How to put the variable in a certain order after using “Solve[]”












5












$begingroup$


I have this code:



eq1 = 4 x1 + 5 x2 - 9 x11 == 5;

eq2 = 5 x1 - 3 x2 + 3 x11 == 99;

eq3 = 2 x1 + 5 x2 - 4 x11 == 7;

system = {eq1, eq2, eq3};

solution = Solve[system]


and the output is:



{{x1 -> 2574/161, x11 -> 1094/161, x2 -> 71/161}}


I would like the output to go in order i.e. x1, x2, and then x11, but I cannot figure out how.






equation-solving core-language







share|improve this question











$endgroup$












  • $begingroup$
    Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
    $endgroup$
    – AccidentalFourierTransform
    Nov 13 '18 at 2:17










  • $begingroup$
    Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
    $endgroup$
    – Chris K
    Nov 13 '18 at 2:39










  • $begingroup$
    BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    Nov 13 '18 at 7:06


















5












$begingroup$


I have this code:



eq1 = 4 x1 + 5 x2 - 9 x11 == 5;

eq2 = 5 x1 - 3 x2 + 3 x11 == 99;

eq3 = 2 x1 + 5 x2 - 4 x11 == 7;

system = {eq1, eq2, eq3};

solution = Solve[system]


and the output is:



{{x1 -> 2574/161, x11 -> 1094/161, x2 -> 71/161}}


I would like the output to go in order i.e. x1, x2, and then x11, but I cannot figure out how.






equation-solving core-language







share|improve this question











$endgroup$












  • $begingroup$
    Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
    $endgroup$
    – AccidentalFourierTransform
    Nov 13 '18 at 2:17










  • $begingroup$
    Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
    $endgroup$
    – Chris K
    Nov 13 '18 at 2:39










  • $begingroup$
    BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    Nov 13 '18 at 7:06
















5












5








5





$begingroup$


I have this code:



eq1 = 4 x1 + 5 x2 - 9 x11 == 5;

eq2 = 5 x1 - 3 x2 + 3 x11 == 99;

eq3 = 2 x1 + 5 x2 - 4 x11 == 7;

system = {eq1, eq2, eq3};

solution = Solve[system]


and the output is:



{{x1 -> 2574/161, x11 -> 1094/161, x2 -> 71/161}}


I would like the output to go in order i.e. x1, x2, and then x11, but I cannot figure out how.






equation-solving core-language







share|improve this question











$endgroup$




I have this code:



eq1 = 4 x1 + 5 x2 - 9 x11 == 5;

eq2 = 5 x1 - 3 x2 + 3 x11 == 99;

eq3 = 2 x1 + 5 x2 - 4 x11 == 7;

system = {eq1, eq2, eq3};

solution = Solve[system]


and the output is:



{{x1 -> 2574/161, x11 -> 1094/161, x2 -> 71/161}}


I would like the output to go in order i.e. x1, x2, and then x11, but I cannot figure out how.






equation-solving core-language




equation-solving core-language






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 7:08









Αλέξανδρος Ζεγγ

4,1541929




4,1541929










asked Nov 13 '18 at 2:00









Jose CastellanosJose Castellanos

283




283












  • $begingroup$
    Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
    $endgroup$
    – AccidentalFourierTransform
    Nov 13 '18 at 2:17










  • $begingroup$
    Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
    $endgroup$
    – Chris K
    Nov 13 '18 at 2:39










  • $begingroup$
    BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    Nov 13 '18 at 7:06




















  • $begingroup$
    Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
    $endgroup$
    – AccidentalFourierTransform
    Nov 13 '18 at 2:17










  • $begingroup$
    Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
    $endgroup$
    – Chris K
    Nov 13 '18 at 2:39










  • $begingroup$
    BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    Nov 13 '18 at 7:06


















$begingroup$
Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
$endgroup$
– AccidentalFourierTransform
Nov 13 '18 at 2:17




$begingroup$
Use x[1],x[2],x[1,1] (or x[1],x[2],x[11]) instead of x1,x2,x11.
$endgroup$
– AccidentalFourierTransform
Nov 13 '18 at 2:17












$begingroup$
Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
$endgroup$
– Chris K
Nov 13 '18 at 2:39




$begingroup$
Welcome to Mathematica.SE! I suggest the following: 1) As you receive help, try to give it too, by answering questions in your area of expertise. 2) Take the tour and check the faqs! 3) When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge. Also, please remember to accept the answer, if any, that solves your problem, by clicking the checkmark sign!
$endgroup$
– Chris K
Nov 13 '18 at 2:39












$begingroup$
BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
$endgroup$
– Αλέξανδρος Ζεγγ
Nov 13 '18 at 7:06






$begingroup$
BTW, you can even suppress the output of x11 by using Solve[system, {x1, x2}, {x11}], if you want to.
$endgroup$
– Αλέξανδρος Ζεγγ
Nov 13 '18 at 7:06












3 Answers
3






active

oldest

votes


















12












$begingroup$

Solve will return the solutions in the order requested:



solution = Solve[system, {x1, x2, x11}]

(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}  *)





share|improve this answer









$endgroup$













  • $begingroup$
    Thank you so much!
    $endgroup$
    – Jose Castellanos
    Nov 13 '18 at 14:13



















3












$begingroup$

SortBy[#, {StringLength @ SymbolName[#[[1]]] &}] & /@ solution



{{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}







share|improve this answer









$endgroup$





















    1












    $begingroup$

    Try also this:



    solution /. {a_, b_, c_} -> {a, c, b}
    

    
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}   *)


    Have fun!






    share|improve this answer









    $endgroup$













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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      12












      $begingroup$

      Solve will return the solutions in the order requested:



      solution = Solve[system, {x1, x2, x11}]
      
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}  *)





      share|improve this answer









      $endgroup$













      • $begingroup$
        Thank you so much!
        $endgroup$
        – Jose Castellanos
        Nov 13 '18 at 14:13
















      12












      $begingroup$

      Solve will return the solutions in the order requested:



      solution = Solve[system, {x1, x2, x11}]
      
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}  *)





      share|improve this answer









      $endgroup$













      • $begingroup$
        Thank you so much!
        $endgroup$
        – Jose Castellanos
        Nov 13 '18 at 14:13














      12












      12








      12





      $begingroup$

      Solve will return the solutions in the order requested:



      solution = Solve[system, {x1, x2, x11}]
      
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}  *)





      share|improve this answer









      $endgroup$



      Solve will return the solutions in the order requested:



      solution = Solve[system, {x1, x2, x11}]
      
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}  *)






      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 13 '18 at 2:52









      Michael E2Michael E2

      146k11197468




      146k11197468












      • $begingroup$
        Thank you so much!
        $endgroup$
        – Jose Castellanos
        Nov 13 '18 at 14:13


















      • $begingroup$
        Thank you so much!
        $endgroup$
        – Jose Castellanos
        Nov 13 '18 at 14:13
















      $begingroup$
      Thank you so much!
      $endgroup$
      – Jose Castellanos
      Nov 13 '18 at 14:13




      $begingroup$
      Thank you so much!
      $endgroup$
      – Jose Castellanos
      Nov 13 '18 at 14:13











      3












      $begingroup$

      SortBy[#, {StringLength @ SymbolName[#[[1]]] &}] & /@ solution



      {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}







      share|improve this answer









      $endgroup$


















        3












        $begingroup$

        SortBy[#, {StringLength @ SymbolName[#[[1]]] &}] & /@ solution



        {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}







        share|improve this answer









        $endgroup$
















          3












          3








          3





          $begingroup$

          SortBy[#, {StringLength @ SymbolName[#[[1]]] &}] & /@ solution



          {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}







          share|improve this answer









          $endgroup$



          SortBy[#, {StringLength @ SymbolName[#[[1]]] &}] & /@ solution



          {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 2:31









          kglrkglr

          179k9198410




          179k9198410























              1












              $begingroup$

              Try also this:



              solution /. {a_, b_, c_} -> {a, c, b}
              

              
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}   *)


              Have fun!






              share|improve this answer









              $endgroup$


















                1












                $begingroup$

                Try also this:



                solution /. {a_, b_, c_} -> {a, c, b}
                

                
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}   *)


                Have fun!






                share|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  Try also this:



                  solution /. {a_, b_, c_} -> {a, c, b}
                  

                  
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}   *)


                  Have fun!






                  share|improve this answer









                  $endgroup$



                  Try also this:



                  solution /. {a_, b_, c_} -> {a, c, b}
                  

                  
(*  {{x1 -> 2574/161, x2 -> 71/161, x11 -> 1094/161}}   *)


                  Have fun!







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 12:50









                  Alexei BoulbitchAlexei Boulbitch

                  21.4k2470




                  21.4k2470






























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