How to stack (None,1024) tensor into (None,7,7,1024) tensor in keras?
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I have a tensor A
of shape (None,1024)
and I want to repeat it 49 times to make a matrix tensor of shape (None,7,7,1024)
. Every (,1024)
vector is a copy of the tensor A
.
How do I do this?
I tried
A = K.stack([A,A,A,A,A,A,A])
A = K.stack([A,A,A,A,A,A,A])
But this gives me a tensor of shape (7, 7, None, 1024)
python tensorflow keras tensor
add a comment |
I have a tensor A
of shape (None,1024)
and I want to repeat it 49 times to make a matrix tensor of shape (None,7,7,1024)
. Every (,1024)
vector is a copy of the tensor A
.
How do I do this?
I tried
A = K.stack([A,A,A,A,A,A,A])
A = K.stack([A,A,A,A,A,A,A])
But this gives me a tensor of shape (7, 7, None, 1024)
python tensorflow keras tensor
add a comment |
I have a tensor A
of shape (None,1024)
and I want to repeat it 49 times to make a matrix tensor of shape (None,7,7,1024)
. Every (,1024)
vector is a copy of the tensor A
.
How do I do this?
I tried
A = K.stack([A,A,A,A,A,A,A])
A = K.stack([A,A,A,A,A,A,A])
But this gives me a tensor of shape (7, 7, None, 1024)
python tensorflow keras tensor
I have a tensor A
of shape (None,1024)
and I want to repeat it 49 times to make a matrix tensor of shape (None,7,7,1024)
. Every (,1024)
vector is a copy of the tensor A
.
How do I do this?
I tried
A = K.stack([A,A,A,A,A,A,A])
A = K.stack([A,A,A,A,A,A,A])
But this gives me a tensor of shape (7, 7, None, 1024)
python tensorflow keras tensor
python tensorflow keras tensor
asked Nov 16 '18 at 12:24
Nirvan AnjirbagNirvan Anjirbag
3901418
3901418
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1 Answer
1
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oldest
votes
First use RepeatVector
layer to repeat it for 49 times, then use Reshape
layer to reshape it as desired:
r_A = RepeatVector(49)(A)
rsh_A = Reshape((7, 7, -1))(r_A)
Alternatively, you can define a function based on backend functions and wrap it inside a Lambda
layer:
from keras import backend as K
def rsh(x):
y = K.repeat(x, 49)
return K.reshape(y, (-1, 7, 7, K.int_shape(y)[-1]))
rsh_A = Lambda(rsh)(A)
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
First use RepeatVector
layer to repeat it for 49 times, then use Reshape
layer to reshape it as desired:
r_A = RepeatVector(49)(A)
rsh_A = Reshape((7, 7, -1))(r_A)
Alternatively, you can define a function based on backend functions and wrap it inside a Lambda
layer:
from keras import backend as K
def rsh(x):
y = K.repeat(x, 49)
return K.reshape(y, (-1, 7, 7, K.int_shape(y)[-1]))
rsh_A = Lambda(rsh)(A)
add a comment |
First use RepeatVector
layer to repeat it for 49 times, then use Reshape
layer to reshape it as desired:
r_A = RepeatVector(49)(A)
rsh_A = Reshape((7, 7, -1))(r_A)
Alternatively, you can define a function based on backend functions and wrap it inside a Lambda
layer:
from keras import backend as K
def rsh(x):
y = K.repeat(x, 49)
return K.reshape(y, (-1, 7, 7, K.int_shape(y)[-1]))
rsh_A = Lambda(rsh)(A)
add a comment |
First use RepeatVector
layer to repeat it for 49 times, then use Reshape
layer to reshape it as desired:
r_A = RepeatVector(49)(A)
rsh_A = Reshape((7, 7, -1))(r_A)
Alternatively, you can define a function based on backend functions and wrap it inside a Lambda
layer:
from keras import backend as K
def rsh(x):
y = K.repeat(x, 49)
return K.reshape(y, (-1, 7, 7, K.int_shape(y)[-1]))
rsh_A = Lambda(rsh)(A)
First use RepeatVector
layer to repeat it for 49 times, then use Reshape
layer to reshape it as desired:
r_A = RepeatVector(49)(A)
rsh_A = Reshape((7, 7, -1))(r_A)
Alternatively, you can define a function based on backend functions and wrap it inside a Lambda
layer:
from keras import backend as K
def rsh(x):
y = K.repeat(x, 49)
return K.reshape(y, (-1, 7, 7, K.int_shape(y)[-1]))
rsh_A = Lambda(rsh)(A)
edited Nov 16 '18 at 12:57
answered Nov 16 '18 at 12:39
todaytoday
11.7k22441
11.7k22441
add a comment |
add a comment |
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