XSLT get value of attributes
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
This is my input XML:
<?xml version="1.0" encoding="utf-8"?>
<Q Sequence="21" xsi:noNamespaceSchemaLocation="xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Response>
<Message ID="507"></Message>
</Response>
</Q>
And this is the output I am trying to get from the XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<C>
<Response>
<ID>507</ID>
<Sequence>21</Sequence>
</Response>
</C>
My XSLT does not produce the expected outcome:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="/Message/@ID" />
</Id>
</Response>
</C>
</xsl:template>
</xsl:stylesheet>
This is far from what I'm trying to achieve but is this a better way to do this? This doesn't currently put the Id into the node. How can this be done?
xml xslt
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
add a comment |
0
This is my input XML:
<?xml version="1.0" encoding="utf-8"?>
<Q Sequence="21" xsi:noNamespaceSchemaLocation="xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Response>
<Message ID="507"></Message>
</Response>
</Q>
And this is the output I am trying to get from the XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<C>
<Response>
<ID>507</ID>
<Sequence>21</Sequence>
</Response>
</C>
My XSLT does not produce the expected outcome:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="/Message/@ID" />
</Id>
</Response>
</C>
</xsl:template>
</xsl:stylesheet>
This is far from what I'm trying to achieve but is this a better way to do this? This doesn't currently put the Id into the node. How can this be done?
xml xslt
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
add a comment |
0
0
0
This is my input XML:
<?xml version="1.0" encoding="utf-8"?>
<Q Sequence="21" xsi:noNamespaceSchemaLocation="xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Response>
<Message ID="507"></Message>
</Response>
</Q>
And this is the output I am trying to get from the XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<C>
<Response>
<ID>507</ID>
<Sequence>21</Sequence>
</Response>
</C>
My XSLT does not produce the expected outcome:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="/Message/@ID" />
</Id>
</Response>
</C>
</xsl:template>
</xsl:stylesheet>
This is far from what I'm trying to achieve but is this a better way to do this? This doesn't currently put the Id into the node. How can this be done?
xml xslt
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
This is my input XML:
<?xml version="1.0" encoding="utf-8"?>
<Q Sequence="21" xsi:noNamespaceSchemaLocation="xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Response>
<Message ID="507"></Message>
</Response>
</Q>
And this is the output I am trying to get from the XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<C>
<Response>
<ID>507</ID>
<Sequence>21</Sequence>
</Response>
</C>
My XSLT does not produce the expected outcome:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="/Message/@ID" />
</Id>
</Response>
</C>
</xsl:template>
</xsl:stylesheet>
This is far from what I'm trying to achieve but is this a better way to do this? This doesn't currently put the Id into the node. How can this be done?
xml xslt
xml xslt
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
asked Nov 16 '18 at 15:47
user3266638user3266638
14013
14013
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
Try it this way:
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="Response/Message/@ID" />
</Id>
<Sequence>
<xsl:value-of select="@Sequence" />
</Sequence>
</Response>
</C>
</xsl:template>
Note: A path that starts with / is an absolute path, starting at the root node.
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53341181%2fxslt-get-value-of-attributes%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Try it this way:
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="Response/Message/@ID" />
</Id>
<Sequence>
<xsl:value-of select="@Sequence" />
</Sequence>
</Response>
</C>
</xsl:template>
Note: A path that starts with / is an absolute path, starting at the root node.
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
add a comment |
1
Try it this way:
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="Response/Message/@ID" />
</Id>
<Sequence>
<xsl:value-of select="@Sequence" />
</Sequence>
</Response>
</C>
</xsl:template>
Note: A path that starts with / is an absolute path, starting at the root node.
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
add a comment |
1
1
1
Try it this way:
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="Response/Message/@ID" />
</Id>
<Sequence>
<xsl:value-of select="@Sequence" />
</Sequence>
</Response>
</C>
</xsl:template>
Note: A path that starts with / is an absolute path, starting at the root node.
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
Try it this way:
<xsl:template match="/Q">
<C>
<Response>
<Id>
<xsl:value-of select="Response/Message/@ID" />
</Id>
<Sequence>
<xsl:value-of select="@Sequence" />
</Sequence>
</Response>
</C>
</xsl:template>
Note: A path that starts with / is an absolute path, starting at the root node.
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
answered Nov 16 '18 at 16:13
michael.hor257kmichael.hor257k
77.1k42338
77.1k42338
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53341181%2fxslt-get-value-of-attributes%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
