Remove the deleted values from array












0















I have two arrays such as,



Array 1:



    deletedValuesfromArray =
[
{ "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
{ "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
]


Array 2:



  normalArray =
[
{ "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
{ "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
{ "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
{ "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
]


I would like to compare both arrays and filter the array to get the new one after removing the deletedValuesfromArray (Array 1).



For which i have tried the following,



let newArray = this.normalArray.filter(function (val) {
return this.deletedValuesfromArray.indexOf(val) == -1;
});
console.log(newArray);


But it doesn't works..



Expected Output is,



New Array



   [
{ "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
{ "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 }
]


Stackblitz that i have tried



The values also will not be unique always it may have a complete duplicate of any object.



How to compare and remove the deleted values from the normal array and get the newarray?










share|improve this question





























    0















    I have two arrays such as,



    Array 1:



        deletedValuesfromArray =
    [
    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
    ]


    Array 2:



      normalArray =
    [
    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
    ]


    I would like to compare both arrays and filter the array to get the new one after removing the deletedValuesfromArray (Array 1).



    For which i have tried the following,



    let newArray = this.normalArray.filter(function (val) {
    return this.deletedValuesfromArray.indexOf(val) == -1;
    });
    console.log(newArray);


    But it doesn't works..



    Expected Output is,



    New Array



       [
    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 }
    ]


    Stackblitz that i have tried



    The values also will not be unique always it may have a complete duplicate of any object.



    How to compare and remove the deleted values from the normal array and get the newarray?










    share|improve this question



























      0












      0








      0








      I have two arrays such as,



      Array 1:



          deletedValuesfromArray =
      [
      { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
      { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
      ]


      Array 2:



        normalArray =
      [
      { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
      { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
      { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
      { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
      ]


      I would like to compare both arrays and filter the array to get the new one after removing the deletedValuesfromArray (Array 1).



      For which i have tried the following,



      let newArray = this.normalArray.filter(function (val) {
      return this.deletedValuesfromArray.indexOf(val) == -1;
      });
      console.log(newArray);


      But it doesn't works..



      Expected Output is,



      New Array



         [
      { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
      { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 }
      ]


      Stackblitz that i have tried



      The values also will not be unique always it may have a complete duplicate of any object.



      How to compare and remove the deleted values from the normal array and get the newarray?










      share|improve this question
















      I have two arrays such as,



      Array 1:



          deletedValuesfromArray =
      [
      { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
      { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
      ]


      Array 2:



        normalArray =
      [
      { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
      { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
      { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
      { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
      ]


      I would like to compare both arrays and filter the array to get the new one after removing the deletedValuesfromArray (Array 1).



      For which i have tried the following,



      let newArray = this.normalArray.filter(function (val) {
      return this.deletedValuesfromArray.indexOf(val) == -1;
      });
      console.log(newArray);


      But it doesn't works..



      Expected Output is,



      New Array



         [
      { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
      { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 }
      ]


      Stackblitz that i have tried



      The values also will not be unique always it may have a complete duplicate of any object.



      How to compare and remove the deleted values from the normal array and get the newarray?







      javascript arrays angular typescript filter






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 14:54









      James Z

      11.2k71935




      11.2k71935










      asked Nov 14 '18 at 13:22









      Maniraj from KarurManiraj from Karur

      1,0491134




      1,0491134
























          5 Answers
          5






          active

          oldest

          votes


















          1














          Your filter predicate doesn't work because you can't just compare an object from normalArray to an object from deletedValuesfromArray:




          indexOf() compares searchElement to elements of the Array using
          strict equality (the same method used by the === or triple-equals
          operator).




          -- Array.indexOf()



          In other words,



          { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 } === { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 }
          // > false


          To make the filter work, you need to implement a comparison function. See How to determine equality for two JavaScript objects? for some ideas.






          share|improve this answer































            0














            Using lodash :-



            npm install --save lodash


            import * as _ from "lodash";

            var newArray = _.differenceWith(this.normalArray, this.deletedValuesfromArray, _.isEqual);
            console.log("newArray", newArray);





            share|improve this answer
























            • I should not use any library or package in my angular project..

              – Maniraj from Karur
              Nov 14 '18 at 13:38











            • Try like this - stackoverflow.com/a/21988185/5362646

              – Chandru
              Nov 14 '18 at 13:42











            • FYI, lodash is swiss army knife of Javascript.

              – devansvd
              Nov 14 '18 at 13:53



















            0














            one of simple options here you can use JSON.stringify, which will turn objects into strings and compare them as strings, because 2 objects never equal each other by value since it compares them by reference, make sure that your objects keys order are the same






            const deletedValuesfromArray =
            [
            { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
            { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
            ]

            const normalArray =
            [
            { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
            { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
            { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
            { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
            ]

            const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

            console.log(result);








            share|improve this answer


























            • what if the order of keys is different in two same-looking objects?

              – shkaper
              Nov 14 '18 at 13:35











            • @shkaper the order is important in my example, I will update my answer

              – Artyom Amiryan
              Nov 14 '18 at 13:36













            • who can explain the downvote ?

              – Artyom Amiryan
              Nov 14 '18 at 16:07











            • I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

              – itsundefined
              Nov 14 '18 at 20:50






            • 1





              @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

              – Artyom Amiryan
              Nov 14 '18 at 21:02



















            0














            You can proceed with ES6 operators (filter and some) :



             ngOnInit() {
            let newArray = this.normalArray.filter( (val) => {
            return !this.deletedValuesfromArray.some((newval) => {
            return JSON.stringify(newval) === JSON.stringify(val) // check if two objects are the same
            });
            });
            console.log(newArray);
            }





            share|improve this answer


























            • Here you're assuming that property_name values are unique. The OP never said that

              – shkaper
              Nov 14 '18 at 13:42











            • Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

              – Maniraj from Karur
              Nov 14 '18 at 13:58











            • @ManiRaj updated answer !

              – selem mn
              Nov 14 '18 at 14:26






            • 3





              this is potentially dangerous since object's property order is not guaranteed in JavaScript

              – shkaper
              Nov 14 '18 at 14:55











            • If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

              – itsundefined
              Nov 14 '18 at 20:58



















            0














            This might also help you.



            function display()
            {
            let newArray = this.normalArray.filter(function (val) {
            count = 0;
            var flag = true;
            return this.deletedValuesfromArray.find(function(item, i){
            count++;

            if(val.property_name == item.property_name && val.property_type == item.property_type && val.property_required == item.property_required && val.property_origin == item.property_origin ){
            flag = false;
            }
            if(count == deletedValuesfromArray.length) {
            return flag;
            }
            });


            });
            }






            share|improve this answer
























            • please vote if this ans helps you

              – Pratik Rathi
              Nov 15 '18 at 6:16











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            5 Answers
            5






            active

            oldest

            votes








            5 Answers
            5






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Your filter predicate doesn't work because you can't just compare an object from normalArray to an object from deletedValuesfromArray:




            indexOf() compares searchElement to elements of the Array using
            strict equality (the same method used by the === or triple-equals
            operator).




            -- Array.indexOf()



            In other words,



            { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 } === { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 }
            // > false


            To make the filter work, you need to implement a comparison function. See How to determine equality for two JavaScript objects? for some ideas.






            share|improve this answer




























              1














              Your filter predicate doesn't work because you can't just compare an object from normalArray to an object from deletedValuesfromArray:




              indexOf() compares searchElement to elements of the Array using
              strict equality (the same method used by the === or triple-equals
              operator).




              -- Array.indexOf()



              In other words,



              { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 } === { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 }
              // > false


              To make the filter work, you need to implement a comparison function. See How to determine equality for two JavaScript objects? for some ideas.






              share|improve this answer


























                1












                1








                1







                Your filter predicate doesn't work because you can't just compare an object from normalArray to an object from deletedValuesfromArray:




                indexOf() compares searchElement to elements of the Array using
                strict equality (the same method used by the === or triple-equals
                operator).




                -- Array.indexOf()



                In other words,



                { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 } === { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 }
                // > false


                To make the filter work, you need to implement a comparison function. See How to determine equality for two JavaScript objects? for some ideas.






                share|improve this answer













                Your filter predicate doesn't work because you can't just compare an object from normalArray to an object from deletedValuesfromArray:




                indexOf() compares searchElement to elements of the Array using
                strict equality (the same method used by the === or triple-equals
                operator).




                -- Array.indexOf()



                In other words,



                { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 } === { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 }
                // > false


                To make the filter work, you need to implement a comparison function. See How to determine equality for two JavaScript objects? for some ideas.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 13:31









                shkapershkaper

                1,2511814




                1,2511814

























                    0














                    Using lodash :-



                    npm install --save lodash


                    import * as _ from "lodash";

                    var newArray = _.differenceWith(this.normalArray, this.deletedValuesfromArray, _.isEqual);
                    console.log("newArray", newArray);





                    share|improve this answer
























                    • I should not use any library or package in my angular project..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:38











                    • Try like this - stackoverflow.com/a/21988185/5362646

                      – Chandru
                      Nov 14 '18 at 13:42











                    • FYI, lodash is swiss army knife of Javascript.

                      – devansvd
                      Nov 14 '18 at 13:53
















                    0














                    Using lodash :-



                    npm install --save lodash


                    import * as _ from "lodash";

                    var newArray = _.differenceWith(this.normalArray, this.deletedValuesfromArray, _.isEqual);
                    console.log("newArray", newArray);





                    share|improve this answer
























                    • I should not use any library or package in my angular project..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:38











                    • Try like this - stackoverflow.com/a/21988185/5362646

                      – Chandru
                      Nov 14 '18 at 13:42











                    • FYI, lodash is swiss army knife of Javascript.

                      – devansvd
                      Nov 14 '18 at 13:53














                    0












                    0








                    0







                    Using lodash :-



                    npm install --save lodash


                    import * as _ from "lodash";

                    var newArray = _.differenceWith(this.normalArray, this.deletedValuesfromArray, _.isEqual);
                    console.log("newArray", newArray);





                    share|improve this answer













                    Using lodash :-



                    npm install --save lodash


                    import * as _ from "lodash";

                    var newArray = _.differenceWith(this.normalArray, this.deletedValuesfromArray, _.isEqual);
                    console.log("newArray", newArray);






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 14 '18 at 13:36









                    ChandruChandru

                    5,20721229




                    5,20721229













                    • I should not use any library or package in my angular project..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:38











                    • Try like this - stackoverflow.com/a/21988185/5362646

                      – Chandru
                      Nov 14 '18 at 13:42











                    • FYI, lodash is swiss army knife of Javascript.

                      – devansvd
                      Nov 14 '18 at 13:53



















                    • I should not use any library or package in my angular project..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:38











                    • Try like this - stackoverflow.com/a/21988185/5362646

                      – Chandru
                      Nov 14 '18 at 13:42











                    • FYI, lodash is swiss army knife of Javascript.

                      – devansvd
                      Nov 14 '18 at 13:53

















                    I should not use any library or package in my angular project..

                    – Maniraj from Karur
                    Nov 14 '18 at 13:38





                    I should not use any library or package in my angular project..

                    – Maniraj from Karur
                    Nov 14 '18 at 13:38













                    Try like this - stackoverflow.com/a/21988185/5362646

                    – Chandru
                    Nov 14 '18 at 13:42





                    Try like this - stackoverflow.com/a/21988185/5362646

                    – Chandru
                    Nov 14 '18 at 13:42













                    FYI, lodash is swiss army knife of Javascript.

                    – devansvd
                    Nov 14 '18 at 13:53





                    FYI, lodash is swiss army knife of Javascript.

                    – devansvd
                    Nov 14 '18 at 13:53











                    0














                    one of simple options here you can use JSON.stringify, which will turn objects into strings and compare them as strings, because 2 objects never equal each other by value since it compares them by reference, make sure that your objects keys order are the same






                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);








                    share|improve this answer


























                    • what if the order of keys is different in two same-looking objects?

                      – shkaper
                      Nov 14 '18 at 13:35











                    • @shkaper the order is important in my example, I will update my answer

                      – Artyom Amiryan
                      Nov 14 '18 at 13:36













                    • who can explain the downvote ?

                      – Artyom Amiryan
                      Nov 14 '18 at 16:07











                    • I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                      – itsundefined
                      Nov 14 '18 at 20:50






                    • 1





                      @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                      – Artyom Amiryan
                      Nov 14 '18 at 21:02
















                    0














                    one of simple options here you can use JSON.stringify, which will turn objects into strings and compare them as strings, because 2 objects never equal each other by value since it compares them by reference, make sure that your objects keys order are the same






                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);








                    share|improve this answer


























                    • what if the order of keys is different in two same-looking objects?

                      – shkaper
                      Nov 14 '18 at 13:35











                    • @shkaper the order is important in my example, I will update my answer

                      – Artyom Amiryan
                      Nov 14 '18 at 13:36













                    • who can explain the downvote ?

                      – Artyom Amiryan
                      Nov 14 '18 at 16:07











                    • I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                      – itsundefined
                      Nov 14 '18 at 20:50






                    • 1





                      @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                      – Artyom Amiryan
                      Nov 14 '18 at 21:02














                    0












                    0








                    0







                    one of simple options here you can use JSON.stringify, which will turn objects into strings and compare them as strings, because 2 objects never equal each other by value since it compares them by reference, make sure that your objects keys order are the same






                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);








                    share|improve this answer















                    one of simple options here you can use JSON.stringify, which will turn objects into strings and compare them as strings, because 2 objects never equal each other by value since it compares them by reference, make sure that your objects keys order are the same






                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);








                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);





                    const deletedValuesfromArray =
                    [
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const normalArray =
                    [
                    { "property_name": "Property one", "property_type": 4, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property two", "property_type": 5, "property_required": true, "property_origin": 1 },
                    { "property_name": "Property three", "property_type": 4, "property_required": true, "property_origin": 2 },
                    { "property_name": "rstywrtre", "property_type": 3, "property_required": true, "property_origin": 1 }
                    ]

                    const result = normalArray.filter(obj => !deletedValuesfromArray.find(o => JSON.stringify(o) == JSON.stringify(obj)));

                    console.log(result);






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 14 '18 at 13:37

























                    answered Nov 14 '18 at 13:34









                    Artyom AmiryanArtyom Amiryan

                    1,9371214




                    1,9371214













                    • what if the order of keys is different in two same-looking objects?

                      – shkaper
                      Nov 14 '18 at 13:35











                    • @shkaper the order is important in my example, I will update my answer

                      – Artyom Amiryan
                      Nov 14 '18 at 13:36













                    • who can explain the downvote ?

                      – Artyom Amiryan
                      Nov 14 '18 at 16:07











                    • I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                      – itsundefined
                      Nov 14 '18 at 20:50






                    • 1





                      @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                      – Artyom Amiryan
                      Nov 14 '18 at 21:02



















                    • what if the order of keys is different in two same-looking objects?

                      – shkaper
                      Nov 14 '18 at 13:35











                    • @shkaper the order is important in my example, I will update my answer

                      – Artyom Amiryan
                      Nov 14 '18 at 13:36













                    • who can explain the downvote ?

                      – Artyom Amiryan
                      Nov 14 '18 at 16:07











                    • I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                      – itsundefined
                      Nov 14 '18 at 20:50






                    • 1





                      @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                      – Artyom Amiryan
                      Nov 14 '18 at 21:02

















                    what if the order of keys is different in two same-looking objects?

                    – shkaper
                    Nov 14 '18 at 13:35





                    what if the order of keys is different in two same-looking objects?

                    – shkaper
                    Nov 14 '18 at 13:35













                    @shkaper the order is important in my example, I will update my answer

                    – Artyom Amiryan
                    Nov 14 '18 at 13:36







                    @shkaper the order is important in my example, I will update my answer

                    – Artyom Amiryan
                    Nov 14 '18 at 13:36















                    who can explain the downvote ?

                    – Artyom Amiryan
                    Nov 14 '18 at 16:07





                    who can explain the downvote ?

                    – Artyom Amiryan
                    Nov 14 '18 at 16:07













                    I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                    – itsundefined
                    Nov 14 '18 at 20:50





                    I can explain the down vote. Using stringify is a terrible solution and the guy that made the question didn't say that he wants to check that the two objects are exactly identical. You should NEVER expect that the order of keys is the same.

                    – itsundefined
                    Nov 14 '18 at 20:50




                    1




                    1





                    @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                    – Artyom Amiryan
                    Nov 14 '18 at 21:02





                    @itsundefined from the question it is easy to get that he wants to check that the two objects are exactly identical. Almost all answers contain the same logic, as accepted answer too which marked by question creator, it means we got question right, and I noted that in my example order is important, so I don't see any reason for down vote, it seems you got question wrong and added down votes to answers which have upvote

                    – Artyom Amiryan
                    Nov 14 '18 at 21:02











                    0














                    You can proceed with ES6 operators (filter and some) :



                     ngOnInit() {
                    let newArray = this.normalArray.filter( (val) => {
                    return !this.deletedValuesfromArray.some((newval) => {
                    return JSON.stringify(newval) === JSON.stringify(val) // check if two objects are the same
                    });
                    });
                    console.log(newArray);
                    }





                    share|improve this answer


























                    • Here you're assuming that property_name values are unique. The OP never said that

                      – shkaper
                      Nov 14 '18 at 13:42











                    • Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:58











                    • @ManiRaj updated answer !

                      – selem mn
                      Nov 14 '18 at 14:26






                    • 3





                      this is potentially dangerous since object's property order is not guaranteed in JavaScript

                      – shkaper
                      Nov 14 '18 at 14:55











                    • If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                      – itsundefined
                      Nov 14 '18 at 20:58
















                    0














                    You can proceed with ES6 operators (filter and some) :



                     ngOnInit() {
                    let newArray = this.normalArray.filter( (val) => {
                    return !this.deletedValuesfromArray.some((newval) => {
                    return JSON.stringify(newval) === JSON.stringify(val) // check if two objects are the same
                    });
                    });
                    console.log(newArray);
                    }





                    share|improve this answer


























                    • Here you're assuming that property_name values are unique. The OP never said that

                      – shkaper
                      Nov 14 '18 at 13:42











                    • Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:58











                    • @ManiRaj updated answer !

                      – selem mn
                      Nov 14 '18 at 14:26






                    • 3





                      this is potentially dangerous since object's property order is not guaranteed in JavaScript

                      – shkaper
                      Nov 14 '18 at 14:55











                    • If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                      – itsundefined
                      Nov 14 '18 at 20:58














                    0












                    0








                    0







                    You can proceed with ES6 operators (filter and some) :



                     ngOnInit() {
                    let newArray = this.normalArray.filter( (val) => {
                    return !this.deletedValuesfromArray.some((newval) => {
                    return JSON.stringify(newval) === JSON.stringify(val) // check if two objects are the same
                    });
                    });
                    console.log(newArray);
                    }





                    share|improve this answer















                    You can proceed with ES6 operators (filter and some) :



                     ngOnInit() {
                    let newArray = this.normalArray.filter( (val) => {
                    return !this.deletedValuesfromArray.some((newval) => {
                    return JSON.stringify(newval) === JSON.stringify(val) // check if two objects are the same
                    });
                    });
                    console.log(newArray);
                    }






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 14 '18 at 14:25

























                    answered Nov 14 '18 at 13:33









                    selem mnselem mn

                    5,07541939




                    5,07541939













                    • Here you're assuming that property_name values are unique. The OP never said that

                      – shkaper
                      Nov 14 '18 at 13:42











                    • Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:58











                    • @ManiRaj updated answer !

                      – selem mn
                      Nov 14 '18 at 14:26






                    • 3





                      this is potentially dangerous since object's property order is not guaranteed in JavaScript

                      – shkaper
                      Nov 14 '18 at 14:55











                    • If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                      – itsundefined
                      Nov 14 '18 at 20:58



















                    • Here you're assuming that property_name values are unique. The OP never said that

                      – shkaper
                      Nov 14 '18 at 13:42











                    • Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                      – Maniraj from Karur
                      Nov 14 '18 at 13:58











                    • @ManiRaj updated answer !

                      – selem mn
                      Nov 14 '18 at 14:26






                    • 3





                      this is potentially dangerous since object's property order is not guaranteed in JavaScript

                      – shkaper
                      Nov 14 '18 at 14:55











                    • If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                      – itsundefined
                      Nov 14 '18 at 20:58

















                    Here you're assuming that property_name values are unique. The OP never said that

                    – shkaper
                    Nov 14 '18 at 13:42





                    Here you're assuming that property_name values are unique. The OP never said that

                    – shkaper
                    Nov 14 '18 at 13:42













                    Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                    – Maniraj from Karur
                    Nov 14 '18 at 13:58





                    Yes this solution seems to be close to me but the thing is as @shkaper said the values may not be unique at all time..

                    – Maniraj from Karur
                    Nov 14 '18 at 13:58













                    @ManiRaj updated answer !

                    – selem mn
                    Nov 14 '18 at 14:26





                    @ManiRaj updated answer !

                    – selem mn
                    Nov 14 '18 at 14:26




                    3




                    3





                    this is potentially dangerous since object's property order is not guaranteed in JavaScript

                    – shkaper
                    Nov 14 '18 at 14:55





                    this is potentially dangerous since object's property order is not guaranteed in JavaScript

                    – shkaper
                    Nov 14 '18 at 14:55













                    If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                    – itsundefined
                    Nov 14 '18 at 20:58





                    If you need an explanation about why this solution is terrible, please consider how much cpu time is wasted to stringify all those objects. You are also stringifying the same object way too many times with the way this loop works. You are also not taking into account that there is no spec in javascript that says that the order of object properties stays the same.

                    – itsundefined
                    Nov 14 '18 at 20:58











                    0














                    This might also help you.



                    function display()
                    {
                    let newArray = this.normalArray.filter(function (val) {
                    count = 0;
                    var flag = true;
                    return this.deletedValuesfromArray.find(function(item, i){
                    count++;

                    if(val.property_name == item.property_name && val.property_type == item.property_type && val.property_required == item.property_required && val.property_origin == item.property_origin ){
                    flag = false;
                    }
                    if(count == deletedValuesfromArray.length) {
                    return flag;
                    }
                    });


                    });
                    }






                    share|improve this answer
























                    • please vote if this ans helps you

                      – Pratik Rathi
                      Nov 15 '18 at 6:16
















                    0














                    This might also help you.



                    function display()
                    {
                    let newArray = this.normalArray.filter(function (val) {
                    count = 0;
                    var flag = true;
                    return this.deletedValuesfromArray.find(function(item, i){
                    count++;

                    if(val.property_name == item.property_name && val.property_type == item.property_type && val.property_required == item.property_required && val.property_origin == item.property_origin ){
                    flag = false;
                    }
                    if(count == deletedValuesfromArray.length) {
                    return flag;
                    }
                    });


                    });
                    }






                    share|improve this answer
























                    • please vote if this ans helps you

                      – Pratik Rathi
                      Nov 15 '18 at 6:16














                    0












                    0








                    0







                    This might also help you.



                    function display()
                    {
                    let newArray = this.normalArray.filter(function (val) {
                    count = 0;
                    var flag = true;
                    return this.deletedValuesfromArray.find(function(item, i){
                    count++;

                    if(val.property_name == item.property_name && val.property_type == item.property_type && val.property_required == item.property_required && val.property_origin == item.property_origin ){
                    flag = false;
                    }
                    if(count == deletedValuesfromArray.length) {
                    return flag;
                    }
                    });


                    });
                    }






                    share|improve this answer













                    This might also help you.



                    function display()
                    {
                    let newArray = this.normalArray.filter(function (val) {
                    count = 0;
                    var flag = true;
                    return this.deletedValuesfromArray.find(function(item, i){
                    count++;

                    if(val.property_name == item.property_name && val.property_type == item.property_type && val.property_required == item.property_required && val.property_origin == item.property_origin ){
                    flag = false;
                    }
                    if(count == deletedValuesfromArray.length) {
                    return flag;
                    }
                    });


                    });
                    }







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 15 '18 at 6:15









                    Pratik RathiPratik Rathi

                    66




                    66













                    • please vote if this ans helps you

                      – Pratik Rathi
                      Nov 15 '18 at 6:16



















                    • please vote if this ans helps you

                      – Pratik Rathi
                      Nov 15 '18 at 6:16

















                    please vote if this ans helps you

                    – Pratik Rathi
                    Nov 15 '18 at 6:16





                    please vote if this ans helps you

                    – Pratik Rathi
                    Nov 15 '18 at 6:16


















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