QuTiP: Resolving inconsistent Qobj shapes
This was previously explored in QuTiP TypeError: Incompatible Qobj shapes with tensor product but I'm not sure about the answer there.
Suppose I define A = tensor(qeye(2), qeye(2)) and B = qeye(4), I cannot multiply them because the object shapes are inconsistent.
However, the matrices are of the same dimension and I would like to "flatten" A to allow it to be multiplied by B. If I have a combination of seperable operators and non-seperable ones, how do I use them together? In other words, B cannot be simplified further so what should I do to A to allow them to be multiplied?
EDIT: The clunky looking Qobj(A.data.toarray()) works but I'll leave this open in case someone has a better idea or understands why QuTiP does this.
python qutip
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
add a comment |
This was previously explored in QuTiP TypeError: Incompatible Qobj shapes with tensor product but I'm not sure about the answer there.
Suppose I define A = tensor(qeye(2), qeye(2)) and B = qeye(4), I cannot multiply them because the object shapes are inconsistent.
However, the matrices are of the same dimension and I would like to "flatten" A to allow it to be multiplied by B. If I have a combination of seperable operators and non-seperable ones, how do I use them together? In other words, B cannot be simplified further so what should I do to A to allow them to be multiplied?
EDIT: The clunky looking Qobj(A.data.toarray()) works but I'll leave this open in case someone has a better idea or understands why QuTiP does this.
python qutip
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
add a comment |
This was previously explored in QuTiP TypeError: Incompatible Qobj shapes with tensor product but I'm not sure about the answer there.
Suppose I define A = tensor(qeye(2), qeye(2)) and B = qeye(4), I cannot multiply them because the object shapes are inconsistent.
However, the matrices are of the same dimension and I would like to "flatten" A to allow it to be multiplied by B. If I have a combination of seperable operators and non-seperable ones, how do I use them together? In other words, B cannot be simplified further so what should I do to A to allow them to be multiplied?
EDIT: The clunky looking Qobj(A.data.toarray()) works but I'll leave this open in case someone has a better idea or understands why QuTiP does this.
python qutip
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
This was previously explored in QuTiP TypeError: Incompatible Qobj shapes with tensor product but I'm not sure about the answer there.
Suppose I define A = tensor(qeye(2), qeye(2)) and B = qeye(4), I cannot multiply them because the object shapes are inconsistent.
However, the matrices are of the same dimension and I would like to "flatten" A to allow it to be multiplied by B. If I have a combination of seperable operators and non-seperable ones, how do I use them together? In other words, B cannot be simplified further so what should I do to A to allow them to be multiplied?
EDIT: The clunky looking Qobj(A.data.toarray()) works but I'll leave this open in case someone has a better idea or understands why QuTiP does this.
python qutip
python qutip
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
edited Nov 13 '18 at 0:27
user1936752
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
asked Nov 12 '18 at 19:06
user1936752user1936752
231312
231312
add a comment |
add a comment |
1 Answer
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Yes using Qobj.data you get the matrix representing the state or operator.
Hence A.data * B.data allows you to multiply them together. Once you've done that you can enclose it in Qobj(A.data * B.data) to make it a quantum object.
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
add a comment |
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1 Answer
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1 Answer
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active
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Yes using Qobj.data you get the matrix representing the state or operator.
Hence A.data * B.data allows you to multiply them together. Once you've done that you can enclose it in Qobj(A.data * B.data) to make it a quantum object.
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
add a comment |
Yes using Qobj.data you get the matrix representing the state or operator.
Hence A.data * B.data allows you to multiply them together. Once you've done that you can enclose it in Qobj(A.data * B.data) to make it a quantum object.
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
add a comment |
Yes using Qobj.data you get the matrix representing the state or operator.
Hence A.data * B.data allows you to multiply them together. Once you've done that you can enclose it in Qobj(A.data * B.data) to make it a quantum object.
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
Yes using Qobj.data you get the matrix representing the state or operator.
Hence A.data * B.data allows you to multiply them together. Once you've done that you can enclose it in Qobj(A.data * B.data) to make it a quantum object.
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
edited Nov 14 '18 at 11:58
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
answered Nov 13 '18 at 19:12
TurbotantenTurbotanten
1978
1978
add a comment |
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