Accessing super class methods in django

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0
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I have the following model,
a User

class User(AbstractBaseUser, PermissionsMixin, Base):

    email = models.EmailField(db_index=True, unique=True, max_length=255)

    mobile = PhoneNumberField(null=True)

    username = models.CharField(db_index=True, null=False, unique=True, max_length=255)

A base class

class Room(Base):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    status = models.CharField(default=RoomStatus.ACTIVE, max_length=256, null=True)

    members = models.ManyToManyField(User)

    last_activity = models.DateTimeField(default=timezone.now)

And two children

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)



class ClubRoom(Room):

    club = models.ForeignKey(Club, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

I want to access the leagueroom_set for the user. I'm not sure how to do this. The user currently has a property room_set, but I wish to access the specific room_set. Can someone help me with this?

asked Nov 11 at 17:11

Melissa Stewart

780622

You are using multi-table inheritance here. Did you mean for Room to be a table in the database, or did you only want it to be a base class to define the shared fields for the league and club models?
– Martijn Pieters♦
Nov 11 at 17:18

@MartijnPieters I don't have any real use of the Room, but I can't make it abstract because I need the room id to globally sort all forms of room.
– Melissa Stewart
Nov 11 at 17:21

add a comment |

up vote
0
down vote

favorite

I have the following model,
a User

class User(AbstractBaseUser, PermissionsMixin, Base):

    email = models.EmailField(db_index=True, unique=True, max_length=255)

    mobile = PhoneNumberField(null=True)

    username = models.CharField(db_index=True, null=False, unique=True, max_length=255)

A base class

class Room(Base):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    status = models.CharField(default=RoomStatus.ACTIVE, max_length=256, null=True)

    members = models.ManyToManyField(User)

    last_activity = models.DateTimeField(default=timezone.now)

And two children

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)



class ClubRoom(Room):

    club = models.ForeignKey(Club, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

asked Nov 11 at 17:11

Melissa Stewart

780622

You are using multi-table inheritance here. Did you mean for Room to be a table in the database, or did you only want it to be a base class to define the shared fields for the league and club models?
– Martijn Pieters♦
Nov 11 at 17:18

@MartijnPieters I don't have any real use of the Room, but I can't make it abstract because I need the room id to globally sort all forms of room.
– Melissa Stewart
Nov 11 at 17:21

add a comment |

up vote
0
down vote

favorite

I have the following model,
a User

class User(AbstractBaseUser, PermissionsMixin, Base):

    email = models.EmailField(db_index=True, unique=True, max_length=255)

    mobile = PhoneNumberField(null=True)

    username = models.CharField(db_index=True, null=False, unique=True, max_length=255)

A base class

class Room(Base):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    status = models.CharField(default=RoomStatus.ACTIVE, max_length=256, null=True)

    members = models.ManyToManyField(User)

    last_activity = models.DateTimeField(default=timezone.now)

And two children

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)



class ClubRoom(Room):

    club = models.ForeignKey(Club, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

asked Nov 11 at 17:11

Melissa Stewart

780622

I have the following model,
a User

class User(AbstractBaseUser, PermissionsMixin, Base):

    email = models.EmailField(db_index=True, unique=True, max_length=255)

    mobile = PhoneNumberField(null=True)

    username = models.CharField(db_index=True, null=False, unique=True, max_length=255)

A base class

class Room(Base):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    status = models.CharField(default=RoomStatus.ACTIVE, max_length=256, null=True)

    members = models.ManyToManyField(User)

    last_activity = models.DateTimeField(default=timezone.now)

And two children

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)



class ClubRoom(Room):

    club = models.ForeignKey(Club, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

python django django-models

asked Nov 11 at 17:11

Melissa Stewart

780622

asked Nov 11 at 17:11

Melissa Stewart

780622

asked Nov 11 at 17:11

Melissa Stewart

780622

asked Nov 11 at 17:11

Melissa Stewart

780622

asked Nov 11 at 17:11

Melissa Stewart

780622

You are using multi-table inheritance here. Did you mean for Room to be a table in the database, or did you only want it to be a base class to define the shared fields for the league and club models?
– Martijn Pieters♦
Nov 11 at 17:18

@MartijnPieters I don't have any real use of the Room, but I can't make it abstract because I need the room id to globally sort all forms of room.
– Melissa Stewart
Nov 11 at 17:21

add a comment |

You are using multi-table inheritance here. Did you mean for Room to be a table in the database, or did you only want it to be a base class to define the shared fields for the league and club models?
– Martijn Pieters♦
Nov 11 at 17:18

@MartijnPieters I don't have any real use of the Room, but I can't make it abstract because I need the room id to globally sort all forms of room.
– Melissa Stewart
Nov 11 at 17:21

You are using multi-table inheritance here. Did you mean for Room to be a table in the database, or did you only want it to be a base class to define the shared fields for the league and club models?
– Martijn Pieters♦
Nov 11 at 17:18

@MartijnPieters I don't have any real use of the Room, but I can't make it abstract because I need the room id to globally sort all forms of room.
– Melissa Stewart
Nov 11 at 17:21

add a comment |

2 Answers
2

active

oldest

votes

up vote
2
down vote

You could start from the other end:

league_rooms = LeagueRoom.objects.filter(members=my_user)

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

add a comment |

up vote
1
down vote

I think you want Room to be an abstract base class. Then what you are trying to do will work. https://docs.djangoproject.com/en/2.1/topics/db/models/#model-inheritance

class Room(models.Model):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    # other fields

    …



    class Meta:

        abstract = True

If Room can't be an abstract class, then you'll have to move your members field from Room into each of the subclasses to use the built-in relationships.

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

    members = models.ManyToManyField(User)



# same with ClubRoom

Third option I can think of is to set a type attribute on each of your subclasses so that you can filter room_set to the type of room you want.
```
class LeagueRoom(Room):

   …

   type = models.CharField(max_length=10, default='league')

   …
```
Then somewhere else:
```
room_set.filter(type='league')
```

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

You could start from the other end:

league_rooms = LeagueRoom.objects.filter(members=my_user)

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

add a comment |

up vote
2
down vote

You could start from the other end:

league_rooms = LeagueRoom.objects.filter(members=my_user)

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

add a comment |

up vote
2
down vote

You could start from the other end:

league_rooms = LeagueRoom.objects.filter(members=my_user)

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

You could start from the other end:

league_rooms = LeagueRoom.objects.filter(members=my_user)

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

answered Nov 11 at 17:18

Daniel Roseman

442k41573628

add a comment |

up vote
1
down vote

I think you want Room to be an abstract base class. Then what you are trying to do will work. https://docs.djangoproject.com/en/2.1/topics/db/models/#model-inheritance

class Room(models.Model):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    # other fields

    …



    class Meta:

        abstract = True

If Room can't be an abstract class, then you'll have to move your members field from Room into each of the subclasses to use the built-in relationships.

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

    members = models.ManyToManyField(User)



# same with ClubRoom

Third option I can think of is to set a type attribute on each of your subclasses so that you can filter room_set to the type of room you want.
```
class LeagueRoom(Room):

   …

   type = models.CharField(max_length=10, default='league')

   …
```
Then somewhere else:
```
room_set.filter(type='league')
```

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

add a comment |

up vote
1
down vote

I think you want Room to be an abstract base class. Then what you are trying to do will work. https://docs.djangoproject.com/en/2.1/topics/db/models/#model-inheritance

class Room(models.Model):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    # other fields

    …



    class Meta:

        abstract = True

If Room can't be an abstract class, then you'll have to move your members field from Room into each of the subclasses to use the built-in relationships.

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

    members = models.ManyToManyField(User)



# same with ClubRoom

Third option I can think of is to set a type attribute on each of your subclasses so that you can filter room_set to the type of room you want.
```
class LeagueRoom(Room):

   …

   type = models.CharField(max_length=10, default='league')

   …
```
Then somewhere else:
```
room_set.filter(type='league')
```

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

add a comment |

up vote
1
down vote

I think you want Room to be an abstract base class. Then what you are trying to do will work. https://docs.djangoproject.com/en/2.1/topics/db/models/#model-inheritance

class Room(models.Model):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    # other fields

    …



    class Meta:

        abstract = True

If Room can't be an abstract class, then you'll have to move your members field from Room into each of the subclasses to use the built-in relationships.

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

    members = models.ManyToManyField(User)



# same with ClubRoom

Third option I can think of is to set a type attribute on each of your subclasses so that you can filter room_set to the type of room you want.
```
class LeagueRoom(Room):

   …

   type = models.CharField(max_length=10, default='league')

   …
```
Then somewhere else:
```
room_set.filter(type='league')
```

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

I think you want Room to be an abstract base class. Then what you are trying to do will work. https://docs.djangoproject.com/en/2.1/topics/db/models/#model-inheritance

class Room(models.Model):

    name = models.CharField(db_index=True, unique=True, max_length=255)

    # other fields

    …



    class Meta:

        abstract = True

If Room can't be an abstract class, then you'll have to move your members field from Room into each of the subclasses to use the built-in relationships.

class LeagueRoom(Room):

    league = models.ForeignKey(League, on_delete=models.CASCADE, null=True)

    location = models.ForeignKey(Location, on_delete=models.CASCADE, null=True)

    members = models.ManyToManyField(User)



# same with ClubRoom

Third option I can think of is to set a type attribute on each of your subclasses so that you can filter room_set to the type of room you want.
```
class LeagueRoom(Room):

   …

   type = models.CharField(max_length=10, default='league')

   …
```
Then somewhere else:
```
room_set.filter(type='league')
```

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

edited Nov 12 at 1:29

answered Nov 12 at 1:23

Victor Bruno

886610

answered Nov 12 at 1:23

Victor Bruno

886610

answered Nov 12 at 1:23

Victor Bruno

886610

add a comment |

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