correct format
x= x.replace(/[/]/g, '/'); //to remove [ and ]
x= x.replace( /},/ ,'}n' ); // does not split the string to list of strings
list = x; // type mismatch error since x is a string and list is array
javascript string replace split substring
asked Nov 13 '18 at 9:50
User MAUser MA
111
8
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00
add a comment |
1
1
1
I have an input Json string like this:
var x= "[{"name":"ahmed","age":"26"},
{"name":"Sam","age":"25"}]"
I want to split it to a list of strings from{ to } as follows without removing a delimiter
var list;
list[0]= {"name":"ahmed","age":"26"}
list[1]= {"name":"Sam","age":"25"}
using the split method removes the delimiter and does not yield the correct format
x= x.replace(/[/]/g, '/'); //to remove [ and ]
x= x.replace( /},/ ,'}n' ); // does not split the string to list of strings
list = x; // type mismatch error since x is a string and list is array
javascript string replace split substring
asked Nov 13 '18 at 9:50
User MAUser MA
111
I have an input Json string like this:
var x= "[{"name":"ahmed","age":"26"},
{"name":"Sam","age":"25"}]"
I want to split it to a list of strings from{ to } as follows without removing a delimiter
var list;
list[0]= {"name":"ahmed","age":"26"}
list[1]= {"name":"Sam","age":"25"}
using the split method removes the delimiter and does not yield the correct format
x= x.replace(/[/]/g, '/'); //to remove [ and ]
x= x.replace( /},/ ,'}n' ); // does not split the string to list of strings
list = x; // type mismatch error since x is a string and list is array
javascript string replace split substring
javascript string replace split substring
asked Nov 13 '18 at 9:50
User MAUser MA
111
asked Nov 13 '18 at 9:50
User MAUser MA
111
asked Nov 13 '18 at 9:50
User MAUser MA
111
asked Nov 13 '18 at 9:50
User MAUser MA
111
asked Nov 13 '18 at 9:50
User MAUser MA
111
111
8
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00
add a comment |
8
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00
8
8
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00
add a comment |
3 Answers
3
active
oldest
votes
1
As commented above by Teemu, using JSON.parse is the safe and correct way to parse json.
const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
add a comment |
1
You can parse it to JSON first then use map to make list out of it.
var parsedX = JSON.parse(x);
var list = parsedX.map(x => JSON.stringify(x).replace(/"/g,'\"'));
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
add a comment |
0
You could use following code to achieve desired result with this particular type of json:
var str = "[{"name":"ahmed","age":"26"}, {"name":"Sam","age":"25"}]";
var list = str.match(/[{][^{}]*[}]/gm);
alert(list)
Fell free to ask if you have any questions:
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
As commented above by Teemu, using JSON.parse is the safe and correct way to parse json.
const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
add a comment |
1
As commented above by Teemu, using JSON.parse is the safe and correct way to parse json.
const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
add a comment |
1
1
1
As commented above by Teemu, using JSON.parse is the safe and correct way to parse json.
const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
As commented above by Teemu, using JSON.parse is the safe and correct way to parse json.
const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));const x = "[{"name":"ahmed","age":"26"},{"name":"Sam","age":"25"}]";
console.log(JSON.parse(x));answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
answered Nov 13 '18 at 9:56
David LemonDavid Lemon
997618
997618
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
add a comment |
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
thanks @David for clarification
– User MA
Nov 13 '18 at 10:01
add a comment |
1
You can parse it to JSON first then use map to make list out of it.
var parsedX = JSON.parse(x);
var list = parsedX.map(x => JSON.stringify(x).replace(/"/g,'\"'));
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
add a comment |
1
You can parse it to JSON first then use map to make list out of it.
var parsedX = JSON.parse(x);
var list = parsedX.map(x => JSON.stringify(x).replace(/"/g,'\"'));
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
add a comment |
1
1
1
You can parse it to JSON first then use map to make list out of it.
var parsedX = JSON.parse(x);
var list = parsedX.map(x => JSON.stringify(x).replace(/"/g,'\"'));
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
You can parse it to JSON first then use map to make list out of it.
var parsedX = JSON.parse(x);
var list = parsedX.map(x => JSON.stringify(x).replace(/"/g,'\"'));
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
edited Nov 13 '18 at 10:15
qiAlex
2,0261724
2,0261724
answered Nov 13 '18 at 10:01
ptdienptdien
744
answered Nov 13 '18 at 10:01
ptdienptdien
744
answered Nov 13 '18 at 10:01
ptdienptdien
744
744
add a comment |
add a comment |
0
You could use following code to achieve desired result with this particular type of json:
var str = "[{"name":"ahmed","age":"26"}, {"name":"Sam","age":"25"}]";
var list = str.match(/[{][^{}]*[}]/gm);
alert(list)
Fell free to ask if you have any questions:
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
add a comment |
0
You could use following code to achieve desired result with this particular type of json:
var str = "[{"name":"ahmed","age":"26"}, {"name":"Sam","age":"25"}]";
var list = str.match(/[{][^{}]*[}]/gm);
alert(list)
Fell free to ask if you have any questions:
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
add a comment |
0
0
0
You could use following code to achieve desired result with this particular type of json:
var str = "[{"name":"ahmed","age":"26"}, {"name":"Sam","age":"25"}]";
var list = str.match(/[{][^{}]*[}]/gm);
alert(list)
Fell free to ask if you have any questions:
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
You could use following code to achieve desired result with this particular type of json:
var str = "[{"name":"ahmed","age":"26"}, {"name":"Sam","age":"25"}]";
var list = str.match(/[{][^{}]*[}]/gm);
alert(list)
Fell free to ask if you have any questions:
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
answered Nov 13 '18 at 10:34
Tornike ShavishviliTornike Shavishvili
61021022
61021022
add a comment |
add a comment |
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8
How about parsing the JSON using JSON.parse?
– Teemu
Nov 13 '18 at 9:51
Possible duplicate of JS string.split() without removing the delimiters
– pwolaq
Nov 13 '18 at 9:57
@Teemu thanks alot.. don't know how this didn't cross my mind...
– User MA
Nov 13 '18 at 10:00