Avoiding a repeated handler call












0















I have the following in the html of an Angular project:



    <input type="text"
class="whatever"
(blur)="myEvent()"
(keyup.enter)="myEvent()">


This works, but the repetition of "myEvent()" feels like a DRY violation. Is there a way to link both blur and keyup.enter to that event without repeating the call?










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  • You should take care of your OCD problem first :)

    – Aviad P.
    Nov 14 '18 at 18:17











  • I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

    – John Montgomery
    Nov 14 '18 at 19:33
















0















I have the following in the html of an Angular project:



    <input type="text"
class="whatever"
(blur)="myEvent()"
(keyup.enter)="myEvent()">


This works, but the repetition of "myEvent()" feels like a DRY violation. Is there a way to link both blur and keyup.enter to that event without repeating the call?










share|improve this question























  • You should take care of your OCD problem first :)

    – Aviad P.
    Nov 14 '18 at 18:17











  • I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

    – John Montgomery
    Nov 14 '18 at 19:33














0












0








0








I have the following in the html of an Angular project:



    <input type="text"
class="whatever"
(blur)="myEvent()"
(keyup.enter)="myEvent()">


This works, but the repetition of "myEvent()" feels like a DRY violation. Is there a way to link both blur and keyup.enter to that event without repeating the call?










share|improve this question














I have the following in the html of an Angular project:



    <input type="text"
class="whatever"
(blur)="myEvent()"
(keyup.enter)="myEvent()">


This works, but the repetition of "myEvent()" feels like a DRY violation. Is there a way to link both blur and keyup.enter to that event without repeating the call?







html angular events






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asked Nov 14 '18 at 18:01









William JockuschWilliam Jockusch

8,97041155268




8,97041155268













  • You should take care of your OCD problem first :)

    – Aviad P.
    Nov 14 '18 at 18:17











  • I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

    – John Montgomery
    Nov 14 '18 at 19:33



















  • You should take care of your OCD problem first :)

    – Aviad P.
    Nov 14 '18 at 18:17











  • I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

    – John Montgomery
    Nov 14 '18 at 19:33

















You should take care of your OCD problem first :)

– Aviad P.
Nov 14 '18 at 18:17





You should take care of your OCD problem first :)

– Aviad P.
Nov 14 '18 at 18:17













I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

– John Montgomery
Nov 14 '18 at 19:33





I can't think of any way to do this that wouldn't be significantly messier than the normal way. Best to just deal with it.

– John Montgomery
Nov 14 '18 at 19:33












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Based on the comment and the lack of another answer, I'm assuming the answer is "no, there is no way to do that."






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    1 Answer
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    1 Answer
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    active

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    active

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    0














    Based on the comment and the lack of another answer, I'm assuming the answer is "no, there is no way to do that."






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      0














      Based on the comment and the lack of another answer, I'm assuming the answer is "no, there is no way to do that."






      share|improve this answer


























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        0







        Based on the comment and the lack of another answer, I'm assuming the answer is "no, there is no way to do that."






        share|improve this answer













        Based on the comment and the lack of another answer, I'm assuming the answer is "no, there is no way to do that."







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 14 '18 at 19:28









        William JockuschWilliam Jockusch

        8,97041155268




        8,97041155268
































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