Trying to understand how eval(expr, envir = df) works












0















I have built a function which seems to work, but I don't understand why.



My initial problem was to take a data.frame which contains counts of a population and expand it to re-create the original population. This is easy enough if you know the column names in advance.



      library(tidyverse)

set.seed(121)

test_counts <- tibble(Population = letters[1:4], Length = c(1,1,2,1),
Number = sample(1:100, 4))

expand_counts_v0 <- function(Length, Population, Number) {
tibble(Population = Population,
Length = rep(Length, times = Number))

}


test_counts %>% pmap_dfr(expand_counts_v0) %>% # apply it
group_by(Population, Length) %>% # test it
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE


However, I wanted to generalise it to a function which didn't need to know at the column names of the data.frame, and I'm interested in NSE, so I wrote:



test_counts1 <- tibble(Population = letters[1:4], 
Length = c(1,1,2,1),
Number = sample(1:100, 4),
Height = c(100, 50, 45, 90),
Width = c(700, 50, 60, 90)
)


expand_counts_v1 <- function(df, count = NULL) {
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% pmap_dfr(make_tbl)
}


But, when I test this function it seems to duplicate rows 4 times:



   test_counts %>% expand_counts_v1(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ sum(.$Number)/sum(test_counts$Number)}
# [1] 4


This lead me to guess a solution, which was



   expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% make_tbl
}


This seems to work:



 test_counts %>% expand_counts_v2(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE

test_counts1 %>% expand_counts_v2(count = Number) %>%
group_by(Population, Length, Height, Width) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts1)}
# [1] TRUE


But I don't understand why. How is it evaluating for each row, even though I'm not using pmap anymore? The function needs to be applied to each row in order to work, so it must be somehow, but I can't see how it's doing that.



EDIT



After Artem's correct explanation of what was going on, I realised I could do this



expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

expr(tibble(!!!cols)) %>% eval_tidy(data = df)
}


Which gets rid of the unnecessary mk_tbl function. However, as Artem said, that is only really working because rep is vectorised. So, it's working, but not by re-writing the _v0 function and pmapping it, which is the process I was trying to replicate. Eventually, I discovered, rlang::new_function and wrote:



expand_counts_v3 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

all_names <- df %>% names %>% map(as.name)
args <- rep(0, times = length(all_names)) %>% as.list %>% set_names(all_names)

correct_function <- new_function(args, # this makes the function as in _v0
expr(tibble(!!!cols)) )
pmap_dfr(df, correct_function) # applies it as in _v0
}


which is longer, and probably uglier, but works the way I originally wanted.










share|improve this question

























  • I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

    – Konrad Rudolph
    Nov 13 '18 at 14:55











  • Thank you Konrad. I'll update the names now.

    – Tom Greenwood
    Nov 14 '18 at 11:28
















0















I have built a function which seems to work, but I don't understand why.



My initial problem was to take a data.frame which contains counts of a population and expand it to re-create the original population. This is easy enough if you know the column names in advance.



      library(tidyverse)

set.seed(121)

test_counts <- tibble(Population = letters[1:4], Length = c(1,1,2,1),
Number = sample(1:100, 4))

expand_counts_v0 <- function(Length, Population, Number) {
tibble(Population = Population,
Length = rep(Length, times = Number))

}


test_counts %>% pmap_dfr(expand_counts_v0) %>% # apply it
group_by(Population, Length) %>% # test it
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE


However, I wanted to generalise it to a function which didn't need to know at the column names of the data.frame, and I'm interested in NSE, so I wrote:



test_counts1 <- tibble(Population = letters[1:4], 
Length = c(1,1,2,1),
Number = sample(1:100, 4),
Height = c(100, 50, 45, 90),
Width = c(700, 50, 60, 90)
)


expand_counts_v1 <- function(df, count = NULL) {
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% pmap_dfr(make_tbl)
}


But, when I test this function it seems to duplicate rows 4 times:



   test_counts %>% expand_counts_v1(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ sum(.$Number)/sum(test_counts$Number)}
# [1] 4


This lead me to guess a solution, which was



   expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% make_tbl
}


This seems to work:



 test_counts %>% expand_counts_v2(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE

test_counts1 %>% expand_counts_v2(count = Number) %>%
group_by(Population, Length, Height, Width) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts1)}
# [1] TRUE


But I don't understand why. How is it evaluating for each row, even though I'm not using pmap anymore? The function needs to be applied to each row in order to work, so it must be somehow, but I can't see how it's doing that.



EDIT



After Artem's correct explanation of what was going on, I realised I could do this



expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

expr(tibble(!!!cols)) %>% eval_tidy(data = df)
}


Which gets rid of the unnecessary mk_tbl function. However, as Artem said, that is only really working because rep is vectorised. So, it's working, but not by re-writing the _v0 function and pmapping it, which is the process I was trying to replicate. Eventually, I discovered, rlang::new_function and wrote:



expand_counts_v3 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

all_names <- df %>% names %>% map(as.name)
args <- rep(0, times = length(all_names)) %>% as.list %>% set_names(all_names)

correct_function <- new_function(args, # this makes the function as in _v0
expr(tibble(!!!cols)) )
pmap_dfr(df, correct_function) # applies it as in _v0
}


which is longer, and probably uglier, but works the way I originally wanted.










share|improve this question

























  • I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

    – Konrad Rudolph
    Nov 13 '18 at 14:55











  • Thank you Konrad. I'll update the names now.

    – Tom Greenwood
    Nov 14 '18 at 11:28














0












0








0








I have built a function which seems to work, but I don't understand why.



My initial problem was to take a data.frame which contains counts of a population and expand it to re-create the original population. This is easy enough if you know the column names in advance.



      library(tidyverse)

set.seed(121)

test_counts <- tibble(Population = letters[1:4], Length = c(1,1,2,1),
Number = sample(1:100, 4))

expand_counts_v0 <- function(Length, Population, Number) {
tibble(Population = Population,
Length = rep(Length, times = Number))

}


test_counts %>% pmap_dfr(expand_counts_v0) %>% # apply it
group_by(Population, Length) %>% # test it
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE


However, I wanted to generalise it to a function which didn't need to know at the column names of the data.frame, and I'm interested in NSE, so I wrote:



test_counts1 <- tibble(Population = letters[1:4], 
Length = c(1,1,2,1),
Number = sample(1:100, 4),
Height = c(100, 50, 45, 90),
Width = c(700, 50, 60, 90)
)


expand_counts_v1 <- function(df, count = NULL) {
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% pmap_dfr(make_tbl)
}


But, when I test this function it seems to duplicate rows 4 times:



   test_counts %>% expand_counts_v1(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ sum(.$Number)/sum(test_counts$Number)}
# [1] 4


This lead me to guess a solution, which was



   expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% make_tbl
}


This seems to work:



 test_counts %>% expand_counts_v2(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE

test_counts1 %>% expand_counts_v2(count = Number) %>%
group_by(Population, Length, Height, Width) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts1)}
# [1] TRUE


But I don't understand why. How is it evaluating for each row, even though I'm not using pmap anymore? The function needs to be applied to each row in order to work, so it must be somehow, but I can't see how it's doing that.



EDIT



After Artem's correct explanation of what was going on, I realised I could do this



expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

expr(tibble(!!!cols)) %>% eval_tidy(data = df)
}


Which gets rid of the unnecessary mk_tbl function. However, as Artem said, that is only really working because rep is vectorised. So, it's working, but not by re-writing the _v0 function and pmapping it, which is the process I was trying to replicate. Eventually, I discovered, rlang::new_function and wrote:



expand_counts_v3 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

all_names <- df %>% names %>% map(as.name)
args <- rep(0, times = length(all_names)) %>% as.list %>% set_names(all_names)

correct_function <- new_function(args, # this makes the function as in _v0
expr(tibble(!!!cols)) )
pmap_dfr(df, correct_function) # applies it as in _v0
}


which is longer, and probably uglier, but works the way I originally wanted.










share|improve this question
















I have built a function which seems to work, but I don't understand why.



My initial problem was to take a data.frame which contains counts of a population and expand it to re-create the original population. This is easy enough if you know the column names in advance.



      library(tidyverse)

set.seed(121)

test_counts <- tibble(Population = letters[1:4], Length = c(1,1,2,1),
Number = sample(1:100, 4))

expand_counts_v0 <- function(Length, Population, Number) {
tibble(Population = Population,
Length = rep(Length, times = Number))

}


test_counts %>% pmap_dfr(expand_counts_v0) %>% # apply it
group_by(Population, Length) %>% # test it
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE


However, I wanted to generalise it to a function which didn't need to know at the column names of the data.frame, and I'm interested in NSE, so I wrote:



test_counts1 <- tibble(Population = letters[1:4], 
Length = c(1,1,2,1),
Number = sample(1:100, 4),
Height = c(100, 50, 45, 90),
Width = c(700, 50, 60, 90)
)


expand_counts_v1 <- function(df, count = NULL) {
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% pmap_dfr(make_tbl)
}


But, when I test this function it seems to duplicate rows 4 times:



   test_counts %>% expand_counts_v1(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ sum(.$Number)/sum(test_counts$Number)}
# [1] 4


This lead me to guess a solution, which was



   expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

make_tbl <- function(...) {
expr(tibble(!!!cols)) %>% eval(envir = df)
}

df %>% make_tbl
}


This seems to work:



 test_counts %>% expand_counts_v2(count = Number) %>% 
group_by(Population, Length) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts)}
# [1] TRUE

test_counts1 %>% expand_counts_v2(count = Number) %>%
group_by(Population, Length, Height, Width) %>%
summarise(Number = n()) %>%
ungroup %>%
{ all.equal(., test_counts1)}
# [1] TRUE


But I don't understand why. How is it evaluating for each row, even though I'm not using pmap anymore? The function needs to be applied to each row in order to work, so it must be somehow, but I can't see how it's doing that.



EDIT



After Artem's correct explanation of what was going on, I realised I could do this



expand_counts_v2 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

expr(tibble(!!!cols)) %>% eval_tidy(data = df)
}


Which gets rid of the unnecessary mk_tbl function. However, as Artem said, that is only really working because rep is vectorised. So, it's working, but not by re-writing the _v0 function and pmapping it, which is the process I was trying to replicate. Eventually, I discovered, rlang::new_function and wrote:



expand_counts_v3 <- function(df, count = NULL) { 
countq <- enexpr(count)
names <- df %>% select(-!!countq) %>% names
namesq <- names %>% map(as.name)

cols <- map(namesq, ~ expr(rep(!!., times = !!countq))
) %>% set_names(namesq)

all_names <- df %>% names %>% map(as.name)
args <- rep(0, times = length(all_names)) %>% as.list %>% set_names(all_names)

correct_function <- new_function(args, # this makes the function as in _v0
expr(tibble(!!!cols)) )
pmap_dfr(df, correct_function) # applies it as in _v0
}


which is longer, and probably uglier, but works the way I originally wanted.







r eval tidyverse rlang expr






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 15:59







Tom Greenwood

















asked Nov 13 '18 at 12:00









Tom GreenwoodTom Greenwood

185




185













  • I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

    – Konrad Rudolph
    Nov 13 '18 at 14:55











  • Thank you Konrad. I'll update the names now.

    – Tom Greenwood
    Nov 14 '18 at 11:28



















  • I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

    – Konrad Rudolph
    Nov 13 '18 at 14:55











  • Thank you Konrad. I'll update the names now.

    – Tom Greenwood
    Nov 14 '18 at 11:28

















I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

– Konrad Rudolph
Nov 13 '18 at 14:55





I urge you to avoid dots in names: first off, keep it consistent; since you already use underscores, use these exclusively. Secondly, using dots in names has a specific meaning in the context of S3 method lookup, and using dots independently from that leads to confusion.

– Konrad Rudolph
Nov 13 '18 at 14:55













Thank you Konrad. I'll update the names now.

– Tom Greenwood
Nov 14 '18 at 11:28





Thank you Konrad. I'll update the names now.

– Tom Greenwood
Nov 14 '18 at 11:28












1 Answer
1






active

oldest

votes


















0














The issue is in eval( envir = df ), which exposes the entire data frame to make_tbl(). Notice that you never use ... argument inside make_tbl(). Instead, the function effectively computes the equivalent of



with( df, tibble(Population = rep(Population, times = Number), 
Length = rep(Length, times=Number)) )


regardless of what arguments you provide to it. When you call the function via pmap_dfr(), it essentially computes the above four times (once for each row) and concatenates the results by-row, resulting in the duplication of entries you've observed. When you remove pmap_dfr(), the function is called once, but since rep is itself vectorized (try doing rep( test_counts$Population, test_counts$Number ) to see what I mean), make_tbl() computes the entire result in one go.






share|improve this answer





















  • 1





    Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

    – Tom Greenwood
    Nov 16 '18 at 15:50











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














The issue is in eval( envir = df ), which exposes the entire data frame to make_tbl(). Notice that you never use ... argument inside make_tbl(). Instead, the function effectively computes the equivalent of



with( df, tibble(Population = rep(Population, times = Number), 
Length = rep(Length, times=Number)) )


regardless of what arguments you provide to it. When you call the function via pmap_dfr(), it essentially computes the above four times (once for each row) and concatenates the results by-row, resulting in the duplication of entries you've observed. When you remove pmap_dfr(), the function is called once, but since rep is itself vectorized (try doing rep( test_counts$Population, test_counts$Number ) to see what I mean), make_tbl() computes the entire result in one go.






share|improve this answer





















  • 1





    Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

    – Tom Greenwood
    Nov 16 '18 at 15:50
















0














The issue is in eval( envir = df ), which exposes the entire data frame to make_tbl(). Notice that you never use ... argument inside make_tbl(). Instead, the function effectively computes the equivalent of



with( df, tibble(Population = rep(Population, times = Number), 
Length = rep(Length, times=Number)) )


regardless of what arguments you provide to it. When you call the function via pmap_dfr(), it essentially computes the above four times (once for each row) and concatenates the results by-row, resulting in the duplication of entries you've observed. When you remove pmap_dfr(), the function is called once, but since rep is itself vectorized (try doing rep( test_counts$Population, test_counts$Number ) to see what I mean), make_tbl() computes the entire result in one go.






share|improve this answer





















  • 1





    Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

    – Tom Greenwood
    Nov 16 '18 at 15:50














0












0








0







The issue is in eval( envir = df ), which exposes the entire data frame to make_tbl(). Notice that you never use ... argument inside make_tbl(). Instead, the function effectively computes the equivalent of



with( df, tibble(Population = rep(Population, times = Number), 
Length = rep(Length, times=Number)) )


regardless of what arguments you provide to it. When you call the function via pmap_dfr(), it essentially computes the above four times (once for each row) and concatenates the results by-row, resulting in the duplication of entries you've observed. When you remove pmap_dfr(), the function is called once, but since rep is itself vectorized (try doing rep( test_counts$Population, test_counts$Number ) to see what I mean), make_tbl() computes the entire result in one go.






share|improve this answer















The issue is in eval( envir = df ), which exposes the entire data frame to make_tbl(). Notice that you never use ... argument inside make_tbl(). Instead, the function effectively computes the equivalent of



with( df, tibble(Population = rep(Population, times = Number), 
Length = rep(Length, times=Number)) )


regardless of what arguments you provide to it. When you call the function via pmap_dfr(), it essentially computes the above four times (once for each row) and concatenates the results by-row, resulting in the duplication of entries you've observed. When you remove pmap_dfr(), the function is called once, but since rep is itself vectorized (try doing rep( test_counts$Population, test_counts$Number ) to see what I mean), make_tbl() computes the entire result in one go.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 15 '18 at 22:01

























answered Nov 15 '18 at 21:54









Artem SokolovArtem Sokolov

4,77221936




4,77221936








  • 1





    Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

    – Tom Greenwood
    Nov 16 '18 at 15:50














  • 1





    Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

    – Tom Greenwood
    Nov 16 '18 at 15:50








1




1





Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

– Tom Greenwood
Nov 16 '18 at 15:50





Thank you Artem, you explained it brilliantly. I'm just going to add some new versions I made, after reading your explanation.

– Tom Greenwood
Nov 16 '18 at 15:50


















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