Reversing strings in GO











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I'm trying to invert a string in go but I'm having trouble handling the characters. Unlike C, GO treats strings as vectors of bytes, rather than characters, which are called runes here. I tried to do some type conversions to do the assignments, but so far I could not.



The idea here is to generate 5 strings with random characters of sizes 100, 200, 300, 400 and 500 and then invert their characters. I was able to make C work with ease, but in GO, the language returns an error saying that it is not possible to perform the assignment.



 func inverte() {
var c = "A"
var strs, aux string

rand.Seed(time.Now().UnixNano())
// Gera 5 vetores de 100, 200, 300, 400, e 500 caracteres
for i := 1; i < 6; i++ {
strs = randomString(i * 100)
fmt.Print(strs)

for i2, j := 0, len(strs); i2 < j; i2, j = i+1, j-1 {
aux = strs[i2]
strs[i2] = strs[j]
strs[j] = aux
}
}
}









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    up vote
    -1
    down vote

    favorite












    I'm trying to invert a string in go but I'm having trouble handling the characters. Unlike C, GO treats strings as vectors of bytes, rather than characters, which are called runes here. I tried to do some type conversions to do the assignments, but so far I could not.



    The idea here is to generate 5 strings with random characters of sizes 100, 200, 300, 400 and 500 and then invert their characters. I was able to make C work with ease, but in GO, the language returns an error saying that it is not possible to perform the assignment.



     func inverte() {
    var c = "A"
    var strs, aux string

    rand.Seed(time.Now().UnixNano())
    // Gera 5 vetores de 100, 200, 300, 400, e 500 caracteres
    for i := 1; i < 6; i++ {
    strs = randomString(i * 100)
    fmt.Print(strs)

    for i2, j := 0, len(strs); i2 < j; i2, j = i+1, j-1 {
    aux = strs[i2]
    strs[i2] = strs[j]
    strs[j] = aux
    }
    }
    }









    share|improve this question
























      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      I'm trying to invert a string in go but I'm having trouble handling the characters. Unlike C, GO treats strings as vectors of bytes, rather than characters, which are called runes here. I tried to do some type conversions to do the assignments, but so far I could not.



      The idea here is to generate 5 strings with random characters of sizes 100, 200, 300, 400 and 500 and then invert their characters. I was able to make C work with ease, but in GO, the language returns an error saying that it is not possible to perform the assignment.



       func inverte() {
      var c = "A"
      var strs, aux string

      rand.Seed(time.Now().UnixNano())
      // Gera 5 vetores de 100, 200, 300, 400, e 500 caracteres
      for i := 1; i < 6; i++ {
      strs = randomString(i * 100)
      fmt.Print(strs)

      for i2, j := 0, len(strs); i2 < j; i2, j = i+1, j-1 {
      aux = strs[i2]
      strs[i2] = strs[j]
      strs[j] = aux
      }
      }
      }









      share|improve this question













      I'm trying to invert a string in go but I'm having trouble handling the characters. Unlike C, GO treats strings as vectors of bytes, rather than characters, which are called runes here. I tried to do some type conversions to do the assignments, but so far I could not.



      The idea here is to generate 5 strings with random characters of sizes 100, 200, 300, 400 and 500 and then invert their characters. I was able to make C work with ease, but in GO, the language returns an error saying that it is not possible to perform the assignment.



       func inverte() {
      var c = "A"
      var strs, aux string

      rand.Seed(time.Now().UnixNano())
      // Gera 5 vetores de 100, 200, 300, 400, e 500 caracteres
      for i := 1; i < 6; i++ {
      strs = randomString(i * 100)
      fmt.Print(strs)

      for i2, j := 0, len(strs); i2 < j; i2, j = i+1, j-1 {
      aux = strs[i2]
      strs[i2] = strs[j]
      strs[j] = aux
      }
      }
      }






      string go inversion reversion






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      asked Nov 11 at 0:41









      Valney Faria

      35




      35
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          As you correctly identified, go strings are immutable, so you cannot assign to rune/character values at given indices.



          Instead of reversing the string in-place one must create a copy of the runes in the string and reverse those instead, and then return the resulting string.



          For example (Go Playground):



          func reverse(s string) string {
          rs := rune(s)
          for i, j := 0, len(rs)-1; i < j; i, j = i+1, j-1 {
          rs[i], rs[j] = rs[j], rs[i]
          }
          return string(rs)
          }

          func main() {
          fmt.Println(reverse("Hello, World!"))
          // !dlroW ,olleH
          fmt.Println(reverse("Hello, 世界!"))
          // !界世 ,olleH
          }


          There are problems with this approach due to the intricacies of Unicode (e.g. combining diacritical marks) but this will get you started.






          share|improve this answer























          • A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
            – David Maze
            Nov 11 at 1:37










          • @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
            – maerics
            Nov 11 at 5:22











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          As you correctly identified, go strings are immutable, so you cannot assign to rune/character values at given indices.



          Instead of reversing the string in-place one must create a copy of the runes in the string and reverse those instead, and then return the resulting string.



          For example (Go Playground):



          func reverse(s string) string {
          rs := rune(s)
          for i, j := 0, len(rs)-1; i < j; i, j = i+1, j-1 {
          rs[i], rs[j] = rs[j], rs[i]
          }
          return string(rs)
          }

          func main() {
          fmt.Println(reverse("Hello, World!"))
          // !dlroW ,olleH
          fmt.Println(reverse("Hello, 世界!"))
          // !界世 ,olleH
          }


          There are problems with this approach due to the intricacies of Unicode (e.g. combining diacritical marks) but this will get you started.






          share|improve this answer























          • A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
            – David Maze
            Nov 11 at 1:37










          • @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
            – maerics
            Nov 11 at 5:22















          up vote
          1
          down vote



          accepted










          As you correctly identified, go strings are immutable, so you cannot assign to rune/character values at given indices.



          Instead of reversing the string in-place one must create a copy of the runes in the string and reverse those instead, and then return the resulting string.



          For example (Go Playground):



          func reverse(s string) string {
          rs := rune(s)
          for i, j := 0, len(rs)-1; i < j; i, j = i+1, j-1 {
          rs[i], rs[j] = rs[j], rs[i]
          }
          return string(rs)
          }

          func main() {
          fmt.Println(reverse("Hello, World!"))
          // !dlroW ,olleH
          fmt.Println(reverse("Hello, 世界!"))
          // !界世 ,olleH
          }


          There are problems with this approach due to the intricacies of Unicode (e.g. combining diacritical marks) but this will get you started.






          share|improve this answer























          • A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
            – David Maze
            Nov 11 at 1:37










          • @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
            – maerics
            Nov 11 at 5:22













          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          As you correctly identified, go strings are immutable, so you cannot assign to rune/character values at given indices.



          Instead of reversing the string in-place one must create a copy of the runes in the string and reverse those instead, and then return the resulting string.



          For example (Go Playground):



          func reverse(s string) string {
          rs := rune(s)
          for i, j := 0, len(rs)-1; i < j; i, j = i+1, j-1 {
          rs[i], rs[j] = rs[j], rs[i]
          }
          return string(rs)
          }

          func main() {
          fmt.Println(reverse("Hello, World!"))
          // !dlroW ,olleH
          fmt.Println(reverse("Hello, 世界!"))
          // !界世 ,olleH
          }


          There are problems with this approach due to the intricacies of Unicode (e.g. combining diacritical marks) but this will get you started.






          share|improve this answer














          As you correctly identified, go strings are immutable, so you cannot assign to rune/character values at given indices.



          Instead of reversing the string in-place one must create a copy of the runes in the string and reverse those instead, and then return the resulting string.



          For example (Go Playground):



          func reverse(s string) string {
          rs := rune(s)
          for i, j := 0, len(rs)-1; i < j; i, j = i+1, j-1 {
          rs[i], rs[j] = rs[j], rs[i]
          }
          return string(rs)
          }

          func main() {
          fmt.Println(reverse("Hello, World!"))
          // !dlroW ,olleH
          fmt.Println(reverse("Hello, 世界!"))
          // !界世 ,olleH
          }


          There are problems with this approach due to the intricacies of Unicode (e.g. combining diacritical marks) but this will get you started.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 11 at 1:06

























          answered Nov 11 at 0:45









          maerics

          103k28198246




          103k28198246












          • A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
            – David Maze
            Nov 11 at 1:37










          • @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
            – maerics
            Nov 11 at 5:22


















          • A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
            – David Maze
            Nov 11 at 1:37










          • @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
            – maerics
            Nov 11 at 5:22
















          A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
          – David Maze
          Nov 11 at 1:37




          A similar approach using (unicode/utf8).DecodeLastRuneInString might save an extra array/translation.
          – David Maze
          Nov 11 at 1:37












          @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
          – maerics
          Nov 11 at 5:22




          @DavidMaze neat idea, I can't get a benchmark to run faster than the above method or work with unicode edge cases though.
          – maerics
          Nov 11 at 5:22


















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