Postgresql query containing a constant in a logical-or leads to full table scan












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I have a query that contains a clause of the form CONSTANT OR t.foo=:foo, where CONSTANT is some expression that evaluates to a constant boolean value. Then the query is executed as a full table scan, even when there is an index on column foo and the simple t.foo=:foo would use the index. The example query that I analyzed had the form :foo IS NOT NULL OR t.foo=:foo. Here is a simple example:



CREATE TABLE tst (
id serial,
name VARCHAR NOT NULL,
age INTEGER NOT NULL,
CONSTRAINT PK_ID PRIMARY KEY(ID));

EXPLAIN SELECT * FROM tst WHERE (23 IS NOT NULL OR id=23);
QUERY PLAN
--------------------------------------------------------
Seq Scan on tst (cost=0.00..22.00 rows=1200 width=40)


Is there any reason for this? Is there a way to tell the optimizer to logically evaluate/simplify the query?










share|improve this question


















  • 3




    where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
    – a_horse_with_no_name
    Nov 12 '18 at 19:38










  • You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
    – EPSG31468
    Nov 17 '18 at 18:44
















0














I have a query that contains a clause of the form CONSTANT OR t.foo=:foo, where CONSTANT is some expression that evaluates to a constant boolean value. Then the query is executed as a full table scan, even when there is an index on column foo and the simple t.foo=:foo would use the index. The example query that I analyzed had the form :foo IS NOT NULL OR t.foo=:foo. Here is a simple example:



CREATE TABLE tst (
id serial,
name VARCHAR NOT NULL,
age INTEGER NOT NULL,
CONSTRAINT PK_ID PRIMARY KEY(ID));

EXPLAIN SELECT * FROM tst WHERE (23 IS NOT NULL OR id=23);
QUERY PLAN
--------------------------------------------------------
Seq Scan on tst (cost=0.00..22.00 rows=1200 width=40)


Is there any reason for this? Is there a way to tell the optimizer to logically evaluate/simplify the query?










share|improve this question


















  • 3




    where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
    – a_horse_with_no_name
    Nov 12 '18 at 19:38










  • You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
    – EPSG31468
    Nov 17 '18 at 18:44














0












0








0







I have a query that contains a clause of the form CONSTANT OR t.foo=:foo, where CONSTANT is some expression that evaluates to a constant boolean value. Then the query is executed as a full table scan, even when there is an index on column foo and the simple t.foo=:foo would use the index. The example query that I analyzed had the form :foo IS NOT NULL OR t.foo=:foo. Here is a simple example:



CREATE TABLE tst (
id serial,
name VARCHAR NOT NULL,
age INTEGER NOT NULL,
CONSTRAINT PK_ID PRIMARY KEY(ID));

EXPLAIN SELECT * FROM tst WHERE (23 IS NOT NULL OR id=23);
QUERY PLAN
--------------------------------------------------------
Seq Scan on tst (cost=0.00..22.00 rows=1200 width=40)


Is there any reason for this? Is there a way to tell the optimizer to logically evaluate/simplify the query?










share|improve this question













I have a query that contains a clause of the form CONSTANT OR t.foo=:foo, where CONSTANT is some expression that evaluates to a constant boolean value. Then the query is executed as a full table scan, even when there is an index on column foo and the simple t.foo=:foo would use the index. The example query that I analyzed had the form :foo IS NOT NULL OR t.foo=:foo. Here is a simple example:



CREATE TABLE tst (
id serial,
name VARCHAR NOT NULL,
age INTEGER NOT NULL,
CONSTRAINT PK_ID PRIMARY KEY(ID));

EXPLAIN SELECT * FROM tst WHERE (23 IS NOT NULL OR id=23);
QUERY PLAN
--------------------------------------------------------
Seq Scan on tst (cost=0.00..22.00 rows=1200 width=40)


Is there any reason for this? Is there a way to tell the optimizer to logically evaluate/simplify the query?







postgresql query-optimization boolean-logic






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 '18 at 19:09









EPSG31468EPSG31468

668416




668416








  • 3




    where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
    – a_horse_with_no_name
    Nov 12 '18 at 19:38










  • You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
    – EPSG31468
    Nov 17 '18 at 18:44














  • 3




    where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
    – a_horse_with_no_name
    Nov 12 '18 at 19:38










  • You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
    – EPSG31468
    Nov 17 '18 at 18:44








3




3




where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
– a_horse_with_no_name
Nov 12 '18 at 19:38




where (23 IS NOT NULL OR id=23) is the same as where (true or id = 23) which is the same as where true which is the same as not having a where condition at all. So you request all rows of the table, and the most efficient way to do that is a Seq Scan
– a_horse_with_no_name
Nov 12 '18 at 19:38












You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
– EPSG31468
Nov 17 '18 at 18:44




You are right, this was totally non-sense. I tried to simplify a more complex example, but this is of cause a full-table scan because the WHERE-part is true.
– EPSG31468
Nov 17 '18 at 18:44












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