scipy.optimize.curve_fit raises RuntimeWarning
I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
return A*(e+x)**0.0395
strain = np.linspace(0,15,3000) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
However, I constantly get this warning after running the code:
RuntimeWarning: invalid value encountered in power
return A*(e+x)**0.0395
I was wondering why this happens and how should improve the code?
python scipy curve-fitting data-fitting
add a comment |
I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
return A*(e+x)**0.0395
strain = np.linspace(0,15,3000) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
However, I constantly get this warning after running the code:
RuntimeWarning: invalid value encountered in power
return A*(e+x)**0.0395
I was wondering why this happens and how should improve the code?
python scipy curve-fitting data-fitting
add a comment |
I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
return A*(e+x)**0.0395
strain = np.linspace(0,15,3000) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
However, I constantly get this warning after running the code:
RuntimeWarning: invalid value encountered in power
return A*(e+x)**0.0395
I was wondering why this happens and how should improve the code?
python scipy curve-fitting data-fitting
I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
return A*(e+x)**0.0395
strain = np.linspace(0,15,3000) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
However, I constantly get this warning after running the code:
RuntimeWarning: invalid value encountered in power
return A*(e+x)**0.0395
I was wondering why this happens and how should improve the code?
python scipy curve-fitting data-fitting
python scipy curve-fitting data-fitting
asked Nov 16 '18 at 0:59
TomTom
8217
8217
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1 Answer
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I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
return 1.0E10 # large value gives large error, the "brick wall"
return A*(e+x)**0.0395
strain = np.linspace(0,0.1,3) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
return 1.0E10 # large value gives large error, the "brick wall"
return A*(e+x)**0.0395
strain = np.linspace(0,0.1,3) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
add a comment |
I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
return 1.0E10 # large value gives large error, the "brick wall"
return A*(e+x)**0.0395
strain = np.linspace(0,0.1,3) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
add a comment |
I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
return 1.0E10 # large value gives large error, the "brick wall"
return A*(e+x)**0.0395
strain = np.linspace(0,0.1,3) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:
import numpy as np
from scipy.optimize import curve_fit
def func(x,e,A):
if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
return 1.0E10 # large value gives large error, the "brick wall"
return A*(e+x)**0.0395
strain = np.linspace(0,0.1,3) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)
answered Nov 16 '18 at 2:50
James PhillipsJames Phillips
1,775388
1,775388
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