Passing Complex object via web sockets
Using .NetCore...
I have a C# server side code.
It creates an object list like:
[Serializable]
public class MyObject
{
public string test { get; set;}
}
var manyOfTheseObjects = new List<MyObject>();
manyOfTheseObjects ~ add a few records
I now convert to a ByteArray ~
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
On the JavaScript side I am listening on the web socket:
ws.onopen = function (data) {
try {
console.log("onopen");
console.log(JSON.parse(data).result);
$("#divConnectionStatus").html("Client connected");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onopen: " + err);
}
};
I get the error:
SyntaxError: Unexpected token o in JSON at position 1
at JSON.parse (<anonymous>)
at WebSocket.Connect.ws.onopen (LiveFeed.js:182)
I am obviously doing this completely wrong...
NB
Changed this:
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
to this:
socket.Send( JsonConvert.SerializeObject(manyOfTheseObjects ) );
javascript c# websocket
|
show 6 more comments
Using .NetCore...
I have a C# server side code.
It creates an object list like:
[Serializable]
public class MyObject
{
public string test { get; set;}
}
var manyOfTheseObjects = new List<MyObject>();
manyOfTheseObjects ~ add a few records
I now convert to a ByteArray ~
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
On the JavaScript side I am listening on the web socket:
ws.onopen = function (data) {
try {
console.log("onopen");
console.log(JSON.parse(data).result);
$("#divConnectionStatus").html("Client connected");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onopen: " + err);
}
};
I get the error:
SyntaxError: Unexpected token o in JSON at position 1
at JSON.parse (<anonymous>)
at WebSocket.Connect.ws.onopen (LiveFeed.js:182)
I am obviously doing this completely wrong...
NB
Changed this:
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
to this:
socket.Send( JsonConvert.SerializeObject(manyOfTheseObjects ) );
javascript c# websocket
1
A byte array is not necessarily valid JSON. You should probably useJsonConvert.SerializeObject()
if you want JSON...
– Heretic Monkey
Nov 12 '18 at 19:11
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
Add what you get when you doconsole.log(data)
within youronopen
handler.
– Heretic Monkey
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.
– Marc Gravell♦
Nov 12 '18 at 19:28
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what isconsole.log(data)
?
– Marc Gravell♦
Nov 12 '18 at 19:29
|
show 6 more comments
Using .NetCore...
I have a C# server side code.
It creates an object list like:
[Serializable]
public class MyObject
{
public string test { get; set;}
}
var manyOfTheseObjects = new List<MyObject>();
manyOfTheseObjects ~ add a few records
I now convert to a ByteArray ~
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
On the JavaScript side I am listening on the web socket:
ws.onopen = function (data) {
try {
console.log("onopen");
console.log(JSON.parse(data).result);
$("#divConnectionStatus").html("Client connected");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onopen: " + err);
}
};
I get the error:
SyntaxError: Unexpected token o in JSON at position 1
at JSON.parse (<anonymous>)
at WebSocket.Connect.ws.onopen (LiveFeed.js:182)
I am obviously doing this completely wrong...
NB
Changed this:
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
to this:
socket.Send( JsonConvert.SerializeObject(manyOfTheseObjects ) );
javascript c# websocket
Using .NetCore...
I have a C# server side code.
It creates an object list like:
[Serializable]
public class MyObject
{
public string test { get; set;}
}
var manyOfTheseObjects = new List<MyObject>();
manyOfTheseObjects ~ add a few records
I now convert to a ByteArray ~
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
On the JavaScript side I am listening on the web socket:
ws.onopen = function (data) {
try {
console.log("onopen");
console.log(JSON.parse(data).result);
$("#divConnectionStatus").html("Client connected");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onopen: " + err);
}
};
I get the error:
SyntaxError: Unexpected token o in JSON at position 1
at JSON.parse (<anonymous>)
at WebSocket.Connect.ws.onopen (LiveFeed.js:182)
I am obviously doing this completely wrong...
NB
Changed this:
var binFormatter = new BinaryFormatter();
var mStream = new MemoryStream();
binFormatter.Serialize(mStream, manyOfTheseObjects);
socket.Send(mStream.ToArray());
to this:
socket.Send( JsonConvert.SerializeObject(manyOfTheseObjects ) );
javascript c# websocket
javascript c# websocket
edited Nov 12 '18 at 19:27
Andrew Simpson
asked Nov 12 '18 at 19:09
Andrew SimpsonAndrew Simpson
2,783737101
2,783737101
1
A byte array is not necessarily valid JSON. You should probably useJsonConvert.SerializeObject()
if you want JSON...
– Heretic Monkey
Nov 12 '18 at 19:11
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
Add what you get when you doconsole.log(data)
within youronopen
handler.
– Heretic Monkey
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.
– Marc Gravell♦
Nov 12 '18 at 19:28
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what isconsole.log(data)
?
– Marc Gravell♦
Nov 12 '18 at 19:29
|
show 6 more comments
1
A byte array is not necessarily valid JSON. You should probably useJsonConvert.SerializeObject()
if you want JSON...
– Heretic Monkey
Nov 12 '18 at 19:11
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
Add what you get when you doconsole.log(data)
within youronopen
handler.
– Heretic Monkey
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.
– Marc Gravell♦
Nov 12 '18 at 19:28
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what isconsole.log(data)
?
– Marc Gravell♦
Nov 12 '18 at 19:29
1
1
A byte array is not necessarily valid JSON. You should probably use
JsonConvert.SerializeObject()
if you want JSON...– Heretic Monkey
Nov 12 '18 at 19:11
A byte array is not necessarily valid JSON. You should probably use
JsonConvert.SerializeObject()
if you want JSON...– Heretic Monkey
Nov 12 '18 at 19:11
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
Add what you get when you do
console.log(data)
within your onopen
handler.– Heretic Monkey
Nov 12 '18 at 19:28
Add what you get when you do
console.log(data)
within your onopen
handler.– Heretic Monkey
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.– Marc Gravell♦
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.– Marc Gravell♦
Nov 12 '18 at 19:28
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what is
console.log(data)
?– Marc Gravell♦
Nov 12 '18 at 19:29
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what is
console.log(data)
?– Marc Gravell♦
Nov 12 '18 at 19:29
|
show 6 more comments
1 Answer
1
active
oldest
votes
Now that you've switch to a JSON serializer: you want onmessage
, not onopen
:
ws.onmessage = function (evt) {
try {
console.log("onmessage");
console.log(JSON.parse(evt.data).result);
$("#divConnectionStatus").html("Message received");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onmessage: " + err);
}
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;onmessage
is
– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53268591%2fpassing-complex-object-via-web-sockets%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Now that you've switch to a JSON serializer: you want onmessage
, not onopen
:
ws.onmessage = function (evt) {
try {
console.log("onmessage");
console.log(JSON.parse(evt.data).result);
$("#divConnectionStatus").html("Message received");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onmessage: " + err);
}
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;onmessage
is
– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
add a comment |
Now that you've switch to a JSON serializer: you want onmessage
, not onopen
:
ws.onmessage = function (evt) {
try {
console.log("onmessage");
console.log(JSON.parse(evt.data).result);
$("#divConnectionStatus").html("Message received");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onmessage: " + err);
}
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;onmessage
is
– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
add a comment |
Now that you've switch to a JSON serializer: you want onmessage
, not onopen
:
ws.onmessage = function (evt) {
try {
console.log("onmessage");
console.log(JSON.parse(evt.data).result);
$("#divConnectionStatus").html("Message received");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onmessage: " + err);
}
Now that you've switch to a JSON serializer: you want onmessage
, not onopen
:
ws.onmessage = function (evt) {
try {
console.log("onmessage");
console.log(JSON.parse(evt.data).result);
$("#divConnectionStatus").html("Message received");
resume= 1;}
catch (err) {
console.log(err);
$("#divConnectionStatus").html("onmessage: " + err);
}
edited Nov 12 '18 at 19:37
answered Nov 12 '18 at 19:32
Marc Gravell♦Marc Gravell
778k19221262540
778k19221262540
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;onmessage
is
– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
add a comment |
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;onmessage
is
– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
Thanks for ur answer. I will update my qquestion with the console.log(data); in a mo
– Andrew Simpson
Nov 12 '18 at 19:33
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
When I initially request a connection credentials ae sent back from server to client. It is quite acceptable for me to catch the message there?
– Andrew Simpson
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;
onmessage
is– Marc Gravell♦
Nov 12 '18 at 19:34
@AndrewSimpson no, because that isn't the event that gets raised for messages;
onmessage
is– Marc Gravell♦
Nov 12 '18 at 19:34
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
I shall recheck. :)
– Andrew Simpson
Nov 12 '18 at 19:35
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
thanks v much, u r a smart cool dude..
– Andrew Simpson
Nov 12 '18 at 19:39
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53268591%2fpassing-complex-object-via-web-sockets%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
A byte array is not necessarily valid JSON. You should probably use
JsonConvert.SerializeObject()
if you want JSON...– Heretic Monkey
Nov 12 '18 at 19:11
just changed it to that. same error. Will update my question with that code
– Andrew Simpson
Nov 12 '18 at 19:26
Add what you get when you do
console.log(data)
within youronopen
handler.– Heretic Monkey
Nov 12 '18 at 19:28
BinaryFormatter
is a .NET-specific binary serializer (and frankly: one I would avoid) - it isn't JSON. If you want: use a JSON serializer.– Marc Gravell♦
Nov 12 '18 at 19:28
with the edit; what does the received payload turn out to be? As @HereticMonkey asks: what is
console.log(data)
?– Marc Gravell♦
Nov 12 '18 at 19:29