Finding out if multiple values in a list of lists are the same value











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This is my problem:



I have a list of lists (adjoining) that is setup of x and y coordinates.



I'm trying to create a function that can figure out which way to go, that should return a single element from that list.



That return value will be the direction the character moves.



(Example: adjoining = [[1, 0], [3, 2], [1, 1]]. Return returns the smallest both x and y coordinate which is [1, 0].)



My function should return the value with the lowest x coordinate. If there are multiple x coordinates that have the same low value, the one with the lowest y coordinate should be chosen.



How can I create a function that can figure out which x and y value is lowest?










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  • 3




    You could use min
    – Daniel Mesejo
    Nov 10 at 17:29

















up vote
0
down vote

favorite












This is my problem:



I have a list of lists (adjoining) that is setup of x and y coordinates.



I'm trying to create a function that can figure out which way to go, that should return a single element from that list.



That return value will be the direction the character moves.



(Example: adjoining = [[1, 0], [3, 2], [1, 1]]. Return returns the smallest both x and y coordinate which is [1, 0].)



My function should return the value with the lowest x coordinate. If there are multiple x coordinates that have the same low value, the one with the lowest y coordinate should be chosen.



How can I create a function that can figure out which x and y value is lowest?










share|improve this question




















  • 3




    You could use min
    – Daniel Mesejo
    Nov 10 at 17:29















up vote
0
down vote

favorite









up vote
0
down vote

favorite











This is my problem:



I have a list of lists (adjoining) that is setup of x and y coordinates.



I'm trying to create a function that can figure out which way to go, that should return a single element from that list.



That return value will be the direction the character moves.



(Example: adjoining = [[1, 0], [3, 2], [1, 1]]. Return returns the smallest both x and y coordinate which is [1, 0].)



My function should return the value with the lowest x coordinate. If there are multiple x coordinates that have the same low value, the one with the lowest y coordinate should be chosen.



How can I create a function that can figure out which x and y value is lowest?










share|improve this question















This is my problem:



I have a list of lists (adjoining) that is setup of x and y coordinates.



I'm trying to create a function that can figure out which way to go, that should return a single element from that list.



That return value will be the direction the character moves.



(Example: adjoining = [[1, 0], [3, 2], [1, 1]]. Return returns the smallest both x and y coordinate which is [1, 0].)



My function should return the value with the lowest x coordinate. If there are multiple x coordinates that have the same low value, the one with the lowest y coordinate should be chosen.



How can I create a function that can figure out which x and y value is lowest?







python python-3.x






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edited Nov 10 at 17:30









Vasilis G.

2,6042621




2,6042621










asked Nov 10 at 17:26









Sigurd Setså

11




11








  • 3




    You could use min
    – Daniel Mesejo
    Nov 10 at 17:29
















  • 3




    You could use min
    – Daniel Mesejo
    Nov 10 at 17:29










3




3




You could use min
– Daniel Mesejo
Nov 10 at 17:29






You could use min
– Daniel Mesejo
Nov 10 at 17:29














3 Answers
3






active

oldest

votes

















up vote
0
down vote













Just use min() like so:



>>> adjoining = [[3,2],[1,1],[1,0]]
>>> min(adjoining)
[1, 0]





share|improve this answer

















  • 1




    @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
    – jpp
    Nov 10 at 18:15








  • 1




    @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
    – Sigurd Setså
    Nov 10 at 18:24


















up vote
0
down vote













You can do this:



minimum = min(adjoining, key=lambda elem: (elem[0], elem[1]))


Result:



[1, 0]


Use the key parameter to define the fields which will affect the sorting process. First, you will get the minimum element based on x value and if there are many of them, they will be sorted again based on their y value.



An alternative is to use the itemgetter function from operator module:



import operator

adjoining = [[1, 0], [3, 2], [1, 1]]

minimum = min(adjoining, key=operator.itemgetter(0,1))





share|improve this answer






























    up vote
    0
    down vote













    adjoining.sort(key= lambda x:x[0])
    mins = [i for i in adjoining if i[0] == adjoining[0][0]]
    if len(mins)>1:
    mins.sort(key= lambda x:x[1])
    min = [i for i in mins if i[1] == mins[0][1]]
    else:
    min = mins
    answer = min[0]


    I used sort with the key attribute. This allows you to define the criteria by which to sort the list.
    The rest of the code is base on list comprehension.



    [ item for item in a list_of_items if item == wanted_item]


    This filters list_of_item based of some chosen criteria. Just need to make sure what follows if can be evaluated True or False.






    share|improve this answer























    • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
      – hellow
      Nov 11 at 7:21











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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Just use min() like so:



    >>> adjoining = [[3,2],[1,1],[1,0]]
    >>> min(adjoining)
    [1, 0]





    share|improve this answer

















    • 1




      @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
      – jpp
      Nov 10 at 18:15








    • 1




      @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
      – Sigurd Setså
      Nov 10 at 18:24















    up vote
    0
    down vote













    Just use min() like so:



    >>> adjoining = [[3,2],[1,1],[1,0]]
    >>> min(adjoining)
    [1, 0]





    share|improve this answer

















    • 1




      @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
      – jpp
      Nov 10 at 18:15








    • 1




      @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
      – Sigurd Setså
      Nov 10 at 18:24













    up vote
    0
    down vote










    up vote
    0
    down vote









    Just use min() like so:



    >>> adjoining = [[3,2],[1,1],[1,0]]
    >>> min(adjoining)
    [1, 0]





    share|improve this answer












    Just use min() like so:



    >>> adjoining = [[3,2],[1,1],[1,0]]
    >>> min(adjoining)
    [1, 0]






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 10 at 17:34









    Red Cricket

    3,90983381




    3,90983381








    • 1




      @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
      – jpp
      Nov 10 at 18:15








    • 1




      @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
      – Sigurd Setså
      Nov 10 at 18:24














    • 1




      @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
      – jpp
      Nov 10 at 18:15








    • 1




      @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
      – Sigurd Setså
      Nov 10 at 18:24








    1




    1




    @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
    – jpp
    Nov 10 at 18:15






    @SigurdSetså, Can you explain your logic more clearly as an edit to your question. Your question seems to imply [0, 1] comes before [1, 0], i.e. My function should return the value with the lowest x coordinate. Concrete examples (rather than descriptions) often help.
    – jpp
    Nov 10 at 18:15






    1




    1




    @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
    – Sigurd Setså
    Nov 10 at 18:24




    @jpp I realised that my comment got it backwards. [0, 1] would be correct. I meant to say it the other way
    – Sigurd Setså
    Nov 10 at 18:24












    up vote
    0
    down vote













    You can do this:



    minimum = min(adjoining, key=lambda elem: (elem[0], elem[1]))


    Result:



    [1, 0]


    Use the key parameter to define the fields which will affect the sorting process. First, you will get the minimum element based on x value and if there are many of them, they will be sorted again based on their y value.



    An alternative is to use the itemgetter function from operator module:



    import operator

    adjoining = [[1, 0], [3, 2], [1, 1]]

    minimum = min(adjoining, key=operator.itemgetter(0,1))





    share|improve this answer



























      up vote
      0
      down vote













      You can do this:



      minimum = min(adjoining, key=lambda elem: (elem[0], elem[1]))


      Result:



      [1, 0]


      Use the key parameter to define the fields which will affect the sorting process. First, you will get the minimum element based on x value and if there are many of them, they will be sorted again based on their y value.



      An alternative is to use the itemgetter function from operator module:



      import operator

      adjoining = [[1, 0], [3, 2], [1, 1]]

      minimum = min(adjoining, key=operator.itemgetter(0,1))





      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        You can do this:



        minimum = min(adjoining, key=lambda elem: (elem[0], elem[1]))


        Result:



        [1, 0]


        Use the key parameter to define the fields which will affect the sorting process. First, you will get the minimum element based on x value and if there are many of them, they will be sorted again based on their y value.



        An alternative is to use the itemgetter function from operator module:



        import operator

        adjoining = [[1, 0], [3, 2], [1, 1]]

        minimum = min(adjoining, key=operator.itemgetter(0,1))





        share|improve this answer














        You can do this:



        minimum = min(adjoining, key=lambda elem: (elem[0], elem[1]))


        Result:



        [1, 0]


        Use the key parameter to define the fields which will affect the sorting process. First, you will get the minimum element based on x value and if there are many of them, they will be sorted again based on their y value.



        An alternative is to use the itemgetter function from operator module:



        import operator

        adjoining = [[1, 0], [3, 2], [1, 1]]

        minimum = min(adjoining, key=operator.itemgetter(0,1))






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 10 at 17:37

























        answered Nov 10 at 17:32









        Vasilis G.

        2,6042621




        2,6042621






















            up vote
            0
            down vote













            adjoining.sort(key= lambda x:x[0])
            mins = [i for i in adjoining if i[0] == adjoining[0][0]]
            if len(mins)>1:
            mins.sort(key= lambda x:x[1])
            min = [i for i in mins if i[1] == mins[0][1]]
            else:
            min = mins
            answer = min[0]


            I used sort with the key attribute. This allows you to define the criteria by which to sort the list.
            The rest of the code is base on list comprehension.



            [ item for item in a list_of_items if item == wanted_item]


            This filters list_of_item based of some chosen criteria. Just need to make sure what follows if can be evaluated True or False.






            share|improve this answer























            • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
              – hellow
              Nov 11 at 7:21















            up vote
            0
            down vote













            adjoining.sort(key= lambda x:x[0])
            mins = [i for i in adjoining if i[0] == adjoining[0][0]]
            if len(mins)>1:
            mins.sort(key= lambda x:x[1])
            min = [i for i in mins if i[1] == mins[0][1]]
            else:
            min = mins
            answer = min[0]


            I used sort with the key attribute. This allows you to define the criteria by which to sort the list.
            The rest of the code is base on list comprehension.



            [ item for item in a list_of_items if item == wanted_item]


            This filters list_of_item based of some chosen criteria. Just need to make sure what follows if can be evaluated True or False.






            share|improve this answer























            • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
              – hellow
              Nov 11 at 7:21













            up vote
            0
            down vote










            up vote
            0
            down vote









            adjoining.sort(key= lambda x:x[0])
            mins = [i for i in adjoining if i[0] == adjoining[0][0]]
            if len(mins)>1:
            mins.sort(key= lambda x:x[1])
            min = [i for i in mins if i[1] == mins[0][1]]
            else:
            min = mins
            answer = min[0]


            I used sort with the key attribute. This allows you to define the criteria by which to sort the list.
            The rest of the code is base on list comprehension.



            [ item for item in a list_of_items if item == wanted_item]


            This filters list_of_item based of some chosen criteria. Just need to make sure what follows if can be evaluated True or False.






            share|improve this answer














            adjoining.sort(key= lambda x:x[0])
            mins = [i for i in adjoining if i[0] == adjoining[0][0]]
            if len(mins)>1:
            mins.sort(key= lambda x:x[1])
            min = [i for i in mins if i[1] == mins[0][1]]
            else:
            min = mins
            answer = min[0]


            I used sort with the key attribute. This allows you to define the criteria by which to sort the list.
            The rest of the code is base on list comprehension.



            [ item for item in a list_of_items if item == wanted_item]


            This filters list_of_item based of some chosen criteria. Just need to make sure what follows if can be evaluated True or False.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 11 at 15:25

























            answered Nov 11 at 1:29









            qwerty asdf

            92




            92












            • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
              – hellow
              Nov 11 at 7:21


















            • While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
              – hellow
              Nov 11 at 7:21
















            While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
            – hellow
            Nov 11 at 7:21




            While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.
            – hellow
            Nov 11 at 7:21


















             

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