Model many-to-many over three tables in SQLAlchemy











up vote
0
down vote

favorite












I have difficulty to model these relations.



There is products, each one belonging to a product_type. Product_types have a list of different features eg. color, size, weight, volume, in a relation of many-to-many. In their turn, each features have differents feature_options eg. red, blue, green, black for colors. Finally products have some of the feature_options. One example should be the product BIC2006 which have the product_type pen, whose features are color and weight, and which has in these features the feature_options red and blue for the color and 1g and 2g for the weight.



At the end I would like to store the feature_options by products and query by products the list of feature_options by feature :



BIC2006 - Pen



Color : Red, Blue



Weight : 1g, 2g



What should be the best DB model to use with SQLAlchemy?



For now, as I need to store the feature_options by products I tried with this, but I'm not sure about how to retrieve the sort by features :



class ProductTypes_Features(Base):
__tablename__ = 'product_types_features'
product_type_id = Column(Integer, ForeignKey('product_types.id'), primary_key=True)
feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)

class Feature_FeatureOptions(Base):
__tablename__ = 'feature_feature_options'
feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)
feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)

class Product_FeatureOptions(Base):
__tablename__ = 'product_feature_options'
product_id = Column(Integer, ForeignKey('products.id'), primary_key=True)
feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)
feature_id = Column(Integer, ForeignKey('features.id')) #??

class Products(Base):
__tablename__ = 'product'
id = Column(Integer, primary_key=True)
product_type_id = Column(Integer, ForeignKey('product_types.id'))
feature_options = relationship("Product_FeatureOptions")

class FeatureOptions(Base):
__tablename__ = 'feature_options'
id = Column(Integer, primary_key=True)

class Features(Base):
__tablename__ = 'features'
id = Column(Integer, primary_key=True)
feature_options = relationship("Feature_FeatureOptions")

class ProductTypes(Base):
__tablename__ = 'product_types'
id = Column(Integer, primary_key=True)
features = relationship("ProductType_Features")


How can I query?



session.query(Products.id, 
Products.feature_options.feature_id,
Products.feature_options.feature_option_id).
order_by(...).all()


Thanks a lot for your best practices advices!










share|improve this question


























    up vote
    0
    down vote

    favorite












    I have difficulty to model these relations.



    There is products, each one belonging to a product_type. Product_types have a list of different features eg. color, size, weight, volume, in a relation of many-to-many. In their turn, each features have differents feature_options eg. red, blue, green, black for colors. Finally products have some of the feature_options. One example should be the product BIC2006 which have the product_type pen, whose features are color and weight, and which has in these features the feature_options red and blue for the color and 1g and 2g for the weight.



    At the end I would like to store the feature_options by products and query by products the list of feature_options by feature :



    BIC2006 - Pen



    Color : Red, Blue



    Weight : 1g, 2g



    What should be the best DB model to use with SQLAlchemy?



    For now, as I need to store the feature_options by products I tried with this, but I'm not sure about how to retrieve the sort by features :



    class ProductTypes_Features(Base):
    __tablename__ = 'product_types_features'
    product_type_id = Column(Integer, ForeignKey('product_types.id'), primary_key=True)
    feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)

    class Feature_FeatureOptions(Base):
    __tablename__ = 'feature_feature_options'
    feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)
    feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)

    class Product_FeatureOptions(Base):
    __tablename__ = 'product_feature_options'
    product_id = Column(Integer, ForeignKey('products.id'), primary_key=True)
    feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)
    feature_id = Column(Integer, ForeignKey('features.id')) #??

    class Products(Base):
    __tablename__ = 'product'
    id = Column(Integer, primary_key=True)
    product_type_id = Column(Integer, ForeignKey('product_types.id'))
    feature_options = relationship("Product_FeatureOptions")

    class FeatureOptions(Base):
    __tablename__ = 'feature_options'
    id = Column(Integer, primary_key=True)

    class Features(Base):
    __tablename__ = 'features'
    id = Column(Integer, primary_key=True)
    feature_options = relationship("Feature_FeatureOptions")

    class ProductTypes(Base):
    __tablename__ = 'product_types'
    id = Column(Integer, primary_key=True)
    features = relationship("ProductType_Features")


    How can I query?



    session.query(Products.id, 
    Products.feature_options.feature_id,
    Products.feature_options.feature_option_id).
    order_by(...).all()


    Thanks a lot for your best practices advices!










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have difficulty to model these relations.



      There is products, each one belonging to a product_type. Product_types have a list of different features eg. color, size, weight, volume, in a relation of many-to-many. In their turn, each features have differents feature_options eg. red, blue, green, black for colors. Finally products have some of the feature_options. One example should be the product BIC2006 which have the product_type pen, whose features are color and weight, and which has in these features the feature_options red and blue for the color and 1g and 2g for the weight.



      At the end I would like to store the feature_options by products and query by products the list of feature_options by feature :



      BIC2006 - Pen



      Color : Red, Blue



      Weight : 1g, 2g



      What should be the best DB model to use with SQLAlchemy?



      For now, as I need to store the feature_options by products I tried with this, but I'm not sure about how to retrieve the sort by features :



      class ProductTypes_Features(Base):
      __tablename__ = 'product_types_features'
      product_type_id = Column(Integer, ForeignKey('product_types.id'), primary_key=True)
      feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)

      class Feature_FeatureOptions(Base):
      __tablename__ = 'feature_feature_options'
      feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)
      feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)

      class Product_FeatureOptions(Base):
      __tablename__ = 'product_feature_options'
      product_id = Column(Integer, ForeignKey('products.id'), primary_key=True)
      feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)
      feature_id = Column(Integer, ForeignKey('features.id')) #??

      class Products(Base):
      __tablename__ = 'product'
      id = Column(Integer, primary_key=True)
      product_type_id = Column(Integer, ForeignKey('product_types.id'))
      feature_options = relationship("Product_FeatureOptions")

      class FeatureOptions(Base):
      __tablename__ = 'feature_options'
      id = Column(Integer, primary_key=True)

      class Features(Base):
      __tablename__ = 'features'
      id = Column(Integer, primary_key=True)
      feature_options = relationship("Feature_FeatureOptions")

      class ProductTypes(Base):
      __tablename__ = 'product_types'
      id = Column(Integer, primary_key=True)
      features = relationship("ProductType_Features")


      How can I query?



      session.query(Products.id, 
      Products.feature_options.feature_id,
      Products.feature_options.feature_option_id).
      order_by(...).all()


      Thanks a lot for your best practices advices!










      share|improve this question













      I have difficulty to model these relations.



      There is products, each one belonging to a product_type. Product_types have a list of different features eg. color, size, weight, volume, in a relation of many-to-many. In their turn, each features have differents feature_options eg. red, blue, green, black for colors. Finally products have some of the feature_options. One example should be the product BIC2006 which have the product_type pen, whose features are color and weight, and which has in these features the feature_options red and blue for the color and 1g and 2g for the weight.



      At the end I would like to store the feature_options by products and query by products the list of feature_options by feature :



      BIC2006 - Pen



      Color : Red, Blue



      Weight : 1g, 2g



      What should be the best DB model to use with SQLAlchemy?



      For now, as I need to store the feature_options by products I tried with this, but I'm not sure about how to retrieve the sort by features :



      class ProductTypes_Features(Base):
      __tablename__ = 'product_types_features'
      product_type_id = Column(Integer, ForeignKey('product_types.id'), primary_key=True)
      feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)

      class Feature_FeatureOptions(Base):
      __tablename__ = 'feature_feature_options'
      feature_id = Column(Integer, ForeignKey('features.id'), primary_key=True)
      feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)

      class Product_FeatureOptions(Base):
      __tablename__ = 'product_feature_options'
      product_id = Column(Integer, ForeignKey('products.id'), primary_key=True)
      feature_options_id = Column(Integer, ForeignKey('feature_options.id'), primary_key=True)
      feature_id = Column(Integer, ForeignKey('features.id')) #??

      class Products(Base):
      __tablename__ = 'product'
      id = Column(Integer, primary_key=True)
      product_type_id = Column(Integer, ForeignKey('product_types.id'))
      feature_options = relationship("Product_FeatureOptions")

      class FeatureOptions(Base):
      __tablename__ = 'feature_options'
      id = Column(Integer, primary_key=True)

      class Features(Base):
      __tablename__ = 'features'
      id = Column(Integer, primary_key=True)
      feature_options = relationship("Feature_FeatureOptions")

      class ProductTypes(Base):
      __tablename__ = 'product_types'
      id = Column(Integer, primary_key=True)
      features = relationship("ProductType_Features")


      How can I query?



      session.query(Products.id, 
      Products.feature_options.feature_id,
      Products.feature_options.feature_option_id).
      order_by(...).all()


      Thanks a lot for your best practices advices!







      python sql sqlalchemy






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 at 20:00









      Romain

      263




      263





























          active

          oldest

          votes











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














           

          draft saved


          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53242899%2fmodel-many-to-many-over-three-tables-in-sqlalchemy%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















           

          draft saved


          draft discarded



















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53242899%2fmodel-many-to-many-over-three-tables-in-sqlalchemy%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Florida Star v. B. J. F.

          Danny Elfman

          Lugert, Oklahoma