What happens when a variable is assigned to zero in an `if` condition?
It would be helpful if anybody can explain this.
int main()
{
int a=0;
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
printf("Value of a is %dn",a);
return 0;
}
output of this is
a is not zero Value of a is 0
c
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
|
show 6 more comments
It would be helpful if anybody can explain this.
int main()
{
int a=0;
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
printf("Value of a is %dn",a);
return 0;
}
output of this is
a is not zero Value of a is 0
c
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
6
A line of your code is in error:if(a=0)should beif(a==0).
– STLDev
Jul 9 '13 at 5:36
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
3
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
1
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
1
@Ani: Er... Value of zero if treated asfalsein logical context (underif, for example). For this reasonelsebranch of yourifis taken. Why you wrote"a is not zero"in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.
– AnT
Jul 9 '13 at 6:27
|
show 6 more comments
It would be helpful if anybody can explain this.
int main()
{
int a=0;
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
printf("Value of a is %dn",a);
return 0;
}
output of this is
a is not zero Value of a is 0
c
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
It would be helpful if anybody can explain this.
int main()
{
int a=0;
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
printf("Value of a is %dn",a);
return 0;
}
output of this is
a is not zero Value of a is 0
c
c
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
edited Nov 15 '18 at 20:35
ealfonso
3,04722240
3,04722240
asked Jul 9 '13 at 5:35
AniAni
522313
asked Jul 9 '13 at 5:35
AniAni
522313
asked Jul 9 '13 at 5:35
AniAni
522313
522313
6
A line of your code is in error:if(a=0)should beif(a==0).
– STLDev
Jul 9 '13 at 5:36
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
3
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
1
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
1
@Ani: Er... Value of zero if treated asfalsein logical context (underif, for example). For this reasonelsebranch of yourifis taken. Why you wrote"a is not zero"in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.
– AnT
Jul 9 '13 at 6:27
|
show 6 more comments
6
A line of your code is in error:if(a=0)should beif(a==0).
– STLDev
Jul 9 '13 at 5:36
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
3
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
1
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
1
@Ani: Er... Value of zero if treated asfalsein logical context (underif, for example). For this reasonelsebranch of yourifis taken. Why you wrote"a is not zero"in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.
– AnT
Jul 9 '13 at 6:27
6
6
A line of your code is in error:
if(a=0) should be if(a==0).– STLDev
Jul 9 '13 at 5:36
A line of your code is in error:
if(a=0) should be if(a==0).– STLDev
Jul 9 '13 at 5:36
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
3
3
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
1
1
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
1
1
@Ani: Er... Value of zero if treated as
false in logical context (under if, for example). For this reason else branch of your if is taken. Why you wrote "a is not zero" in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.– AnT
Jul 9 '13 at 6:27
@Ani: Er... Value of zero if treated as
false in logical context (under if, for example). For this reason else branch of your if is taken. Why you wrote "a is not zero" in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.– AnT
Jul 9 '13 at 6:27
|
show 6 more comments
4 Answers
4
active
oldest
votes
The result of the assignment is the value of the expression.
Therefore:
if (a = 0)
is the same as:
if (0)
which is the same as:
if (false)
which will force the else path.
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
add a comment |
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
These messages are precisely backwards. The statement after the if is executed if the condition isn't 0, and the statement after the else is executed if the condition is 0, so this should be
if(a=0)
printf("a is not zerot");
else
printf("a is zerot");
Or, equivalently but more clearly,
a = 0;
if(a)
printf("a is not zerot");
else
printf("a is zerot");
Which, together with
printf("Value of a is %dn",a);
would print
a is zero Value of a is 0
as expected.
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
add a comment |
if(a=0) is assignement of 0 in variable a. if you want to compare a against zero you need to write like below
if(a==0)
your condition is simple assignment which is making a as zero so condition getting false and you are getting prints from else part.
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
add a comment |
If () function accepts true or false value as an argument.
So whatever you put inside the bracket has no significance to if() function but of the fact what value it has.
'0' in any case is considered as false value, so when you pass 0 as an argument like:
if(0)
{
---statments---
}
The statement part of will not get executed, and the system will directly jump to else part.
In the case you mentioned you assigned 0 to your variable and passed it as an argument to if().
Note that if() only accepts 0 or non 0 value. So, it doesn't matter what assignment you made. if() will recieve the value of your variable 'a' as an argument and act accordingly.
In this case, since the value of a is 0, the if part will not get executed and the system will jump to else.
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
The result of the assignment is the value of the expression.
Therefore:
if (a = 0)
is the same as:
if (0)
which is the same as:
if (false)
which will force the else path.
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
add a comment |
The result of the assignment is the value of the expression.
Therefore:
if (a = 0)
is the same as:
if (0)
which is the same as:
if (false)
which will force the else path.
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
add a comment |
The result of the assignment is the value of the expression.
Therefore:
if (a = 0)
is the same as:
if (0)
which is the same as:
if (false)
which will force the else path.
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
The result of the assignment is the value of the expression.
Therefore:
if (a = 0)
is the same as:
if (0)
which is the same as:
if (false)
which will force the else path.
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
answered Jul 9 '13 at 5:37
trojanfoetrojanfoe
106k15172210
106k15172210
add a comment |
add a comment |
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
These messages are precisely backwards. The statement after the if is executed if the condition isn't 0, and the statement after the else is executed if the condition is 0, so this should be
if(a=0)
printf("a is not zerot");
else
printf("a is zerot");
Or, equivalently but more clearly,
a = 0;
if(a)
printf("a is not zerot");
else
printf("a is zerot");
Which, together with
printf("Value of a is %dn",a);
would print
a is zero Value of a is 0
as expected.
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
add a comment |
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
These messages are precisely backwards. The statement after the if is executed if the condition isn't 0, and the statement after the else is executed if the condition is 0, so this should be
if(a=0)
printf("a is not zerot");
else
printf("a is zerot");
Or, equivalently but more clearly,
a = 0;
if(a)
printf("a is not zerot");
else
printf("a is zerot");
Which, together with
printf("Value of a is %dn",a);
would print
a is zero Value of a is 0
as expected.
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
add a comment |
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
These messages are precisely backwards. The statement after the if is executed if the condition isn't 0, and the statement after the else is executed if the condition is 0, so this should be
if(a=0)
printf("a is not zerot");
else
printf("a is zerot");
Or, equivalently but more clearly,
a = 0;
if(a)
printf("a is not zerot");
else
printf("a is zerot");
Which, together with
printf("Value of a is %dn",a);
would print
a is zero Value of a is 0
as expected.
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
if(a=0)
printf("a is zerot");
else
printf("a is not zerot");
These messages are precisely backwards. The statement after the if is executed if the condition isn't 0, and the statement after the else is executed if the condition is 0, so this should be
if(a=0)
printf("a is not zerot");
else
printf("a is zerot");
Or, equivalently but more clearly,
a = 0;
if(a)
printf("a is not zerot");
else
printf("a is zerot");
Which, together with
printf("Value of a is %dn",a);
would print
a is zero Value of a is 0
as expected.
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
edited Nov 26 '18 at 20:29
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
answered Jul 9 '13 at 5:47
Jim BalterJim Balter
13.5k12954
13.5k12954
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
add a comment |
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
1
1
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
@PHIfounder I know, it's strange how many folks at SO -- programmers -- are inattentive to details. Thanks for the upvote. I think I would have gotten more if I had dashed something off instead of taking the time to get it right ... I was still writing when the accepted answer was posted.
– Jim Balter
Jul 9 '13 at 5:59
add a comment |
if(a=0) is assignement of 0 in variable a. if you want to compare a against zero you need to write like below
if(a==0)
your condition is simple assignment which is making a as zero so condition getting false and you are getting prints from else part.
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
add a comment |
if(a=0) is assignement of 0 in variable a. if you want to compare a against zero you need to write like below
if(a==0)
your condition is simple assignment which is making a as zero so condition getting false and you are getting prints from else part.
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
add a comment |
if(a=0) is assignement of 0 in variable a. if you want to compare a against zero you need to write like below
if(a==0)
your condition is simple assignment which is making a as zero so condition getting false and you are getting prints from else part.
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
if(a=0) is assignement of 0 in variable a. if you want to compare a against zero you need to write like below
if(a==0)
your condition is simple assignment which is making a as zero so condition getting false and you are getting prints from else part.
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
edited Jul 9 '13 at 5:49
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
answered Jul 9 '13 at 5:37
Dayal raiDayal rai
5,7391627
5,7391627
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
add a comment |
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
The OP doesn't want ==. The OP has made extremely clear that assignment is intended.
– Jim Balter
Jul 9 '13 at 5:50
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
@JimBalter ya i know that,That is why i have given reason behind failing of condition and why prints from else part.I suggested comparison also just to be on safe side.
– Dayal rai
Jul 9 '13 at 5:52
add a comment |
If () function accepts true or false value as an argument.
So whatever you put inside the bracket has no significance to if() function but of the fact what value it has.
'0' in any case is considered as false value, so when you pass 0 as an argument like:
if(0)
{
---statments---
}
The statement part of will not get executed, and the system will directly jump to else part.
In the case you mentioned you assigned 0 to your variable and passed it as an argument to if().
Note that if() only accepts 0 or non 0 value. So, it doesn't matter what assignment you made. if() will recieve the value of your variable 'a' as an argument and act accordingly.
In this case, since the value of a is 0, the if part will not get executed and the system will jump to else.
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
add a comment |
If () function accepts true or false value as an argument.
So whatever you put inside the bracket has no significance to if() function but of the fact what value it has.
'0' in any case is considered as false value, so when you pass 0 as an argument like:
if(0)
{
---statments---
}
The statement part of will not get executed, and the system will directly jump to else part.
In the case you mentioned you assigned 0 to your variable and passed it as an argument to if().
Note that if() only accepts 0 or non 0 value. So, it doesn't matter what assignment you made. if() will recieve the value of your variable 'a' as an argument and act accordingly.
In this case, since the value of a is 0, the if part will not get executed and the system will jump to else.
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
add a comment |
If () function accepts true or false value as an argument.
So whatever you put inside the bracket has no significance to if() function but of the fact what value it has.
'0' in any case is considered as false value, so when you pass 0 as an argument like:
if(0)
{
---statments---
}
The statement part of will not get executed, and the system will directly jump to else part.
In the case you mentioned you assigned 0 to your variable and passed it as an argument to if().
Note that if() only accepts 0 or non 0 value. So, it doesn't matter what assignment you made. if() will recieve the value of your variable 'a' as an argument and act accordingly.
In this case, since the value of a is 0, the if part will not get executed and the system will jump to else.
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
If () function accepts true or false value as an argument.
So whatever you put inside the bracket has no significance to if() function but of the fact what value it has.
'0' in any case is considered as false value, so when you pass 0 as an argument like:
if(0)
{
---statments---
}
The statement part of will not get executed, and the system will directly jump to else part.
In the case you mentioned you assigned 0 to your variable and passed it as an argument to if().
Note that if() only accepts 0 or non 0 value. So, it doesn't matter what assignment you made. if() will recieve the value of your variable 'a' as an argument and act accordingly.
In this case, since the value of a is 0, the if part will not get executed and the system will jump to else.
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
answered Jul 9 '13 at 13:46
Chetan BhasinChetan Bhasin
2,2551633
2,2551633
add a comment |
add a comment |
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6
A line of your code is in error:
if(a=0)should beif(a==0).– STLDev
Jul 9 '13 at 5:36
You used the assignment operator not the comparison operator ==
– Mr Moose
Jul 9 '13 at 5:37
3
The title says "zero is assigned again" so presumably the second assignment is intentional. But I'm voting to close for general lack of clarity and research.
– Jim Balter
Jul 9 '13 at 5:43
1
@AndreyT The problem is that the text of the messages is backwards ... it would be right if they were inverted.
– Jim Balter
Jul 9 '13 at 5:45
1
@Ani: Er... Value of zero if treated as
falsein logical context (underif, for example). For this reasonelsebranch of yourifis taken. Why you wrote"a is not zero"in that branch is really a question to you. It is you, who for some strange reason arranged these messages "backwards". That's all there is to it.– AnT
Jul 9 '13 at 6:27