scipy.optimize.curve_fit raises RuntimeWarning












1















I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.



import numpy as np
from scipy.optimize import curve_fit

def func(x,e,A):
return A*(e+x)**0.0395

strain = np.linspace(0,15,3000) # variable
e = 0.773
A = 386.5
n0 = 0.395
y = A*(e+strain)**n0 # target to minimize
popt, pcov = curve_fit(func, strain, y)


However, I constantly get this warning after running the code:



RuntimeWarning: invalid value encountered in power
return A*(e+x)**0.0395


I was wondering why this happens and how should improve the code?










share|improve this question



























    1















    I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.



    import numpy as np
    from scipy.optimize import curve_fit

    def func(x,e,A):
    return A*(e+x)**0.0395

    strain = np.linspace(0,15,3000) # variable
    e = 0.773
    A = 386.5
    n0 = 0.395
    y = A*(e+strain)**n0 # target to minimize
    popt, pcov = curve_fit(func, strain, y)


    However, I constantly get this warning after running the code:



    RuntimeWarning: invalid value encountered in power
    return A*(e+x)**0.0395


    I was wondering why this happens and how should improve the code?










    share|improve this question

























      1












      1








      1








      I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.



      import numpy as np
      from scipy.optimize import curve_fit

      def func(x,e,A):
      return A*(e+x)**0.0395

      strain = np.linspace(0,15,3000) # variable
      e = 0.773
      A = 386.5
      n0 = 0.395
      y = A*(e+strain)**n0 # target to minimize
      popt, pcov = curve_fit(func, strain, y)


      However, I constantly get this warning after running the code:



      RuntimeWarning: invalid value encountered in power
      return A*(e+x)**0.0395


      I was wondering why this happens and how should improve the code?










      share|improve this question














      I am trying to fit a curve by changing two parameters (e and A). The target curve is plotted by assigning n0=0.395, but its actual value is 0.0395. So I am hoping to achieve the same curve by changing e and A.



      import numpy as np
      from scipy.optimize import curve_fit

      def func(x,e,A):
      return A*(e+x)**0.0395

      strain = np.linspace(0,15,3000) # variable
      e = 0.773
      A = 386.5
      n0 = 0.395
      y = A*(e+strain)**n0 # target to minimize
      popt, pcov = curve_fit(func, strain, y)


      However, I constantly get this warning after running the code:



      RuntimeWarning: invalid value encountered in power
      return A*(e+x)**0.0395


      I was wondering why this happens and how should improve the code?







      python scipy curve-fitting data-fitting






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 16 '18 at 0:59









      TomTom

      8217




      8217
























          1 Answer
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          oldest

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          1














          I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:



          import numpy as np
          from scipy.optimize import curve_fit

          def func(x,e,A):
          if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
          return 1.0E10 # large value gives large error, the "brick wall"
          return A*(e+x)**0.0395

          strain = np.linspace(0,0.1,3) # variable
          e = 0.773
          A = 386.5
          n0 = 0.395
          y = A*(e+strain)**n0 # target to minimize
          popt, pcov = curve_fit(func, strain, y)





          share|improve this answer























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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:



            import numpy as np
            from scipy.optimize import curve_fit

            def func(x,e,A):
            if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
            return 1.0E10 # large value gives large error, the "brick wall"
            return A*(e+x)**0.0395

            strain = np.linspace(0,0.1,3) # variable
            e = 0.773
            A = 386.5
            n0 = 0.395
            y = A*(e+strain)**n0 # target to minimize
            popt, pcov = curve_fit(func, strain, y)





            share|improve this answer




























              1














              I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:



              import numpy as np
              from scipy.optimize import curve_fit

              def func(x,e,A):
              if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
              return 1.0E10 # large value gives large error, the "brick wall"
              return A*(e+x)**0.0395

              strain = np.linspace(0,0.1,3) # variable
              e = 0.773
              A = 386.5
              n0 = 0.395
              y = A*(e+strain)**n0 # target to minimize
              popt, pcov = curve_fit(func, strain, y)





              share|improve this answer


























                1












                1








                1







                I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:



                import numpy as np
                from scipy.optimize import curve_fit

                def func(x,e,A):
                if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
                return 1.0E10 # large value gives large error, the "brick wall"
                return A*(e+x)**0.0395

                strain = np.linspace(0,0.1,3) # variable
                e = 0.773
                A = 386.5
                n0 = 0.395
                y = A*(e+strain)**n0 # target to minimize
                popt, pcov = curve_fit(func, strain, y)





                share|improve this answer













                I found a solution that I do not like, but it does eliminate the warning. I found that, strangely to me, "e" was being made negative within curve_fit(). I added a "brick wall" inside the function to stop this, but it should be unnecessary. My code is:



                import numpy as np
                from scipy.optimize import curve_fit

                def func(x,e,A):
                if e < 0.0: # curve_fit() hits a "brick wall" if e is negative
                return 1.0E10 # large value gives large error, the "brick wall"
                return A*(e+x)**0.0395

                strain = np.linspace(0,0.1,3) # variable
                e = 0.773
                A = 386.5
                n0 = 0.395
                y = A*(e+strain)**n0 # target to minimize
                popt, pcov = curve_fit(func, strain, y)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 16 '18 at 2:50









                James PhillipsJames Phillips

                1,775388




                1,775388
































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