Ndtyjky

I need two input array A and array B.
The answer will be like this - if input A is

{5,2,6,8} 

and input B is

{6,5,5,8,5,6} 

then the output will be:

2 (0 times), 5 (3 times), 6 (2 times), 8 ( 1 times)

Here is an example of how you can achieve it.

public static void main(String args) {

    int A={5,2,6,8},

            B={6,5,5,8,5,6};

    int count = new int[A.length]; // An array counting the occurences

    StringBuilder result = new StringBuilder(); // The String to be displayed. StringBuilder is better than String, when multiple concatenations occur.



    Arrays.sort(A); // Sorts array A in ascending order (by default).



    // This loop counts the occurence of each value of A inside B

    for (int i = 0; i <A.length; i++){

        for (int j = 0; j < B.length; j++){

            if (A[i] == B[j])

                count[i]++;

        }

        // After each value of A, add the number of occurence in the String

        result.append(A[i]).append(" (").append(count[i]).append(" times), ");

    }





    // Displays the String in the console, removing the last ", "

    System.out.println(result.substring(0,result.length()-2));



}