Random URL Redirect On click
I want to redirect my links random every time they click on Hyper-link or button or Image on my website.
Example :
I have 3 URL : Google.com, Facebook.com, yahoo.com.
<a href="<?php $sites[array_rand($sites)] ?>">Visit here</a>
So whenever user click on visit here they will taking to random from anyone of the 3 URL. i have tried this code but not working as i want, it simply making a redirect.
$sites = array(
'http://www.google.com/',
'http://www.facebook.com/',
'http://www.yahoo.com/'
);
die();
Please help me in this. Provide me working JavaScript or PHP code.
javascript php jquery html ajax
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
add a comment |
I want to redirect my links random every time they click on Hyper-link or button or Image on my website.
Example :
I have 3 URL : Google.com, Facebook.com, yahoo.com.
<a href="<?php $sites[array_rand($sites)] ?>">Visit here</a>
So whenever user click on visit here they will taking to random from anyone of the 3 URL. i have tried this code but not working as i want, it simply making a redirect.
$sites = array(
'http://www.google.com/',
'http://www.facebook.com/',
'http://www.yahoo.com/'
);
die();
Please help me in this. Provide me working JavaScript or PHP code.
javascript php jquery html ajax
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
2
you're missing a semi-colon after$sites = array(...);
– Emissary
Nov 11 at 15:29
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38
add a comment |
I want to redirect my links random every time they click on Hyper-link or button or Image on my website.
Example :
I have 3 URL : Google.com, Facebook.com, yahoo.com.
<a href="<?php $sites[array_rand($sites)] ?>">Visit here</a>
So whenever user click on visit here they will taking to random from anyone of the 3 URL. i have tried this code but not working as i want, it simply making a redirect.
$sites = array(
'http://www.google.com/',
'http://www.facebook.com/',
'http://www.yahoo.com/'
);
die();
Please help me in this. Provide me working JavaScript or PHP code.
javascript php jquery html ajax
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
I want to redirect my links random every time they click on Hyper-link or button or Image on my website.
Example :
I have 3 URL : Google.com, Facebook.com, yahoo.com.
<a href="<?php $sites[array_rand($sites)] ?>">Visit here</a>
So whenever user click on visit here they will taking to random from anyone of the 3 URL. i have tried this code but not working as i want, it simply making a redirect.
$sites = array(
'http://www.google.com/',
'http://www.facebook.com/',
'http://www.yahoo.com/'
);
die();
Please help me in this. Provide me working JavaScript or PHP code.
javascript php jquery html ajax
javascript php jquery html ajax
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
edited Nov 12 at 6:56
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
asked Nov 11 at 15:21
Rajeev Ranjan Sharma
248
248
2
you're missing a semi-colon after$sites = array(...);
– Emissary
Nov 11 at 15:29
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38
add a comment |
2
you're missing a semi-colon after$sites = array(...);
– Emissary
Nov 11 at 15:29
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38
2
2
you're missing a semi-colon after
$sites = array(...);– Emissary
Nov 11 at 15:29
you're missing a semi-colon after
$sites = array(...);– Emissary
Nov 11 at 15:29
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38
add a comment |
2 Answers
2
active
oldest
votes
The same functionality using javascript:
<a href='javascript:openUrl()'>Visit here</a>
<script>
var sites=['http://www.google.com/',
'http://www.msn.com/',
'http://www.yahoo.com/'
];
function openUrl(){
var i = Math.round(Math.random()*(sites.length-1));
window.location.href=sites[i];
return false;
}
</script>
answered Nov 11 at 15:47
Pati
43748
add a comment |
I got my code working.
<?php
$addresses = [
'http://www.google.com',
'http://www.facebook.com',
'http://www.youtube.com'
];
$size = count($addresses);
$randomIndex = rand(0, $size - 1);
$randomUrl = $addresses[$randomIndex];
?>
<a href="<?php echo $randomUrl; ?>">random url</a>
If you have a better code, Please make a suggestion.
Thank you
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The same functionality using javascript:
<a href='javascript:openUrl()'>Visit here</a>
<script>
var sites=['http://www.google.com/',
'http://www.msn.com/',
'http://www.yahoo.com/'
];
function openUrl(){
var i = Math.round(Math.random()*(sites.length-1));
window.location.href=sites[i];
return false;
}
</script>
answered Nov 11 at 15:47
Pati
43748
add a comment |
The same functionality using javascript:
<a href='javascript:openUrl()'>Visit here</a>
<script>
var sites=['http://www.google.com/',
'http://www.msn.com/',
'http://www.yahoo.com/'
];
function openUrl(){
var i = Math.round(Math.random()*(sites.length-1));
window.location.href=sites[i];
return false;
}
</script>
answered Nov 11 at 15:47
Pati
43748
add a comment |
The same functionality using javascript:
<a href='javascript:openUrl()'>Visit here</a>
<script>
var sites=['http://www.google.com/',
'http://www.msn.com/',
'http://www.yahoo.com/'
];
function openUrl(){
var i = Math.round(Math.random()*(sites.length-1));
window.location.href=sites[i];
return false;
}
</script>
answered Nov 11 at 15:47
Pati
43748
The same functionality using javascript:
<a href='javascript:openUrl()'>Visit here</a>
<script>
var sites=['http://www.google.com/',
'http://www.msn.com/',
'http://www.yahoo.com/'
];
function openUrl(){
var i = Math.round(Math.random()*(sites.length-1));
window.location.href=sites[i];
return false;
}
</script>
answered Nov 11 at 15:47
Pati
43748
answered Nov 11 at 15:47
Pati
43748
answered Nov 11 at 15:47
Pati
43748
answered Nov 11 at 15:47
Pati
43748
43748
add a comment |
add a comment |
I got my code working.
<?php
$addresses = [
'http://www.google.com',
'http://www.facebook.com',
'http://www.youtube.com'
];
$size = count($addresses);
$randomIndex = rand(0, $size - 1);
$randomUrl = $addresses[$randomIndex];
?>
<a href="<?php echo $randomUrl; ?>">random url</a>
If you have a better code, Please make a suggestion.
Thank you
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
add a comment |
I got my code working.
<?php
$addresses = [
'http://www.google.com',
'http://www.facebook.com',
'http://www.youtube.com'
];
$size = count($addresses);
$randomIndex = rand(0, $size - 1);
$randomUrl = $addresses[$randomIndex];
?>
<a href="<?php echo $randomUrl; ?>">random url</a>
If you have a better code, Please make a suggestion.
Thank you
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
add a comment |
I got my code working.
<?php
$addresses = [
'http://www.google.com',
'http://www.facebook.com',
'http://www.youtube.com'
];
$size = count($addresses);
$randomIndex = rand(0, $size - 1);
$randomUrl = $addresses[$randomIndex];
?>
<a href="<?php echo $randomUrl; ?>">random url</a>
If you have a better code, Please make a suggestion.
Thank you
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
I got my code working.
<?php
$addresses = [
'http://www.google.com',
'http://www.facebook.com',
'http://www.youtube.com'
];
$size = count($addresses);
$randomIndex = rand(0, $size - 1);
$randomUrl = $addresses[$randomIndex];
?>
<a href="<?php echo $randomUrl; ?>">random url</a>
If you have a better code, Please make a suggestion.
Thank you
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
answered Nov 11 at 15:39
Rajeev Ranjan Sharma
248
248
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
add a comment |
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
2
2
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
I would recommend Pati's answer as it doesn't require refreshing the page for the URL to be different with each click. Since PHP is processed server-side, the URL isn't dynamic one it's sent to the client. Pati's JS answer dynamically changes the URL on the client.
– Snake14
Nov 11 at 15:52
add a comment |
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2
you're missing a semi-colon after
$sites = array(...);– Emissary
Nov 11 at 15:29
Also not clear if that href is legitimate or not. You haven't identified where the current redirect takes you
– charlietfl
Nov 11 at 15:38