add large string numbers
i want to create a static method that takes two strings that represent two numbers
(any number of digits) and returns the result of adding them as a string..
the purpose of this is to be able to add large numbers as you know that integers have a limited range however i don't want to use arrays in my solution..
here is my code (assuming n1 length > n2)
public class LargeNumber {
public static void main(String args) {
System.out.println(returnSum("138", "68"));
System.out.println(returnSum("134548", "6668"));
}
public static String returnSum(String n1, String n2) {
int n1L = n1.length();
int n2L = n2.length();
String total = "x";
int extra = 0;
for (int i = 0; i < n1L; i++) {
String digit = n1.substring(n1L - i);
int one = Integer.parseInt(digit);
int two;
if (i > n2L) {
two = 0;
} else {
String digit2 = n2.substring(n2L - i);
two = Integer.parseInt(digit2);
}
int num = one + two;
if (extra > 0) {
num = num + extra;
extra = 0;
} else {
extra = 0;
}
if (num < 10) {
total = Integer.toString(num) + total;
} else {
extra = (num / 10);
int numT = num - extra * 10;
total = Integer.toString(numT) + total;
}
}
return total;
}
}
i want to know if my code is correct and also to know what is the reason for the Exception error.
for-loop numbers parseint
asked Nov 12 at 7:40
Aifa
32
add a comment |
i want to create a static method that takes two strings that represent two numbers
(any number of digits) and returns the result of adding them as a string..
the purpose of this is to be able to add large numbers as you know that integers have a limited range however i don't want to use arrays in my solution..
here is my code (assuming n1 length > n2)
public class LargeNumber {
public static void main(String args) {
System.out.println(returnSum("138", "68"));
System.out.println(returnSum("134548", "6668"));
}
public static String returnSum(String n1, String n2) {
int n1L = n1.length();
int n2L = n2.length();
String total = "x";
int extra = 0;
for (int i = 0; i < n1L; i++) {
String digit = n1.substring(n1L - i);
int one = Integer.parseInt(digit);
int two;
if (i > n2L) {
two = 0;
} else {
String digit2 = n2.substring(n2L - i);
two = Integer.parseInt(digit2);
}
int num = one + two;
if (extra > 0) {
num = num + extra;
extra = 0;
} else {
extra = 0;
}
if (num < 10) {
total = Integer.toString(num) + total;
} else {
extra = (num / 10);
int numT = num - extra * 10;
total = Integer.toString(numT) + total;
}
}
return total;
}
}
i want to know if my code is correct and also to know what is the reason for the Exception error.
for-loop numbers parseint
asked Nov 12 at 7:40
Aifa
32
add a comment |
i want to create a static method that takes two strings that represent two numbers
(any number of digits) and returns the result of adding them as a string..
the purpose of this is to be able to add large numbers as you know that integers have a limited range however i don't want to use arrays in my solution..
here is my code (assuming n1 length > n2)
public class LargeNumber {
public static void main(String args) {
System.out.println(returnSum("138", "68"));
System.out.println(returnSum("134548", "6668"));
}
public static String returnSum(String n1, String n2) {
int n1L = n1.length();
int n2L = n2.length();
String total = "x";
int extra = 0;
for (int i = 0; i < n1L; i++) {
String digit = n1.substring(n1L - i);
int one = Integer.parseInt(digit);
int two;
if (i > n2L) {
two = 0;
} else {
String digit2 = n2.substring(n2L - i);
two = Integer.parseInt(digit2);
}
int num = one + two;
if (extra > 0) {
num = num + extra;
extra = 0;
} else {
extra = 0;
}
if (num < 10) {
total = Integer.toString(num) + total;
} else {
extra = (num / 10);
int numT = num - extra * 10;
total = Integer.toString(numT) + total;
}
}
return total;
}
}
i want to know if my code is correct and also to know what is the reason for the Exception error.
for-loop numbers parseint
asked Nov 12 at 7:40
Aifa
32
i want to create a static method that takes two strings that represent two numbers
(any number of digits) and returns the result of adding them as a string..
the purpose of this is to be able to add large numbers as you know that integers have a limited range however i don't want to use arrays in my solution..
here is my code (assuming n1 length > n2)
public class LargeNumber {
public static void main(String args) {
System.out.println(returnSum("138", "68"));
System.out.println(returnSum("134548", "6668"));
}
public static String returnSum(String n1, String n2) {
int n1L = n1.length();
int n2L = n2.length();
String total = "x";
int extra = 0;
for (int i = 0; i < n1L; i++) {
String digit = n1.substring(n1L - i);
int one = Integer.parseInt(digit);
int two;
if (i > n2L) {
two = 0;
} else {
String digit2 = n2.substring(n2L - i);
two = Integer.parseInt(digit2);
}
int num = one + two;
if (extra > 0) {
num = num + extra;
extra = 0;
} else {
extra = 0;
}
if (num < 10) {
total = Integer.toString(num) + total;
} else {
extra = (num / 10);
int numT = num - extra * 10;
total = Integer.toString(numT) + total;
}
}
return total;
}
}
i want to know if my code is correct and also to know what is the reason for the Exception error.
for-loop numbers parseint
for-loop numbers parseint
asked Nov 12 at 7:40
Aifa
32
asked Nov 12 at 7:40
Aifa
32
asked Nov 12 at 7:40
Aifa
32
asked Nov 12 at 7:40
Aifa
32
asked Nov 12 at 7:40
Aifa
32
32
add a comment |
add a comment |
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