How to search item using key in object and update that value into the array?
1
var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];As per the snippet I have two array:
replaceArr and originalArr
I want to compare the replaceArr with the originalArr and get the key value from there and replace into the replaceArr.
Means after replacing the replaceArr would be == [0,10,11,9,1]
In Advanced Thanks..
javascript arrays
edited Nov 12 '18 at 14:45
Gordon A.
627
asked Nov 12 '18 at 13:13
Sachin
102
add a comment |
1
var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];As per the snippet I have two array:
replaceArr and originalArr
I want to compare the replaceArr with the originalArr and get the key value from there and replace into the replaceArr.
Means after replacing the replaceArr would be == [0,10,11,9,1]
In Advanced Thanks..
javascript arrays
edited Nov 12 '18 at 14:45
Gordon A.
627
asked Nov 12 '18 at 13:13
Sachin
102
add a comment |
1
1
1
var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];As per the snippet I have two array:
replaceArr and originalArr
I want to compare the replaceArr with the originalArr and get the key value from there and replace into the replaceArr.
Means after replacing the replaceArr would be == [0,10,11,9,1]
In Advanced Thanks..
javascript arrays
edited Nov 12 '18 at 14:45
Gordon A.
627
asked Nov 12 '18 at 13:13
Sachin
102
var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];As per the snippet I have two array:
replaceArr and originalArr
I want to compare the replaceArr with the originalArr and get the key value from there and replace into the replaceArr.
Means after replacing the replaceArr would be == [0,10,11,9,1]
In Advanced Thanks..
var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];var replaceArr = ['A','J','Q',10,2];
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];javascript arrays
javascript arrays
edited Nov 12 '18 at 14:45
Gordon A.
627
asked Nov 12 '18 at 13:13
Sachin
102
edited Nov 12 '18 at 14:45
Gordon A.
627
asked Nov 12 '18 at 13:13
Sachin
102
edited Nov 12 '18 at 14:45
Gordon A.
627
edited Nov 12 '18 at 14:45
Gordon A.
627
edited Nov 12 '18 at 14:45
Gordon A.
627
627
asked Nov 12 '18 at 13:13
Sachin
102
asked Nov 12 '18 at 13:13
Sachin
102
asked Nov 12 '18 at 13:13
Sachin
102
102
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
1
you can simple use map and find from array prototype
var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
add a comment |
0
You can club all the different objects in originalArr and then search for replaceArr values in it like below
var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
add a comment |
0
You can use javascript array foreach function
originalArr.forEach((val) => {
var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]);
if (replaceIndex >= 0) {
replaceArr[replaceIndex] = val[Object.keys(val)[0]];
}
});
answered Nov 12 '18 at 13:28
Ali Khan
607
it displays wrong result[0, 10, 11, 10, 2], the correct result should be[0,10,11,9,1]
– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
add a comment |
0
var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
you can simple use map and find from array prototype
var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
add a comment |
1
you can simple use map and find from array prototype
var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
add a comment |
1
1
1
you can simple use map and find from array prototype
var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
you can simple use map and find from array prototype
var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);var replaceArr = ["A", "J","Q",10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}];
replaceArr = replaceArr.map(v => originalArr.find(obj => obj[v] !== undefined)[v]);
console.log(replaceArr);answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
answered Nov 12 '18 at 13:20
Artyom Amiryan
1,825113
1,825113
add a comment |
add a comment |
0
You can club all the different objects in originalArr and then search for replaceArr values in it like below
var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
add a comment |
0
You can club all the different objects in originalArr and then search for replaceArr values in it like below
var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
add a comment |
0
0
0
You can club all the different objects in originalArr and then search for replaceArr values in it like below
var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
You can club all the different objects in originalArr and then search for replaceArr values in it like below
var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)var replaceArr = ['A','J','Q',10,2]
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
let arrWithOneObject = Object.assign(...originalArr)
let result = replaceArr.map(d => arrWithOneObject[d])
console.log(result)answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
answered Nov 12 '18 at 13:21
Nitish Narang
2,948815
2,948815
add a comment |
add a comment |
0
You can use javascript array foreach function
originalArr.forEach((val) => {
var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]);
if (replaceIndex >= 0) {
replaceArr[replaceIndex] = val[Object.keys(val)[0]];
}
});
answered Nov 12 '18 at 13:28
Ali Khan
607
it displays wrong result[0, 10, 11, 10, 2], the correct result should be[0,10,11,9,1]
– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
add a comment |
0
You can use javascript array foreach function
originalArr.forEach((val) => {
var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]);
if (replaceIndex >= 0) {
replaceArr[replaceIndex] = val[Object.keys(val)[0]];
}
});
answered Nov 12 '18 at 13:28
Ali Khan
607
it displays wrong result[0, 10, 11, 10, 2], the correct result should be[0,10,11,9,1]
– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
add a comment |
0
0
0
You can use javascript array foreach function
originalArr.forEach((val) => {
var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]);
if (replaceIndex >= 0) {
replaceArr[replaceIndex] = val[Object.keys(val)[0]];
}
});
answered Nov 12 '18 at 13:28
Ali Khan
607
You can use javascript array foreach function
originalArr.forEach((val) => {
var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]);
if (replaceIndex >= 0) {
replaceArr[replaceIndex] = val[Object.keys(val)[0]];
}
});
answered Nov 12 '18 at 13:28
Ali Khan
607
answered Nov 12 '18 at 13:28
Ali Khan
607
answered Nov 12 '18 at 13:28
Ali Khan
607
answered Nov 12 '18 at 13:28
Ali Khan
607
607
it displays wrong result[0, 10, 11, 10, 2], the correct result should be[0,10,11,9,1]
– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
add a comment |
it displays wrong result[0, 10, 11, 10, 2], the correct result should be[0,10,11,9,1]
– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
it displays wrong result
[0, 10, 11, 10, 2], the correct result should be [0,10,11,9,1]– Artyom Amiryan
Nov 12 '18 at 13:30
it displays wrong result
[0, 10, 11, 10, 2], the correct result should be [0,10,11,9,1]– Artyom Amiryan
Nov 12 '18 at 13:30
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
seemed to be working on my side var replaceArr = ['A','J','Q','10','2'] var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}] originalArr.forEach((val) => { var replaceIndex = replaceArr.indexOf(Object.keys(val)[0]); if (replaceIndex >= 0) { replaceArr[replaceIndex] = val[Object.keys(val)[0]]; } });console.log(replaceArr);
– Ali Khan
Nov 12 '18 at 14:14
add a comment |
0
var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
add a comment |
0
var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
add a comment |
0
0
0
var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)var replaceArr = ['A','J','Q','10','2']
var originalArr = [{A:0},{2:1},{3:2},{4:3},{5:4},{6:5},{10:9},{J:10},{Q:11},{K:12}]
originalArr.forEach((item)=>{
let property = Object.keys(item)[0];
let indexOfproperty = replaceArr.indexOf(property);
if(indexOfproperty !== -1){
replaceArr[indexOfproperty] = item[property]
}
})
console.log(replaceArr)answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
answered Nov 12 '18 at 13:31
Mohammed Ashfaq
1,6672512
1,6672512
add a comment |
add a comment |
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