R - Find all possible combinations splitted word












0















I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question


















  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24
















0















I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question


















  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24














0












0








0


1






I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...










share|improve this question














I have a function which extracts all meaningful words from a string. After this, I would like to create all possible sentences from these words.



For example:



MyString <- "temelproblem"


After splitting with my function I get a dataframe like this;



Data <- data.frame(
myword = c("te","tem","teme","temel","em","eme","emel","me","mel","el","pr","problem","em"),
start = c(1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 6, 11),
finish = c(2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 7, 12, 12)
)

> Data
myword start finish
1 te 1 2
2 tem 1 3
3 teme 1 4
4 temel 1 5
5 em 2 3
6 eme 2 4
7 emel 2 5
8 me 3 4
9 mel 3 5
10 el 4 5
11 pr 6 7
12 problem 6 12
13 em 11 12


I need all possible combinations and the rule is; next word should start after previous word finish. From this sample I sould get;



"tem" "el" "problem"
"temel" "problem"


I will be grateful for guiding ideas...







r loops dataframe






share|improve this question













share|improve this question











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share|improve this question










asked Nov 13 '18 at 22:08









BoraxBorax

284




284








  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24














  • 1





    how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

    – user702846
    Nov 13 '18 at 22:16











  • Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

    – Borax
    Nov 13 '18 at 22:24








1




1





how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

– user702846
Nov 13 '18 at 22:16





how many sub-words ? your first example you have three sub-word, and in your second examples you have two. Can you clarify that in your question ?

– user702846
Nov 13 '18 at 22:16













Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

– Borax
Nov 13 '18 at 22:24





Number of sub-words are not important. Only rule is start-finish continuity. First combination is: tem(1:3)-el(4:5)-problem(6:12) and the second is: temel(1:5)-problem(6:12).

– Borax
Nov 13 '18 at 22:24












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