Angular 6 *ngFor display different styles for first, odd, even and last












1















I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="{'background-color':getColor(i)}" style="color: white;">
<strong>Index : </strong>{{i}} <strong>ID : </strong>{{course.id}} <strong>Name</strong> : {{course.name}}
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import { Component } from '@angular/core';

@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
})


export class AppComponent {
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = {id: null, name: null};
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event) {
if ($event.keyCode != 13) {
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
}
}

onAdd() {

if (!this.fields.id || !this.fields.name) {
this.noValues = true;
} else {
this.courses.push({id: this.fields.id, name: this.fields.name});
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}
}

onRemove(i) {
this.courses.splice(i, 1);
}

onClear() {
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}

onModify(i) {
if (!this.fields.id || !this.fields.name) {
this.noModifyValues = true;
} else {
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;

}
}

getColor(i){
if (i % 2 === 0 && i != 0){i = 'odd';}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
}
return 'red';
}
}
interface Courses {
id: number;
name: string;
}


Image of the code in action for better understanding.










share|improve this question























  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

    – Eliseo
    Nov 13 '18 at 8:15
















1















I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="{'background-color':getColor(i)}" style="color: white;">
<strong>Index : </strong>{{i}} <strong>ID : </strong>{{course.id}} <strong>Name</strong> : {{course.name}}
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import { Component } from '@angular/core';

@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
})


export class AppComponent {
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = {id: null, name: null};
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event) {
if ($event.keyCode != 13) {
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
}
}

onAdd() {

if (!this.fields.id || !this.fields.name) {
this.noValues = true;
} else {
this.courses.push({id: this.fields.id, name: this.fields.name});
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}
}

onRemove(i) {
this.courses.splice(i, 1);
}

onClear() {
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}

onModify(i) {
if (!this.fields.id || !this.fields.name) {
this.noModifyValues = true;
} else {
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;

}
}

getColor(i){
if (i % 2 === 0 && i != 0){i = 'odd';}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
}
return 'red';
}
}
interface Courses {
id: number;
name: string;
}


Image of the code in action for better understanding.










share|improve this question























  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

    – Eliseo
    Nov 13 '18 at 8:15














1












1








1








I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="{'background-color':getColor(i)}" style="color: white;">
<strong>Index : </strong>{{i}} <strong>ID : </strong>{{course.id}} <strong>Name</strong> : {{course.name}}
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import { Component } from '@angular/core';

@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
})


export class AppComponent {
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = {id: null, name: null};
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event) {
if ($event.keyCode != 13) {
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
}
}

onAdd() {

if (!this.fields.id || !this.fields.name) {
this.noValues = true;
} else {
this.courses.push({id: this.fields.id, name: this.fields.name});
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}
}

onRemove(i) {
this.courses.splice(i, 1);
}

onClear() {
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}

onModify(i) {
if (!this.fields.id || !this.fields.name) {
this.noModifyValues = true;
} else {
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;

}
}

getColor(i){
if (i % 2 === 0 && i != 0){i = 'odd';}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
}
return 'red';
}
}
interface Courses {
id: number;
name: string;
}


Image of the code in action for better understanding.










share|improve this question














I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="{'background-color':getColor(i)}" style="color: white;">
<strong>Index : </strong>{{i}} <strong>ID : </strong>{{course.id}} <strong>Name</strong> : {{course.name}}
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import { Component } from '@angular/core';

@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
})


export class AppComponent {
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = {id: null, name: null};
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event) {
if ($event.keyCode != 13) {
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
}
}

onAdd() {

if (!this.fields.id || !this.fields.name) {
this.noValues = true;
} else {
this.courses.push({id: this.fields.id, name: this.fields.name});
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}
}

onRemove(i) {
this.courses.splice(i, 1);
}

onClear() {
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
}

onModify(i) {
if (!this.fields.id || !this.fields.name) {
this.noModifyValues = true;
} else {
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;

}
}

getColor(i){
if (i % 2 === 0 && i != 0){i = 'odd';}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
}
return 'red';
}
}
interface Courses {
id: number;
name: string;
}


Image of the code in action for better understanding.







arrays angular typescript angular6






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asked Nov 13 '18 at 3:01









Jean-Philippe DufourJean-Philippe Dufour

297




297













  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

    – Eliseo
    Nov 13 '18 at 8:15



















  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

    – Eliseo
    Nov 13 '18 at 8:15

















If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

– Eliseo
Nov 13 '18 at 8:15





If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer

– Eliseo
Nov 13 '18 at 8:15












4 Answers
4






active

oldest

votes


















1














Try something like this



getColor(i){
if (i % 2 === 0 && i != 0){i = 'odd';}
if (this.courses && (this.courses.length - 1 === i)) {i = 'last'}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
}
return 'red';
}


Hope it works - Happy coding !!






share|improve this answer
























  • You can use it as else if in case to avoid another condition :)

    – Rahul
    Nov 13 '18 at 3:45



















1














If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>





share|improve this answer
























  • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13













  • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

    – Eliseo
    Nov 16 '18 at 13:14











  • thanks for your input. I will defenitly look this up.

    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06



















0














Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







getColor(i){
if (this.courses && i != 0 && (this.courses.length - 1 === i)) {i = 'last'}
if (i % 2 === 0 && i != 0 && i != 'last'){i = 'odd';}
switch (i) {
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
}
return 'red';
}


Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






share|improve this answer































    0














    You could use if else ladder instead of mixing up if else and switch and assignments like given below



    getColor(i)
    {
    if(this.courses)
    {
    if(i==0)
    return "orange";
    else if(i==this.courses.length-1)
    return "purple";
    else if (i%2==0)
    return "red";
    else
    return "blue";
    }
    }





    share|improve this answer



















    • 1





      Would def make a cleaner and easier to understand code. Thanks for your input.

      – Jean-Philippe Dufour
      Nov 13 '18 at 5:38











    • When you have simpler alternatives, don't mix up and always welcome :)

      – Mithil Mohan
      Nov 13 '18 at 5:39











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    4 Answers
    4






    active

    oldest

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    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Try something like this



    getColor(i){
    if (i % 2 === 0 && i != 0){i = 'odd';}
    if (this.courses && (this.courses.length - 1 === i)) {i = 'last'}
    switch (i) {
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    }
    return 'red';
    }


    Hope it works - Happy coding !!






    share|improve this answer
























    • You can use it as else if in case to avoid another condition :)

      – Rahul
      Nov 13 '18 at 3:45
















    1














    Try something like this



    getColor(i){
    if (i % 2 === 0 && i != 0){i = 'odd';}
    if (this.courses && (this.courses.length - 1 === i)) {i = 'last'}
    switch (i) {
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    }
    return 'red';
    }


    Hope it works - Happy coding !!






    share|improve this answer
























    • You can use it as else if in case to avoid another condition :)

      – Rahul
      Nov 13 '18 at 3:45














    1












    1








    1







    Try something like this



    getColor(i){
    if (i % 2 === 0 && i != 0){i = 'odd';}
    if (this.courses && (this.courses.length - 1 === i)) {i = 'last'}
    switch (i) {
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    }
    return 'red';
    }


    Hope it works - Happy coding !!






    share|improve this answer













    Try something like this



    getColor(i){
    if (i % 2 === 0 && i != 0){i = 'odd';}
    if (this.courses && (this.courses.length - 1 === i)) {i = 'last'}
    switch (i) {
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    }
    return 'red';
    }


    Hope it works - Happy coding !!







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 3:31









    RahulRahul

    1,0331315




    1,0331315













    • You can use it as else if in case to avoid another condition :)

      – Rahul
      Nov 13 '18 at 3:45



















    • You can use it as else if in case to avoid another condition :)

      – Rahul
      Nov 13 '18 at 3:45

















    You can use it as else if in case to avoid another condition :)

    – Rahul
    Nov 13 '18 at 3:45





    You can use it as else if in case to avoid another condition :)

    – Rahul
    Nov 13 '18 at 3:45













    1














    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer
























    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13













    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

      – Eliseo
      Nov 16 '18 at 13:14











    • thanks for your input. I will defenitly look this up.

      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06
















    1














    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer
























    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13













    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

      – Eliseo
      Nov 16 '18 at 13:14











    • thanks for your input. I will defenitly look this up.

      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06














    1












    1








    1







    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer













    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 8:13









    EliseoEliseo

    5,5891312




    5,5891312













    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13













    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

      – Eliseo
      Nov 16 '18 at 13:14











    • thanks for your input. I will defenitly look this up.

      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06



















    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13













    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

      – Eliseo
      Nov 16 '18 at 13:14











    • thanks for your input. I will defenitly look this up.

      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06

















    That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13







    That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values

    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13















    If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

    – Eliseo
    Nov 16 '18 at 13:14





    If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance

    – Eliseo
    Nov 16 '18 at 13:14













    thanks for your input. I will defenitly look this up.

    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06





    thanks for your input. I will defenitly look this up.

    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06











    0














    Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







    getColor(i){
    if (this.courses && i != 0 && (this.courses.length - 1 === i)) {i = 'last'}
    if (i % 2 === 0 && i != 0 && i != 'last'){i = 'odd';}
    switch (i) {
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    case i = 'last' : return 'purple';
    }
    return 'red';
    }


    Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






    share|improve this answer




























      0














      Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







      getColor(i){
      if (this.courses && i != 0 && (this.courses.length - 1 === i)) {i = 'last'}
      if (i % 2 === 0 && i != 0 && i != 'last'){i = 'odd';}
      switch (i) {
      case i = 0 : return 'orange';
      case i = 'odd' : return 'blue';
      case i = 'last' : return 'purple';
      }
      return 'red';
      }


      Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






      share|improve this answer


























        0












        0








        0







        Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







        getColor(i){
        if (this.courses && i != 0 && (this.courses.length - 1 === i)) {i = 'last'}
        if (i % 2 === 0 && i != 0 && i != 'last'){i = 'odd';}
        switch (i) {
        case i = 0 : return 'orange';
        case i = 'odd' : return 'blue';
        case i = 'last' : return 'purple';
        }
        return 'red';
        }


        Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






        share|improve this answer













        Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







        getColor(i){
        if (this.courses && i != 0 && (this.courses.length - 1 === i)) {i = 'last'}
        if (i % 2 === 0 && i != 0 && i != 'last'){i = 'odd';}
        switch (i) {
        case i = 0 : return 'orange';
        case i = 'odd' : return 'blue';
        case i = 'last' : return 'purple';
        }
        return 'red';
        }


        Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 3:43









        Jean-Philippe DufourJean-Philippe Dufour

        297




        297























            0














            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)
            {
            if(this.courses)
            {
            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";
            }
            }





            share|improve this answer



















            • 1





              Would def make a cleaner and easier to understand code. Thanks for your input.

              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38











            • When you have simpler alternatives, don't mix up and always welcome :)

              – Mithil Mohan
              Nov 13 '18 at 5:39
















            0














            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)
            {
            if(this.courses)
            {
            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";
            }
            }





            share|improve this answer



















            • 1





              Would def make a cleaner and easier to understand code. Thanks for your input.

              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38











            • When you have simpler alternatives, don't mix up and always welcome :)

              – Mithil Mohan
              Nov 13 '18 at 5:39














            0












            0








            0







            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)
            {
            if(this.courses)
            {
            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";
            }
            }





            share|improve this answer













            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)
            {
            if(this.courses)
            {
            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";
            }
            }






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 13 '18 at 5:30









            Mithil MohanMithil Mohan

            1389




            1389








            • 1





              Would def make a cleaner and easier to understand code. Thanks for your input.

              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38











            • When you have simpler alternatives, don't mix up and always welcome :)

              – Mithil Mohan
              Nov 13 '18 at 5:39














            • 1





              Would def make a cleaner and easier to understand code. Thanks for your input.

              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38











            • When you have simpler alternatives, don't mix up and always welcome :)

              – Mithil Mohan
              Nov 13 '18 at 5:39








            1




            1





            Would def make a cleaner and easier to understand code. Thanks for your input.

            – Jean-Philippe Dufour
            Nov 13 '18 at 5:38





            Would def make a cleaner and easier to understand code. Thanks for your input.

            – Jean-Philippe Dufour
            Nov 13 '18 at 5:38













            When you have simpler alternatives, don't mix up and always welcome :)

            – Mithil Mohan
            Nov 13 '18 at 5:39





            When you have simpler alternatives, don't mix up and always welcome :)

            – Mithil Mohan
            Nov 13 '18 at 5:39


















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