R - Find all possible combinations splitted word












0















I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question


















  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24
















0















I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question


















  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24














0












0








0


1






I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question














I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...







r loops dataframe






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 13 '18 at 22:08









BoraxBorax

284




284








  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24














  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24








1




1





how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

– user702846
Nov 13 '18 at 22:16





how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

– user702846
Nov 13 '18 at 22:16













Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

– Borax
Nov 13 '18 at 22:24





Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

– Borax
Nov 13 '18 at 22:24












0






active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290239%2fr-find-all-possible-combinations-splitted-word%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53290239%2fr-find-all-possible-combinations-splitted-word%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Florida Star v. B. J. F.

Error while running script in elastic search , gateway timeout

Adding quotations to stringified JSON object values