Bash Nested Private Functions
I am trying to create a custom Mac Terminal command, start, In Terminal, my intent is to write $ start func1 subfunc myText, where func is a function in the start.sh file and subfunc is a function only in func that can only be called from in func. So $ start subfunc myText wouldn't be possible. I see that its possible to pass a function from another (Here), but only when both are in the outer scope of the start.sh file.
Basically:
start.sh:
function func(){
function subfunc(){
echo $1
}
}
and then in Terminal:
$ start func subfunc Hey prints Hey
bash
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
add a comment |
I am trying to create a custom Mac Terminal command, start, In Terminal, my intent is to write $ start func1 subfunc myText, where func is a function in the start.sh file and subfunc is a function only in func that can only be called from in func. So $ start subfunc myText wouldn't be possible. I see that its possible to pass a function from another (Here), but only when both are in the outer scope of the start.sh file.
Basically:
start.sh:
function func(){
function subfunc(){
echo $1
}
}
and then in Terminal:
$ start func subfunc Hey prints Hey
bash
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
1
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
2
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't dostart subfunc myTextcan still dostart func subfunc Heydo still callsubfuncanyway. What problem are you trying to solve with this?
– P.P.
Nov 13 '18 at 21:58
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variablesif [$command = "func"]if [ $subcommand = "subfunc"]sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.
– JNevill
Nov 13 '18 at 22:06
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31
add a comment |
I am trying to create a custom Mac Terminal command, start, In Terminal, my intent is to write $ start func1 subfunc myText, where func is a function in the start.sh file and subfunc is a function only in func that can only be called from in func. So $ start subfunc myText wouldn't be possible. I see that its possible to pass a function from another (Here), but only when both are in the outer scope of the start.sh file.
Basically:
start.sh:
function func(){
function subfunc(){
echo $1
}
}
and then in Terminal:
$ start func subfunc Hey prints Hey
bash
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
I am trying to create a custom Mac Terminal command, start, In Terminal, my intent is to write $ start func1 subfunc myText, where func is a function in the start.sh file and subfunc is a function only in func that can only be called from in func. So $ start subfunc myText wouldn't be possible. I see that its possible to pass a function from another (Here), but only when both are in the outer scope of the start.sh file.
Basically:
start.sh:
function func(){
function subfunc(){
echo $1
}
}
and then in Terminal:
$ start func subfunc Hey prints Hey
bash
bash
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
edited Nov 13 '18 at 22:02
Ulrich Eckhardt
12.7k11737
12.7k11737
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
asked Nov 13 '18 at 21:36
Jasper BraunJasper Braun
12716
12716
1
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
2
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't dostart subfunc myTextcan still dostart func subfunc Heydo still callsubfuncanyway. What problem are you trying to solve with this?
– P.P.
Nov 13 '18 at 21:58
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variablesif [$command = "func"]if [ $subcommand = "subfunc"]sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.
– JNevill
Nov 13 '18 at 22:06
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31
add a comment |
1
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
2
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't dostart subfunc myTextcan still dostart func subfunc Heydo still callsubfuncanyway. What problem are you trying to solve with this?
– P.P.
Nov 13 '18 at 21:58
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variablesif [$command = "func"]if [ $subcommand = "subfunc"]sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.
– JNevill
Nov 13 '18 at 22:06
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31
1
1
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
2
2
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't do
start subfunc myText can still do start func subfunc Hey do still call subfunc anyway. What problem are you trying to solve with this?– P.P.
Nov 13 '18 at 21:58
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't do
start subfunc myText can still do start func subfunc Hey do still call subfunc anyway. What problem are you trying to solve with this?– P.P.
Nov 13 '18 at 21:58
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variables
if [$command = "func"] if [ $subcommand = "subfunc"] sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.– JNevill
Nov 13 '18 at 22:06
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variables
if [$command = "func"] if [ $subcommand = "subfunc"] sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.– JNevill
Nov 13 '18 at 22:06
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31
add a comment |
2 Answers
2
active
oldest
votes
You need to call the functions, not only declare them:
func() {
subfunc() {
echo "$1"
}
"$@"
}
"$@"
However functions have no scopes, so once you declare the function inside another function it overwrites the previous declaration. So I would advise so to make each function and sub-function name unique.
f() {
f() {
echo in
}
echo out
}
f // will print 'out'
f // will print 'in'
Note that using function name() {} is accepted, but not really valid. Use name() { }, as function name {} is not specified by posix.
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
add a comment |
You don't need nested functions for this. I think this is an argument parsing problem:
#!/bin/bash
start() {
case $1 in
func) shift; do_func "$@" ;;
*) echo "unknown subcommand"; exit 1 ;;
esac
}
do_func() {
case $1 in
subfunc) shift; do_subfunc "$@" ;;
*) echo "unknown sub-subcommand"; exit 1 ;;
esac
}
do_subfunc() {
echo "$1"
}
start "$@"
Then
$ ./start func foo
unknown sub-subcommand
$ ./start func subfunc 'hello world'
hello world
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to call the functions, not only declare them:
func() {
subfunc() {
echo "$1"
}
"$@"
}
"$@"
However functions have no scopes, so once you declare the function inside another function it overwrites the previous declaration. So I would advise so to make each function and sub-function name unique.
f() {
f() {
echo in
}
echo out
}
f // will print 'out'
f // will print 'in'
Note that using function name() {} is accepted, but not really valid. Use name() { }, as function name {} is not specified by posix.
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
add a comment |
You need to call the functions, not only declare them:
func() {
subfunc() {
echo "$1"
}
"$@"
}
"$@"
However functions have no scopes, so once you declare the function inside another function it overwrites the previous declaration. So I would advise so to make each function and sub-function name unique.
f() {
f() {
echo in
}
echo out
}
f // will print 'out'
f // will print 'in'
Note that using function name() {} is accepted, but not really valid. Use name() { }, as function name {} is not specified by posix.
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
add a comment |
You need to call the functions, not only declare them:
func() {
subfunc() {
echo "$1"
}
"$@"
}
"$@"
However functions have no scopes, so once you declare the function inside another function it overwrites the previous declaration. So I would advise so to make each function and sub-function name unique.
f() {
f() {
echo in
}
echo out
}
f // will print 'out'
f // will print 'in'
Note that using function name() {} is accepted, but not really valid. Use name() { }, as function name {} is not specified by posix.
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
You need to call the functions, not only declare them:
func() {
subfunc() {
echo "$1"
}
"$@"
}
"$@"
However functions have no scopes, so once you declare the function inside another function it overwrites the previous declaration. So I would advise so to make each function and sub-function name unique.
f() {
f() {
echo in
}
echo out
}
f // will print 'out'
f // will print 'in'
Note that using function name() {} is accepted, but not really valid. Use name() { }, as function name {} is not specified by posix.
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
answered Nov 13 '18 at 22:46
Kamil CukKamil Cuk
10.4k1527
10.4k1527
add a comment |
add a comment |
You don't need nested functions for this. I think this is an argument parsing problem:
#!/bin/bash
start() {
case $1 in
func) shift; do_func "$@" ;;
*) echo "unknown subcommand"; exit 1 ;;
esac
}
do_func() {
case $1 in
subfunc) shift; do_subfunc "$@" ;;
*) echo "unknown sub-subcommand"; exit 1 ;;
esac
}
do_subfunc() {
echo "$1"
}
start "$@"
Then
$ ./start func foo
unknown sub-subcommand
$ ./start func subfunc 'hello world'
hello world
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
add a comment |
You don't need nested functions for this. I think this is an argument parsing problem:
#!/bin/bash
start() {
case $1 in
func) shift; do_func "$@" ;;
*) echo "unknown subcommand"; exit 1 ;;
esac
}
do_func() {
case $1 in
subfunc) shift; do_subfunc "$@" ;;
*) echo "unknown sub-subcommand"; exit 1 ;;
esac
}
do_subfunc() {
echo "$1"
}
start "$@"
Then
$ ./start func foo
unknown sub-subcommand
$ ./start func subfunc 'hello world'
hello world
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
add a comment |
You don't need nested functions for this. I think this is an argument parsing problem:
#!/bin/bash
start() {
case $1 in
func) shift; do_func "$@" ;;
*) echo "unknown subcommand"; exit 1 ;;
esac
}
do_func() {
case $1 in
subfunc) shift; do_subfunc "$@" ;;
*) echo "unknown sub-subcommand"; exit 1 ;;
esac
}
do_subfunc() {
echo "$1"
}
start "$@"
Then
$ ./start func foo
unknown sub-subcommand
$ ./start func subfunc 'hello world'
hello world
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
You don't need nested functions for this. I think this is an argument parsing problem:
#!/bin/bash
start() {
case $1 in
func) shift; do_func "$@" ;;
*) echo "unknown subcommand"; exit 1 ;;
esac
}
do_func() {
case $1 in
subfunc) shift; do_subfunc "$@" ;;
*) echo "unknown sub-subcommand"; exit 1 ;;
esac
}
do_subfunc() {
echo "$1"
}
start "$@"
Then
$ ./start func foo
unknown sub-subcommand
$ ./start func subfunc 'hello world'
hello world
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
answered Nov 13 '18 at 23:04
glenn jackmanglenn jackman
167k26145237
167k26145237
add a comment |
add a comment |
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1
I don't think bash has nested function scopes like this.
– Barmar
Nov 13 '18 at 21:51
2
What is it supposed to achieve? Even if it works (it doesn't), Anyone who can't do
start subfunc myTextcan still dostart func subfunc Heydo still callsubfuncanyway. What problem are you trying to solve with this?– P.P.
Nov 13 '18 at 21:58
This feels like similar functionality to like an aws console command? I don't think bash is the right place to write this though. If you did, I think you would need to catch those arguments to variables and then perform logic based on what is in those variables
if [$command = "func"]if [ $subcommand = "subfunc"]sort of thing... IT may help if you explained what you are trying to achieve though since it's not clear from your very not-working code.– JNevill
Nov 13 '18 at 22:06
Sorry, I haven't used bash before and couldn't find great documentation for this. I was trying to create a custom hierarchy of commands to do something like nodecontroller nodestart node1 start, or something with a hierarchy of commands like this.
– Jasper Braun
Nov 14 '18 at 1:31