Replace columns separated by string with id from another table - SQL Server












-1















I have following 2 tables in SQL Server



Category table:



Category
--------------------------
Delivery;Gauges;Book;Table


Category id:



id      name
-----------------
13183 Delivery
88781 Gauges
88782 Book
12512 Table


Intended result is to have category table replaced with category id, as:



Category
-----------------------
13183;88781;88782;12512


I approached this by first separating category columns into separate columns using :



ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))


and so on. Then used left join and replace on each new column. Isn't there an easier way to do this? I searched on the net and stackoverflow but can't seem to find anything similar.










share|improve this question

























  • Possible duplicate of How to make a query with group_concat in sql server

    – scsimon
    Nov 14 '18 at 1:02






  • 2





    Fix your data! Don't store lists in strings!

    – Gordon Linoff
    Nov 14 '18 at 4:30
















-1















I have following 2 tables in SQL Server



Category table:



Category
--------------------------
Delivery;Gauges;Book;Table


Category id:



id      name
-----------------
13183 Delivery
88781 Gauges
88782 Book
12512 Table


Intended result is to have category table replaced with category id, as:



Category
-----------------------
13183;88781;88782;12512


I approached this by first separating category columns into separate columns using :



ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))


and so on. Then used left join and replace on each new column. Isn't there an easier way to do this? I searched on the net and stackoverflow but can't seem to find anything similar.










share|improve this question

























  • Possible duplicate of How to make a query with group_concat in sql server

    – scsimon
    Nov 14 '18 at 1:02






  • 2





    Fix your data! Don't store lists in strings!

    – Gordon Linoff
    Nov 14 '18 at 4:30














-1












-1








-1








I have following 2 tables in SQL Server



Category table:



Category
--------------------------
Delivery;Gauges;Book;Table


Category id:



id      name
-----------------
13183 Delivery
88781 Gauges
88782 Book
12512 Table


Intended result is to have category table replaced with category id, as:



Category
-----------------------
13183;88781;88782;12512


I approached this by first separating category columns into separate columns using :



ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))


and so on. Then used left join and replace on each new column. Isn't there an easier way to do this? I searched on the net and stackoverflow but can't seem to find anything similar.










share|improve this question
















I have following 2 tables in SQL Server



Category table:



Category
--------------------------
Delivery;Gauges;Book;Table


Category id:



id      name
-----------------
13183 Delivery
88781 Gauges
88782 Book
12512 Table


Intended result is to have category table replaced with category id, as:



Category
-----------------------
13183;88781;88782;12512


I approached this by first separating category columns into separate columns using :



ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))


and so on. Then used left join and replace on each new column. Isn't there an easier way to do this? I searched on the net and stackoverflow but can't seem to find anything similar.







sql sql-server replace






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 5:50









marc_s

575k12811101257




575k12811101257










asked Nov 13 '18 at 23:31









SimranSimran

254




254













  • Possible duplicate of How to make a query with group_concat in sql server

    – scsimon
    Nov 14 '18 at 1:02






  • 2





    Fix your data! Don't store lists in strings!

    – Gordon Linoff
    Nov 14 '18 at 4:30



















  • Possible duplicate of How to make a query with group_concat in sql server

    – scsimon
    Nov 14 '18 at 1:02






  • 2





    Fix your data! Don't store lists in strings!

    – Gordon Linoff
    Nov 14 '18 at 4:30

















Possible duplicate of How to make a query with group_concat in sql server

– scsimon
Nov 14 '18 at 1:02





Possible duplicate of How to make a query with group_concat in sql server

– scsimon
Nov 14 '18 at 1:02




2




2





Fix your data! Don't store lists in strings!

– Gordon Linoff
Nov 14 '18 at 4:30





Fix your data! Don't store lists in strings!

– Gordon Linoff
Nov 14 '18 at 4:30












1 Answer
1






active

oldest

votes


















0














You can try to make a function to split your string value by a character.



CREATE FUNCTION Split_fun 
( @Words nvarchar(MAX)
, @splitStr varchar(50)
)
RETURNS @Result_Table TABLE
(
[word] nvarchar(max) NULL
)
BEGIN
Declare @TempStr nvarchar(MAX)

WHILE (CHARINDEX(@splitStr,@Words)>0)
BEGIN
Set @TempStr=SUBSTRING(@Words,1,CHARINDEX(@splitStr,@Words)-1)
Insert into @Result_Table (word) Values (@TempStr)

Set @Words = REPLACE(@Words,@TempStr+@splitStr,'')
END/*End While*/

IF(LEN(RTRIM(LTRIM(@Words)))>0 And CHARINDEX(@splitStr,RTRIM(LTRIM(@Words)))=0)
Begin
Set @TempStr=@Words

Insert into @Result_Table (word) Values (@TempStr)

End

RETURN
END



  • you can use this function to make a result set by ';'.


  • do self-join with Category id table.



final you can use FOR XML connect all string by ; to get your expectation result.



;with cte as (
SELECT id
FROM T CROSS APPLY Split_fun(Category,';') v
JOIN T1 on v.word = t1.Category
)
select STUFF((
select distinct ';'+ cast(id as varchar(10))
FROM cte
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')


sqlfiddle






share|improve this answer

























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53291024%2freplace-columns-separated-by-string-with-id-from-another-table-sql-server%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You can try to make a function to split your string value by a character.



    CREATE FUNCTION Split_fun 
    ( @Words nvarchar(MAX)
    , @splitStr varchar(50)
    )
    RETURNS @Result_Table TABLE
    (
    [word] nvarchar(max) NULL
    )
    BEGIN
    Declare @TempStr nvarchar(MAX)

    WHILE (CHARINDEX(@splitStr,@Words)>0)
    BEGIN
    Set @TempStr=SUBSTRING(@Words,1,CHARINDEX(@splitStr,@Words)-1)
    Insert into @Result_Table (word) Values (@TempStr)

    Set @Words = REPLACE(@Words,@TempStr+@splitStr,'')
    END/*End While*/

    IF(LEN(RTRIM(LTRIM(@Words)))>0 And CHARINDEX(@splitStr,RTRIM(LTRIM(@Words)))=0)
    Begin
    Set @TempStr=@Words

    Insert into @Result_Table (word) Values (@TempStr)

    End

    RETURN
    END



    • you can use this function to make a result set by ';'.


    • do self-join with Category id table.



    final you can use FOR XML connect all string by ; to get your expectation result.



    ;with cte as (
    SELECT id
    FROM T CROSS APPLY Split_fun(Category,';') v
    JOIN T1 on v.word = t1.Category
    )
    select STUFF((
    select distinct ';'+ cast(id as varchar(10))
    FROM cte
    FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')


    sqlfiddle






    share|improve this answer






























      0














      You can try to make a function to split your string value by a character.



      CREATE FUNCTION Split_fun 
      ( @Words nvarchar(MAX)
      , @splitStr varchar(50)
      )
      RETURNS @Result_Table TABLE
      (
      [word] nvarchar(max) NULL
      )
      BEGIN
      Declare @TempStr nvarchar(MAX)

      WHILE (CHARINDEX(@splitStr,@Words)>0)
      BEGIN
      Set @TempStr=SUBSTRING(@Words,1,CHARINDEX(@splitStr,@Words)-1)
      Insert into @Result_Table (word) Values (@TempStr)

      Set @Words = REPLACE(@Words,@TempStr+@splitStr,'')
      END/*End While*/

      IF(LEN(RTRIM(LTRIM(@Words)))>0 And CHARINDEX(@splitStr,RTRIM(LTRIM(@Words)))=0)
      Begin
      Set @TempStr=@Words

      Insert into @Result_Table (word) Values (@TempStr)

      End

      RETURN
      END



      • you can use this function to make a result set by ';'.


      • do self-join with Category id table.



      final you can use FOR XML connect all string by ; to get your expectation result.



      ;with cte as (
      SELECT id
      FROM T CROSS APPLY Split_fun(Category,';') v
      JOIN T1 on v.word = t1.Category
      )
      select STUFF((
      select distinct ';'+ cast(id as varchar(10))
      FROM cte
      FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')


      sqlfiddle






      share|improve this answer




























        0












        0








        0







        You can try to make a function to split your string value by a character.



        CREATE FUNCTION Split_fun 
        ( @Words nvarchar(MAX)
        , @splitStr varchar(50)
        )
        RETURNS @Result_Table TABLE
        (
        [word] nvarchar(max) NULL
        )
        BEGIN
        Declare @TempStr nvarchar(MAX)

        WHILE (CHARINDEX(@splitStr,@Words)>0)
        BEGIN
        Set @TempStr=SUBSTRING(@Words,1,CHARINDEX(@splitStr,@Words)-1)
        Insert into @Result_Table (word) Values (@TempStr)

        Set @Words = REPLACE(@Words,@TempStr+@splitStr,'')
        END/*End While*/

        IF(LEN(RTRIM(LTRIM(@Words)))>0 And CHARINDEX(@splitStr,RTRIM(LTRIM(@Words)))=0)
        Begin
        Set @TempStr=@Words

        Insert into @Result_Table (word) Values (@TempStr)

        End

        RETURN
        END



        • you can use this function to make a result set by ';'.


        • do self-join with Category id table.



        final you can use FOR XML connect all string by ; to get your expectation result.



        ;with cte as (
        SELECT id
        FROM T CROSS APPLY Split_fun(Category,';') v
        JOIN T1 on v.word = t1.Category
        )
        select STUFF((
        select distinct ';'+ cast(id as varchar(10))
        FROM cte
        FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')


        sqlfiddle






        share|improve this answer















        You can try to make a function to split your string value by a character.



        CREATE FUNCTION Split_fun 
        ( @Words nvarchar(MAX)
        , @splitStr varchar(50)
        )
        RETURNS @Result_Table TABLE
        (
        [word] nvarchar(max) NULL
        )
        BEGIN
        Declare @TempStr nvarchar(MAX)

        WHILE (CHARINDEX(@splitStr,@Words)>0)
        BEGIN
        Set @TempStr=SUBSTRING(@Words,1,CHARINDEX(@splitStr,@Words)-1)
        Insert into @Result_Table (word) Values (@TempStr)

        Set @Words = REPLACE(@Words,@TempStr+@splitStr,'')
        END/*End While*/

        IF(LEN(RTRIM(LTRIM(@Words)))>0 And CHARINDEX(@splitStr,RTRIM(LTRIM(@Words)))=0)
        Begin
        Set @TempStr=@Words

        Insert into @Result_Table (word) Values (@TempStr)

        End

        RETURN
        END



        • you can use this function to make a result set by ';'.


        • do self-join with Category id table.



        final you can use FOR XML connect all string by ; to get your expectation result.



        ;with cte as (
        SELECT id
        FROM T CROSS APPLY Split_fun(Category,';') v
        JOIN T1 on v.word = t1.Category
        )
        select STUFF((
        select distinct ';'+ cast(id as varchar(10))
        FROM cte
        FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')


        sqlfiddle







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 14 '18 at 1:54

























        answered Nov 14 '18 at 1:49









        D-ShihD-Shih

        25.8k61531




        25.8k61531






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53291024%2freplace-columns-separated-by-string-with-id-from-another-table-sql-server%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Florida Star v. B. J. F.

            Danny Elfman

            Retrieve a Users Dashboard in Tumblr with R and TumblR. Oauth Issues