How can I enable the input if the two ajax functions check that there is no email and the user
up vote
0
down vote
favorite
I have a form checking real-time username and email.
$('#email').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {email: $th.val()},
success: function(data){
$("#resultEmail").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 1
})
$('#username').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {username: $th.val()},
success: function(data){
$("#resultUser").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 2
});
HTML
<div class="input">
<input type="text" name="username" id="username" required="required" pattern="^[a-zA-Z0-9]+$" class="input-field"/>
<label for="username" class="label-field">Username <div id="resultUser">*</div></label>
</div>
<div class="input">
<input type="email" name="email" id="email" class="input-field" required="required"/>
<label for="email" class="label-field">E-mail <div id="resultEmail">*</div></label>
</div>
<input type="submit" name="enviar" id="enviar" value="Enviar" disabled />
How can I make the input be enabled if the requests verify that the username and the email do not exist in the database
in check.php page if there is email or username print
$rows = $query->num_rows;
if($rows>0){
echo "exists in DB";
}
php jquery database
edited Nov 15 at 21:52
marc_s
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
add a comment |
up vote
0
down vote
favorite
I have a form checking real-time username and email.
$('#email').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {email: $th.val()},
success: function(data){
$("#resultEmail").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 1
})
$('#username').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {username: $th.val()},
success: function(data){
$("#resultUser").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 2
});
HTML
<div class="input">
<input type="text" name="username" id="username" required="required" pattern="^[a-zA-Z0-9]+$" class="input-field"/>
<label for="username" class="label-field">Username <div id="resultUser">*</div></label>
</div>
<div class="input">
<input type="email" name="email" id="email" class="input-field" required="required"/>
<label for="email" class="label-field">E-mail <div id="resultEmail">*</div></label>
</div>
<input type="submit" name="enviar" id="enviar" value="Enviar" disabled />
How can I make the input be enabled if the requests verify that the username and the email do not exist in the database
in check.php page if there is email or username print
$rows = $query->num_rows;
if($rows>0){
echo "exists in DB";
}
php jquery database
edited Nov 15 at 21:52
marc_s
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
If you're already using jQuery, you should look at usingDeferredobjects to achieve this. Specifically, if you want to have two separateAJAXrequests that you only act upon when both are complete/successful, the.when()method allows this: api.jquery.com/jquery.when
– Stevangelista
Nov 11 at 23:15
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a form checking real-time username and email.
$('#email').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {email: $th.val()},
success: function(data){
$("#resultEmail").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 1
})
$('#username').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {username: $th.val()},
success: function(data){
$("#resultUser").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 2
});
HTML
<div class="input">
<input type="text" name="username" id="username" required="required" pattern="^[a-zA-Z0-9]+$" class="input-field"/>
<label for="username" class="label-field">Username <div id="resultUser">*</div></label>
</div>
<div class="input">
<input type="email" name="email" id="email" class="input-field" required="required"/>
<label for="email" class="label-field">E-mail <div id="resultEmail">*</div></label>
</div>
<input type="submit" name="enviar" id="enviar" value="Enviar" disabled />
How can I make the input be enabled if the requests verify that the username and the email do not exist in the database
in check.php page if there is email or username print
$rows = $query->num_rows;
if($rows>0){
echo "exists in DB";
}
php jquery database
edited Nov 15 at 21:52
marc_s
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
I have a form checking real-time username and email.
$('#email').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {email: $th.val()},
success: function(data){
$("#resultEmail").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 1
})
$('#username').blur(function() {
$th = $(this);
$.ajax({
url: 'check.php',
type: 'POST',
data: {username: $th.val()},
success: function(data){
$("#resultUser").html("* "+data);
},
error: function(){
$("#error").html("Error");
}
});//ajax 2
});
HTML
<div class="input">
<input type="text" name="username" id="username" required="required" pattern="^[a-zA-Z0-9]+$" class="input-field"/>
<label for="username" class="label-field">Username <div id="resultUser">*</div></label>
</div>
<div class="input">
<input type="email" name="email" id="email" class="input-field" required="required"/>
<label for="email" class="label-field">E-mail <div id="resultEmail">*</div></label>
</div>
<input type="submit" name="enviar" id="enviar" value="Enviar" disabled />
How can I make the input be enabled if the requests verify that the username and the email do not exist in the database
in check.php page if there is email or username print
$rows = $query->num_rows;
if($rows>0){
echo "exists in DB";
}
php jquery database
php jquery database
edited Nov 15 at 21:52
marc_s
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
edited Nov 15 at 21:52
marc_s
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
edited Nov 15 at 21:52
marc_s
569k12811001250
edited Nov 15 at 21:52
marc_s
569k12811001250
edited Nov 15 at 21:52
marc_s
569k12811001250
569k12811001250
asked Nov 11 at 23:07
Leo Caracciolo
11416
asked Nov 11 at 23:07
Leo Caracciolo
11416
asked Nov 11 at 23:07
Leo Caracciolo
11416
11416
If you're already using jQuery, you should look at usingDeferredobjects to achieve this. Specifically, if you want to have two separateAJAXrequests that you only act upon when both are complete/successful, the.when()method allows this: api.jquery.com/jquery.when
– Stevangelista
Nov 11 at 23:15
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52
add a comment |
If you're already using jQuery, you should look at usingDeferredobjects to achieve this. Specifically, if you want to have two separateAJAXrequests that you only act upon when both are complete/successful, the.when()method allows this: api.jquery.com/jquery.when
– Stevangelista
Nov 11 at 23:15
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52
If you're already using jQuery, you should look at using
Deferred objects to achieve this. Specifically, if you want to have two separate AJAX requests that you only act upon when both are complete/successful, the .when() method allows this: api.jquery.com/jquery.when– Stevangelista
Nov 11 at 23:15
If you're already using jQuery, you should look at using
Deferred objects to achieve this. Specifically, if you want to have two separate AJAX requests that you only act upon when both are complete/successful, the .when() method allows this: api.jquery.com/jquery.when– Stevangelista
Nov 11 at 23:15
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52
add a comment |
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254150%2fhow-can-i-enable-the-input-if-the-two-ajax-functions-check-that-there-is-no-emai%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254150%2fhow-can-i-enable-the-input-if-the-two-ajax-functions-check-that-there-is-no-emai%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
If you're already using jQuery, you should look at using
Deferredobjects to achieve this. Specifically, if you want to have two separateAJAXrequests that you only act upon when both are complete/successful, the.when()method allows this: api.jquery.com/jquery.when– Stevangelista
Nov 11 at 23:15
I would suggest you do all the checking during submit of the form. That way is more user friendly in my opinion.
– guradio
Nov 11 at 23:52