PyQt Dialog box activateWindow() works, but not when its parent window is open
Our PyQt application's dialog box is called from a Windows Explorer window, and naturally is supposed to jump to the front when it is created. This works great in a vacuum - the dialog window successfully jumps in front of the Explorer window, using the following code:
def bring_to_foreground(qwidget):
qwidget.show()
qwidget.raise_()
qwidget.activateWindow()
However, when the application's main window (which is a parent of the dialog window) is open, the dialog window cannot jump to the front.
Can anyone explain this behavior?
From the PyQt4 documentation, I can see that:
On Windows, if you are calling this when the application is not currently the active one then it will not make it the active window. It will change the color of the taskbar entry to indicate that the window has changed in some way. This is because Microsoft does not allow an application to interrupt what the user is currently doing in another application.
I guess that answers my question, but then why does our function work normally the rest of the time?
python-2.7 pyqt4
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
add a comment |
Our PyQt application's dialog box is called from a Windows Explorer window, and naturally is supposed to jump to the front when it is created. This works great in a vacuum - the dialog window successfully jumps in front of the Explorer window, using the following code:
def bring_to_foreground(qwidget):
qwidget.show()
qwidget.raise_()
qwidget.activateWindow()
However, when the application's main window (which is a parent of the dialog window) is open, the dialog window cannot jump to the front.
Can anyone explain this behavior?
From the PyQt4 documentation, I can see that:
On Windows, if you are calling this when the application is not currently the active one then it will not make it the active window. It will change the color of the taskbar entry to indicate that the window has changed in some way. This is because Microsoft does not allow an application to interrupt what the user is currently doing in another application.
I guess that answers my question, but then why does our function work normally the rest of the time?
python-2.7 pyqt4
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
add a comment |
Our PyQt application's dialog box is called from a Windows Explorer window, and naturally is supposed to jump to the front when it is created. This works great in a vacuum - the dialog window successfully jumps in front of the Explorer window, using the following code:
def bring_to_foreground(qwidget):
qwidget.show()
qwidget.raise_()
qwidget.activateWindow()
However, when the application's main window (which is a parent of the dialog window) is open, the dialog window cannot jump to the front.
Can anyone explain this behavior?
From the PyQt4 documentation, I can see that:
On Windows, if you are calling this when the application is not currently the active one then it will not make it the active window. It will change the color of the taskbar entry to indicate that the window has changed in some way. This is because Microsoft does not allow an application to interrupt what the user is currently doing in another application.
I guess that answers my question, but then why does our function work normally the rest of the time?
python-2.7 pyqt4
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
Our PyQt application's dialog box is called from a Windows Explorer window, and naturally is supposed to jump to the front when it is created. This works great in a vacuum - the dialog window successfully jumps in front of the Explorer window, using the following code:
def bring_to_foreground(qwidget):
qwidget.show()
qwidget.raise_()
qwidget.activateWindow()
However, when the application's main window (which is a parent of the dialog window) is open, the dialog window cannot jump to the front.
Can anyone explain this behavior?
From the PyQt4 documentation, I can see that:
On Windows, if you are calling this when the application is not currently the active one then it will not make it the active window. It will change the color of the taskbar entry to indicate that the window has changed in some way. This is because Microsoft does not allow an application to interrupt what the user is currently doing in another application.
I guess that answers my question, but then why does our function work normally the rest of the time?
python-2.7 pyqt4
python-2.7 pyqt4
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
asked Nov 13 '18 at 18:50
Ben QuigleyBen Quigley
382112
382112
add a comment |
add a comment |
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