How to connect to BLE device that isn't advertising service UUID in iOS app
I am trying to connect an ESP32 module to my iPhone via BLE and am using centralManager.scanForPeripherals(withServices: [carServiceCBUUID], options: nil) where let carServiceCBUUID = CBUUID(string: "c0de0001-feed-f00d-c0ff-eeb3d05ebeef"). I am following Ray Wenderlich's heart monitor tutorial but since the ESP32 bluetooth module is not advertising the main Service UUID, it won't find the device when I do scanForPeripherals. Attached is the screenshot of the LightBlue information on the BLE device. Is there a way I can change the advertising data so I can advertise the service? I am running this code on the ESP32 https://thejeshgn.com/2018/06/11/esp32-ble-building-an-echo-service-gatt-server/
screenshot of LightBlue connection
ios swift arduino bluetooth-lowenergy esp32
asked Nov 15 '18 at 20:47
JohnJohn
234
add a comment |
I am trying to connect an ESP32 module to my iPhone via BLE and am using centralManager.scanForPeripherals(withServices: [carServiceCBUUID], options: nil) where let carServiceCBUUID = CBUUID(string: "c0de0001-feed-f00d-c0ff-eeb3d05ebeef"). I am following Ray Wenderlich's heart monitor tutorial but since the ESP32 bluetooth module is not advertising the main Service UUID, it won't find the device when I do scanForPeripherals. Attached is the screenshot of the LightBlue information on the BLE device. Is there a way I can change the advertising data so I can advertise the service? I am running this code on the ESP32 https://thejeshgn.com/2018/06/11/esp32-ble-building-an-echo-service-gatt-server/
screenshot of LightBlue connection
ios swift arduino bluetooth-lowenergy esp32
asked Nov 15 '18 at 20:47
JohnJohn
234
1
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to docentralManager.scanForPeripherals(withServices: nil, options: nil). I guess thatBLEAdvertising *pAdvertising = pServer->getAdvertising();is the where you might want to explicitly advertise the service.
– Larme
Nov 15 '18 at 21:00
add a comment |
I am trying to connect an ESP32 module to my iPhone via BLE and am using centralManager.scanForPeripherals(withServices: [carServiceCBUUID], options: nil) where let carServiceCBUUID = CBUUID(string: "c0de0001-feed-f00d-c0ff-eeb3d05ebeef"). I am following Ray Wenderlich's heart monitor tutorial but since the ESP32 bluetooth module is not advertising the main Service UUID, it won't find the device when I do scanForPeripherals. Attached is the screenshot of the LightBlue information on the BLE device. Is there a way I can change the advertising data so I can advertise the service? I am running this code on the ESP32 https://thejeshgn.com/2018/06/11/esp32-ble-building-an-echo-service-gatt-server/
screenshot of LightBlue connection
ios swift arduino bluetooth-lowenergy esp32
asked Nov 15 '18 at 20:47
JohnJohn
234
I am trying to connect an ESP32 module to my iPhone via BLE and am using centralManager.scanForPeripherals(withServices: [carServiceCBUUID], options: nil) where let carServiceCBUUID = CBUUID(string: "c0de0001-feed-f00d-c0ff-eeb3d05ebeef"). I am following Ray Wenderlich's heart monitor tutorial but since the ESP32 bluetooth module is not advertising the main Service UUID, it won't find the device when I do scanForPeripherals. Attached is the screenshot of the LightBlue information on the BLE device. Is there a way I can change the advertising data so I can advertise the service? I am running this code on the ESP32 https://thejeshgn.com/2018/06/11/esp32-ble-building-an-echo-service-gatt-server/
screenshot of LightBlue connection
ios swift arduino bluetooth-lowenergy esp32
ios swift arduino bluetooth-lowenergy esp32
asked Nov 15 '18 at 20:47
JohnJohn
234
asked Nov 15 '18 at 20:47
JohnJohn
234
asked Nov 15 '18 at 20:47
JohnJohn
234
asked Nov 15 '18 at 20:47
JohnJohn
234
asked Nov 15 '18 at 20:47
JohnJohn
234
234
1
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to docentralManager.scanForPeripherals(withServices: nil, options: nil). I guess thatBLEAdvertising *pAdvertising = pServer->getAdvertising();is the where you might want to explicitly advertise the service.
– Larme
Nov 15 '18 at 21:00
add a comment |
1
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to docentralManager.scanForPeripherals(withServices: nil, options: nil). I guess thatBLEAdvertising *pAdvertising = pServer->getAdvertising();is the where you might want to explicitly advertise the service.
– Larme
Nov 15 '18 at 21:00
1
1
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to do
centralManager.scanForPeripherals(withServices: nil, options: nil). I guess that BLEAdvertising *pAdvertising = pServer->getAdvertising(); is the where you might want to explicitly advertise the service.– Larme
Nov 15 '18 at 21:00
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to do
centralManager.scanForPeripherals(withServices: nil, options: nil). I guess that BLEAdvertising *pAdvertising = pServer->getAdvertising(); is the where you might want to explicitly advertise the service.– Larme
Nov 15 '18 at 21:00
add a comment |
1 Answer
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According to documentation of scanForPeripheralsWithServices:options: the serviceUUIDs parameter can be nil - in that case
all discovered peripherals are returned regardless of their supported services (not recommended)
So unless you are planning to use background modes to scan when app is in background, you can just pass nil as serviceUUIDs parameter
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
add a comment |
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According to documentation of scanForPeripheralsWithServices:options: the serviceUUIDs parameter can be nil - in that case
all discovered peripherals are returned regardless of their supported services (not recommended)
So unless you are planning to use background modes to scan when app is in background, you can just pass nil as serviceUUIDs parameter
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
add a comment |
According to documentation of scanForPeripheralsWithServices:options: the serviceUUIDs parameter can be nil - in that case
all discovered peripherals are returned regardless of their supported services (not recommended)
So unless you are planning to use background modes to scan when app is in background, you can just pass nil as serviceUUIDs parameter
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
add a comment |
According to documentation of scanForPeripheralsWithServices:options: the serviceUUIDs parameter can be nil - in that case
all discovered peripherals are returned regardless of their supported services (not recommended)
So unless you are planning to use background modes to scan when app is in background, you can just pass nil as serviceUUIDs parameter
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
According to documentation of scanForPeripheralsWithServices:options: the serviceUUIDs parameter can be nil - in that case
all discovered peripherals are returned regardless of their supported services (not recommended)
So unless you are planning to use background modes to scan when app is in background, you can just pass nil as serviceUUIDs parameter
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
answered Nov 15 '18 at 21:02
mag_zbcmag_zbc
4,12383048
4,12383048
add a comment |
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1
The issue is not on the Swift. If you don't publicly advertise the service, you can't find it that way. You need to do
centralManager.scanForPeripherals(withServices: nil, options: nil). I guess thatBLEAdvertising *pAdvertising = pServer->getAdvertising();is the where you might want to explicitly advertise the service.– Larme
Nov 15 '18 at 21:00