C: Unable to use modulus operators to break down change into denominations, storing into an array and print...












-2














I'm attempting to write a program in which:




  • The user inputs the cost of an item

  • The user inputs the amount they paid for the item

  • The program determines if the user is owed any change

  • The program calculates the amount of change owed

  • The program uses the modulus operator to break the amount of change down into coin denominations

  • The program stores the change and coin denominations into an array This is the first bit at which I'm getting stuck

  • The program displays the amount of change in coin denominations to the user


The purpose is to use an array to hold the values of the coins, so I "can write a general purpose change calculator that can be used for any coinage by changing the contents of the array".



Here is my code:



void vendingMachine()
{

// Declarations
#define ARRAY_LENGTH 6

int itemCost;
int amountEntered;
int fifty, twenty, ten, five, two, one;
int remainder;

// User input

printf("Please enter the cost of the item in pence: ");
scanf_s("%d", &itemCost);
while (itemCost <= 0 || itemCost > 99)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 99p: ");
scanf_s("%d", &itemCost);
}

printf("Please enter the amount entered into the machine in pence: ");
scanf_s("%d", &amountEntered);
while (amountEntered <= 0 || amountEntered > 100)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 100p: ");
scanf_s("%d", &amountEntered);
}

while (amountEntered < itemCost)
{
printf("You've entered an invalid amount. Please enter an amount equal to or higher than the cost of the item: ");
scanf_s("%d", &amountEntered);
}

// Program to determine if the customer is owed any change and, if so, how much is owed

if (amountEntered == itemCost)
{
printf("No change is owed to the customer");
}
else if (amountEntered > itemCost)
{
int change = amountEntered - itemCost;
printf("The amount of change owed to the customer is: %d pence, broken down as follows: n", change);

fifty = change / 50;
remainder = change % 50;
twenty = remainder / 20;
remainder = remainder % 20;
ten = remainder / 10;
remainder = remainder % 10;
five = remainder / 5;
remainder = remainder % 5;
two = remainder / 2;
remainder = remainder % 2;
one = remainder;

// Program to store the change in an array

int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;

for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}

for (int i = 0; i < ARRAY_LENGTH; i++)
{
printf("The number of %d coins is: %dn", //I don't know what to do here);
}
}
}









share|improve this question
























  • What's the point of count[i] = 0 which deletes all the assignments you did before?
    – Henning Koehler
    Nov 12 at 11:17










  • In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
    – hailnolly
    Nov 12 at 11:26










  • "This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
    – chux
    Nov 12 at 15:13


















-2














I'm attempting to write a program in which:




  • The user inputs the cost of an item

  • The user inputs the amount they paid for the item

  • The program determines if the user is owed any change

  • The program calculates the amount of change owed

  • The program uses the modulus operator to break the amount of change down into coin denominations

  • The program stores the change and coin denominations into an array This is the first bit at which I'm getting stuck

  • The program displays the amount of change in coin denominations to the user


The purpose is to use an array to hold the values of the coins, so I "can write a general purpose change calculator that can be used for any coinage by changing the contents of the array".



Here is my code:



void vendingMachine()
{

// Declarations
#define ARRAY_LENGTH 6

int itemCost;
int amountEntered;
int fifty, twenty, ten, five, two, one;
int remainder;

// User input

printf("Please enter the cost of the item in pence: ");
scanf_s("%d", &itemCost);
while (itemCost <= 0 || itemCost > 99)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 99p: ");
scanf_s("%d", &itemCost);
}

printf("Please enter the amount entered into the machine in pence: ");
scanf_s("%d", &amountEntered);
while (amountEntered <= 0 || amountEntered > 100)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 100p: ");
scanf_s("%d", &amountEntered);
}

while (amountEntered < itemCost)
{
printf("You've entered an invalid amount. Please enter an amount equal to or higher than the cost of the item: ");
scanf_s("%d", &amountEntered);
}

// Program to determine if the customer is owed any change and, if so, how much is owed

if (amountEntered == itemCost)
{
printf("No change is owed to the customer");
}
else if (amountEntered > itemCost)
{
int change = amountEntered - itemCost;
printf("The amount of change owed to the customer is: %d pence, broken down as follows: n", change);

fifty = change / 50;
remainder = change % 50;
twenty = remainder / 20;
remainder = remainder % 20;
ten = remainder / 10;
remainder = remainder % 10;
five = remainder / 5;
remainder = remainder % 5;
two = remainder / 2;
remainder = remainder % 2;
one = remainder;

// Program to store the change in an array

int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;

for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}

for (int i = 0; i < ARRAY_LENGTH; i++)
{
printf("The number of %d coins is: %dn", //I don't know what to do here);
}
}
}









share|improve this question
























  • What's the point of count[i] = 0 which deletes all the assignments you did before?
    – Henning Koehler
    Nov 12 at 11:17










  • In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
    – hailnolly
    Nov 12 at 11:26










  • "This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
    – chux
    Nov 12 at 15:13
















-2












-2








-2


1





I'm attempting to write a program in which:




  • The user inputs the cost of an item

  • The user inputs the amount they paid for the item

  • The program determines if the user is owed any change

  • The program calculates the amount of change owed

  • The program uses the modulus operator to break the amount of change down into coin denominations

  • The program stores the change and coin denominations into an array This is the first bit at which I'm getting stuck

  • The program displays the amount of change in coin denominations to the user


The purpose is to use an array to hold the values of the coins, so I "can write a general purpose change calculator that can be used for any coinage by changing the contents of the array".



Here is my code:



void vendingMachine()
{

// Declarations
#define ARRAY_LENGTH 6

int itemCost;
int amountEntered;
int fifty, twenty, ten, five, two, one;
int remainder;

// User input

printf("Please enter the cost of the item in pence: ");
scanf_s("%d", &itemCost);
while (itemCost <= 0 || itemCost > 99)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 99p: ");
scanf_s("%d", &itemCost);
}

printf("Please enter the amount entered into the machine in pence: ");
scanf_s("%d", &amountEntered);
while (amountEntered <= 0 || amountEntered > 100)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 100p: ");
scanf_s("%d", &amountEntered);
}

while (amountEntered < itemCost)
{
printf("You've entered an invalid amount. Please enter an amount equal to or higher than the cost of the item: ");
scanf_s("%d", &amountEntered);
}

// Program to determine if the customer is owed any change and, if so, how much is owed

if (amountEntered == itemCost)
{
printf("No change is owed to the customer");
}
else if (amountEntered > itemCost)
{
int change = amountEntered - itemCost;
printf("The amount of change owed to the customer is: %d pence, broken down as follows: n", change);

fifty = change / 50;
remainder = change % 50;
twenty = remainder / 20;
remainder = remainder % 20;
ten = remainder / 10;
remainder = remainder % 10;
five = remainder / 5;
remainder = remainder % 5;
two = remainder / 2;
remainder = remainder % 2;
one = remainder;

// Program to store the change in an array

int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;

for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}

for (int i = 0; i < ARRAY_LENGTH; i++)
{
printf("The number of %d coins is: %dn", //I don't know what to do here);
}
}
}









share|improve this question















I'm attempting to write a program in which:




  • The user inputs the cost of an item

  • The user inputs the amount they paid for the item

  • The program determines if the user is owed any change

  • The program calculates the amount of change owed

  • The program uses the modulus operator to break the amount of change down into coin denominations

  • The program stores the change and coin denominations into an array This is the first bit at which I'm getting stuck

  • The program displays the amount of change in coin denominations to the user


The purpose is to use an array to hold the values of the coins, so I "can write a general purpose change calculator that can be used for any coinage by changing the contents of the array".



Here is my code:



void vendingMachine()
{

// Declarations
#define ARRAY_LENGTH 6

int itemCost;
int amountEntered;
int fifty, twenty, ten, five, two, one;
int remainder;

// User input

printf("Please enter the cost of the item in pence: ");
scanf_s("%d", &itemCost);
while (itemCost <= 0 || itemCost > 99)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 99p: ");
scanf_s("%d", &itemCost);
}

printf("Please enter the amount entered into the machine in pence: ");
scanf_s("%d", &amountEntered);
while (amountEntered <= 0 || amountEntered > 100)
{
printf("You've entered an invalid amount. Please enter an amount between 1p and 100p: ");
scanf_s("%d", &amountEntered);
}

while (amountEntered < itemCost)
{
printf("You've entered an invalid amount. Please enter an amount equal to or higher than the cost of the item: ");
scanf_s("%d", &amountEntered);
}

// Program to determine if the customer is owed any change and, if so, how much is owed

if (amountEntered == itemCost)
{
printf("No change is owed to the customer");
}
else if (amountEntered > itemCost)
{
int change = amountEntered - itemCost;
printf("The amount of change owed to the customer is: %d pence, broken down as follows: n", change);

fifty = change / 50;
remainder = change % 50;
twenty = remainder / 20;
remainder = remainder % 20;
ten = remainder / 10;
remainder = remainder % 10;
five = remainder / 5;
remainder = remainder % 5;
two = remainder / 2;
remainder = remainder % 2;
one = remainder;

// Program to store the change in an array

int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;

for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}

for (int i = 0; i < ARRAY_LENGTH; i++)
{
printf("The number of %d coins is: %dn", //I don't know what to do here);
}
}
}






c arrays modulus integer-division






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 11:07

























asked Nov 12 at 10:42









hailnolly

186




186












  • What's the point of count[i] = 0 which deletes all the assignments you did before?
    – Henning Koehler
    Nov 12 at 11:17










  • In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
    – hailnolly
    Nov 12 at 11:26










  • "This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
    – chux
    Nov 12 at 15:13




















  • What's the point of count[i] = 0 which deletes all the assignments you did before?
    – Henning Koehler
    Nov 12 at 11:17










  • In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
    – hailnolly
    Nov 12 at 11:26










  • "This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
    – chux
    Nov 12 at 15:13


















What's the point of count[i] = 0 which deletes all the assignments you did before?
– Henning Koehler
Nov 12 at 11:17




What's the point of count[i] = 0 which deletes all the assignments you did before?
– Henning Koehler
Nov 12 at 11:17












In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
– hailnolly
Nov 12 at 11:26




In entire honesty, I got stuck here and was using code from the notes I was given. I don't think there is a point - thank you for pointing out what that code does.
– hailnolly
Nov 12 at 11:26












"This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
– chux
Nov 12 at 15:13






"This is the first bit at which I'm getting stuck" --> How/why are you stuck? What is unclear about the functionality at for (int i = 0; i < ARRAY_LENGTH; i++) { count[i] = 0; }?
– chux
Nov 12 at 15:13














2 Answers
2






active

oldest

votes


















0














Store the type of coins in an array as well, e.g.



const int coins[ARRAY_LENGTH] = { 50, 20, 10, 5, 2, 1 };


Then you can easily refer to them in your loop:



printf("The number of %d coins is: %dn", coins[i], count[i]);


This also allows you to perform your modulo calculations in a loop.






share|improve this answer





















  • Thank you very much Henning. That's solved my problem!
    – hailnolly
    Nov 12 at 16:45



















0














I am not sure what you are trying to achieve here:



The following piece of (your) code sets the values of count from index 0 to index 5, starting from fifty to one..



int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;


Then here, you are overwriting those with 0 in the for loop.



for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}


So above loop is not required, or at least must not be placed after you have assigned values of fifty, twenty, ten, five, two and one to count array indices.



I guess you are trying to print them? You don't have to use a loop here:



// Doing it the newbie-way:

printf("The number of coins of 50 are: %dn", count[0]);
printf("The number of coins of 20 are: %dn", count[1]);
printf("The number of coins of 10 are: %dn", count[2]);
printf("The number of coins of 5 are: %dn", count[3]);
printf("The number of coins of 2 are: %dn", count[4]);
printf("The number of coins of 1 are: %dn", count[5]);





share|improve this answer





















  • Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
    – hailnolly
    Nov 12 at 16:46












  • @hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
    – WedaPashi
    Nov 13 at 4:45











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Store the type of coins in an array as well, e.g.



const int coins[ARRAY_LENGTH] = { 50, 20, 10, 5, 2, 1 };


Then you can easily refer to them in your loop:



printf("The number of %d coins is: %dn", coins[i], count[i]);


This also allows you to perform your modulo calculations in a loop.






share|improve this answer





















  • Thank you very much Henning. That's solved my problem!
    – hailnolly
    Nov 12 at 16:45
















0














Store the type of coins in an array as well, e.g.



const int coins[ARRAY_LENGTH] = { 50, 20, 10, 5, 2, 1 };


Then you can easily refer to them in your loop:



printf("The number of %d coins is: %dn", coins[i], count[i]);


This also allows you to perform your modulo calculations in a loop.






share|improve this answer





















  • Thank you very much Henning. That's solved my problem!
    – hailnolly
    Nov 12 at 16:45














0












0








0






Store the type of coins in an array as well, e.g.



const int coins[ARRAY_LENGTH] = { 50, 20, 10, 5, 2, 1 };


Then you can easily refer to them in your loop:



printf("The number of %d coins is: %dn", coins[i], count[i]);


This also allows you to perform your modulo calculations in a loop.






share|improve this answer












Store the type of coins in an array as well, e.g.



const int coins[ARRAY_LENGTH] = { 50, 20, 10, 5, 2, 1 };


Then you can easily refer to them in your loop:



printf("The number of %d coins is: %dn", coins[i], count[i]);


This also allows you to perform your modulo calculations in a loop.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 at 11:20









Henning Koehler

1,129610




1,129610












  • Thank you very much Henning. That's solved my problem!
    – hailnolly
    Nov 12 at 16:45


















  • Thank you very much Henning. That's solved my problem!
    – hailnolly
    Nov 12 at 16:45
















Thank you very much Henning. That's solved my problem!
– hailnolly
Nov 12 at 16:45




Thank you very much Henning. That's solved my problem!
– hailnolly
Nov 12 at 16:45













0














I am not sure what you are trying to achieve here:



The following piece of (your) code sets the values of count from index 0 to index 5, starting from fifty to one..



int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;


Then here, you are overwriting those with 0 in the for loop.



for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}


So above loop is not required, or at least must not be placed after you have assigned values of fifty, twenty, ten, five, two and one to count array indices.



I guess you are trying to print them? You don't have to use a loop here:



// Doing it the newbie-way:

printf("The number of coins of 50 are: %dn", count[0]);
printf("The number of coins of 20 are: %dn", count[1]);
printf("The number of coins of 10 are: %dn", count[2]);
printf("The number of coins of 5 are: %dn", count[3]);
printf("The number of coins of 2 are: %dn", count[4]);
printf("The number of coins of 1 are: %dn", count[5]);





share|improve this answer





















  • Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
    – hailnolly
    Nov 12 at 16:46












  • @hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
    – WedaPashi
    Nov 13 at 4:45
















0














I am not sure what you are trying to achieve here:



The following piece of (your) code sets the values of count from index 0 to index 5, starting from fifty to one..



int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;


Then here, you are overwriting those with 0 in the for loop.



for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}


So above loop is not required, or at least must not be placed after you have assigned values of fifty, twenty, ten, five, two and one to count array indices.



I guess you are trying to print them? You don't have to use a loop here:



// Doing it the newbie-way:

printf("The number of coins of 50 are: %dn", count[0]);
printf("The number of coins of 20 are: %dn", count[1]);
printf("The number of coins of 10 are: %dn", count[2]);
printf("The number of coins of 5 are: %dn", count[3]);
printf("The number of coins of 2 are: %dn", count[4]);
printf("The number of coins of 1 are: %dn", count[5]);





share|improve this answer





















  • Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
    – hailnolly
    Nov 12 at 16:46












  • @hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
    – WedaPashi
    Nov 13 at 4:45














0












0








0






I am not sure what you are trying to achieve here:



The following piece of (your) code sets the values of count from index 0 to index 5, starting from fifty to one..



int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;


Then here, you are overwriting those with 0 in the for loop.



for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}


So above loop is not required, or at least must not be placed after you have assigned values of fifty, twenty, ten, five, two and one to count array indices.



I guess you are trying to print them? You don't have to use a loop here:



// Doing it the newbie-way:

printf("The number of coins of 50 are: %dn", count[0]);
printf("The number of coins of 20 are: %dn", count[1]);
printf("The number of coins of 10 are: %dn", count[2]);
printf("The number of coins of 5 are: %dn", count[3]);
printf("The number of coins of 2 are: %dn", count[4]);
printf("The number of coins of 1 are: %dn", count[5]);





share|improve this answer












I am not sure what you are trying to achieve here:



The following piece of (your) code sets the values of count from index 0 to index 5, starting from fifty to one..



int count[ARRAY_LENGTH];
count[0] = fifty;
count[1] = twenty;
count[2] = ten;
count[3] = five;
count[4] = two;
count[5] = one;


Then here, you are overwriting those with 0 in the for loop.



for (int i = 0; i < ARRAY_LENGTH; i++)
{
count[i] = 0;
}


So above loop is not required, or at least must not be placed after you have assigned values of fifty, twenty, ten, five, two and one to count array indices.



I guess you are trying to print them? You don't have to use a loop here:



// Doing it the newbie-way:

printf("The number of coins of 50 are: %dn", count[0]);
printf("The number of coins of 20 are: %dn", count[1]);
printf("The number of coins of 10 are: %dn", count[2]);
printf("The number of coins of 5 are: %dn", count[3]);
printf("The number of coins of 2 are: %dn", count[4]);
printf("The number of coins of 1 are: %dn", count[5]);






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answered Nov 12 at 11:55









WedaPashi

2,3691333




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  • Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
    – hailnolly
    Nov 12 at 16:46












  • @hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
    – WedaPashi
    Nov 13 at 4:45


















  • Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
    – hailnolly
    Nov 12 at 16:46












  • @hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
    – WedaPashi
    Nov 13 at 4:45
















Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
– hailnolly
Nov 12 at 16:46






Thanks! I really didn't realise (I'm new to this language, and programming in general) I was cancelling out my array, which is really embarrassing. Thank you for taking the time to help me.
– hailnolly
Nov 12 at 16:46














@hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
– WedaPashi
Nov 13 at 4:45




@hailnolly: No, its not embarrassing at all. We all have been learning from out mistakes in programming :-)
– WedaPashi
Nov 13 at 4:45


















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