Flutter - showing a PopupMenuButton in BottomNavigationBar
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I am trying to show a menu when a navigation bar item is clicked. This was my attempt:
@override
Widget build(BuildContext context) {
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: MyAppBar(
title: "Home",
context: context,
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new PopupMenuButton(
icon: Icon(Icons.add),
itemBuilder: (_) => <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
),
title: Text('more')),
],
currentIndex: 0,
),
body: new Container()));
}
I encountered two problems. First one is the display of the NavigationBarItem. There is a padding between the icon the title that I could not remove (even by adding padding: EdgeInsets.all(0.0)) (as the picture below shows). And the second is that I need to click exactly on the icon for the menu to appear.
I tried calling showMenu directly (the method that PopupMenuButton calls) when a BottomNavigationBarItem of index=2 (for example) is clicked. But it was tricky how to determine the location of origin where the menu should appear from.
dart
flutter flutter-layout asked Nov 16 '18 at 12:01
M20M20
191116
add a comment |
I am trying to show a menu when a navigation bar item is clicked. This was my attempt:
@override
Widget build(BuildContext context) {
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: MyAppBar(
title: "Home",
context: context,
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new PopupMenuButton(
icon: Icon(Icons.add),
itemBuilder: (_) => <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
),
title: Text('more')),
],
currentIndex: 0,
),
body: new Container()));
}
I encountered two problems. First one is the display of the NavigationBarItem. There is a padding between the icon the title that I could not remove (even by adding padding: EdgeInsets.all(0.0)) (as the picture below shows). And the second is that I need to click exactly on the icon for the menu to appear.
I tried calling showMenu directly (the method that PopupMenuButton calls) when a BottomNavigationBarItem of index=2 (for example) is clicked. But it was tricky how to determine the location of origin where the menu should appear from.
dart
flutter flutter-layout asked Nov 16 '18 at 12:01
M20M20
191116
add a comment |
I am trying to show a menu when a navigation bar item is clicked. This was my attempt:
@override
Widget build(BuildContext context) {
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: MyAppBar(
title: "Home",
context: context,
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new PopupMenuButton(
icon: Icon(Icons.add),
itemBuilder: (_) => <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
),
title: Text('more')),
],
currentIndex: 0,
),
body: new Container()));
}
I encountered two problems. First one is the display of the NavigationBarItem. There is a padding between the icon the title that I could not remove (even by adding padding: EdgeInsets.all(0.0)) (as the picture below shows). And the second is that I need to click exactly on the icon for the menu to appear.
I tried calling showMenu directly (the method that PopupMenuButton calls) when a BottomNavigationBarItem of index=2 (for example) is clicked. But it was tricky how to determine the location of origin where the menu should appear from.
dart
flutter flutter-layout asked Nov 16 '18 at 12:01
M20M20
191116
I am trying to show a menu when a navigation bar item is clicked. This was my attempt:
@override
Widget build(BuildContext context) {
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: MyAppBar(
title: "Home",
context: context,
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new PopupMenuButton(
icon: Icon(Icons.add),
itemBuilder: (_) => <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
),
title: Text('more')),
],
currentIndex: 0,
),
body: new Container()));
}
I encountered two problems. First one is the display of the NavigationBarItem. There is a padding between the icon the title that I could not remove (even by adding padding: EdgeInsets.all(0.0)) (as the picture below shows). And the second is that I need to click exactly on the icon for the menu to appear.
I tried calling showMenu directly (the method that PopupMenuButton calls) when a BottomNavigationBarItem of index=2 (for example) is clicked. But it was tricky how to determine the location of origin where the menu should appear from.
dart
flutter flutter-layout dart
flutter flutter-layout asked Nov 16 '18 at 12:01
M20M20
191116
asked Nov 16 '18 at 12:01
M20M20
191116
edited Nov 16 '18 at 12:48
M20
asked Nov 16 '18 at 12:01
M20M20
191116
asked Nov 16 '18 at 12:01
M20M20
191116
asked Nov 16 '18 at 12:01
M20M20
191116
191116
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Here's an attempt that uses the showMenu directly and calling the function buttonMenuPosition to get the position for the menu. It's fairly fragile, but you can change the location of the button to the middle for example with bar.size.center instead of bar.size.bottomRight. With some MATH and by manually manipulating Offset objects (if/when you have more than 3 items), you can change the location to have the menu on one that isn't the center or at the end).
RelativeRect buttonMenuPosition(BuildContext c) {
final RenderBox bar = c.findRenderObject();
final RenderBox overlay = Overlay.of(c).context.findRenderObject();
final RelativeRect position = RelativeRect.fromRect(
Rect.fromPoints(
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
),
Offset.zero & overlay.size,
);
return position;
}
@override
Widget build(BuildContext context) {
final key = GlobalKey<State<BottomNavigationBar>>();
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
key: key,
items: [
const BottomNavigationBarItem(
icon: Icon(Icons.home), title: Text('Home')),
const BottomNavigationBarItem(
icon: Icon(Icons.book), title: Text('Second')),
const BottomNavigationBarItem(
icon: Icon(Icons.add), title: Text('more')),
],
currentIndex: 0,
onTap: (index) async {
final position = buttonMenuPosition(key.currentContext);
if (index == 2) {
final result = await showMenu(
context: context,
position: position,
items: <PopupMenuItem<String>>[
const PopupMenuItem<String>(
child: Text('test1'), value: 'test1'),
const PopupMenuItem<String>(
child: Text('test2'), value: 'test2'),
],
);
}
},
),
body: Container()));
}
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
add a comment |
Here's my attempt at it:
@override
Widget build(BuildContext context) {
return Material(
child: DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new Icon(Icons.add),
title: Text('More')),
],
currentIndex: 0,
onTap: (int index) async {
if(index == 2){
await showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(1000.0, 1000.0, 0.0, 0.0),
items: <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
elevation: 8.0,
);
}
},
),
body: new Container())));
}
Basically using the showMenu method as you said except I've put the values for the RelativeRect as 1000.0 so that it'll be in the bottom right of any device. You could mess around with these values to get a position more right above the icon but I think having it like this works well:
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
add a comment |
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2 Answers
2
active
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here's an attempt that uses the showMenu directly and calling the function buttonMenuPosition to get the position for the menu. It's fairly fragile, but you can change the location of the button to the middle for example with bar.size.center instead of bar.size.bottomRight. With some MATH and by manually manipulating Offset objects (if/when you have more than 3 items), you can change the location to have the menu on one that isn't the center or at the end).
RelativeRect buttonMenuPosition(BuildContext c) {
final RenderBox bar = c.findRenderObject();
final RenderBox overlay = Overlay.of(c).context.findRenderObject();
final RelativeRect position = RelativeRect.fromRect(
Rect.fromPoints(
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
),
Offset.zero & overlay.size,
);
return position;
}
@override
Widget build(BuildContext context) {
final key = GlobalKey<State<BottomNavigationBar>>();
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
key: key,
items: [
const BottomNavigationBarItem(
icon: Icon(Icons.home), title: Text('Home')),
const BottomNavigationBarItem(
icon: Icon(Icons.book), title: Text('Second')),
const BottomNavigationBarItem(
icon: Icon(Icons.add), title: Text('more')),
],
currentIndex: 0,
onTap: (index) async {
final position = buttonMenuPosition(key.currentContext);
if (index == 2) {
final result = await showMenu(
context: context,
position: position,
items: <PopupMenuItem<String>>[
const PopupMenuItem<String>(
child: Text('test1'), value: 'test1'),
const PopupMenuItem<String>(
child: Text('test2'), value: 'test2'),
],
);
}
},
),
body: Container()));
}
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
add a comment |
Here's an attempt that uses the showMenu directly and calling the function buttonMenuPosition to get the position for the menu. It's fairly fragile, but you can change the location of the button to the middle for example with bar.size.center instead of bar.size.bottomRight. With some MATH and by manually manipulating Offset objects (if/when you have more than 3 items), you can change the location to have the menu on one that isn't the center or at the end).
RelativeRect buttonMenuPosition(BuildContext c) {
final RenderBox bar = c.findRenderObject();
final RenderBox overlay = Overlay.of(c).context.findRenderObject();
final RelativeRect position = RelativeRect.fromRect(
Rect.fromPoints(
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
),
Offset.zero & overlay.size,
);
return position;
}
@override
Widget build(BuildContext context) {
final key = GlobalKey<State<BottomNavigationBar>>();
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
key: key,
items: [
const BottomNavigationBarItem(
icon: Icon(Icons.home), title: Text('Home')),
const BottomNavigationBarItem(
icon: Icon(Icons.book), title: Text('Second')),
const BottomNavigationBarItem(
icon: Icon(Icons.add), title: Text('more')),
],
currentIndex: 0,
onTap: (index) async {
final position = buttonMenuPosition(key.currentContext);
if (index == 2) {
final result = await showMenu(
context: context,
position: position,
items: <PopupMenuItem<String>>[
const PopupMenuItem<String>(
child: Text('test1'), value: 'test1'),
const PopupMenuItem<String>(
child: Text('test2'), value: 'test2'),
],
);
}
},
),
body: Container()));
}
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
add a comment |
Here's an attempt that uses the showMenu directly and calling the function buttonMenuPosition to get the position for the menu. It's fairly fragile, but you can change the location of the button to the middle for example with bar.size.center instead of bar.size.bottomRight. With some MATH and by manually manipulating Offset objects (if/when you have more than 3 items), you can change the location to have the menu on one that isn't the center or at the end).
RelativeRect buttonMenuPosition(BuildContext c) {
final RenderBox bar = c.findRenderObject();
final RenderBox overlay = Overlay.of(c).context.findRenderObject();
final RelativeRect position = RelativeRect.fromRect(
Rect.fromPoints(
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
),
Offset.zero & overlay.size,
);
return position;
}
@override
Widget build(BuildContext context) {
final key = GlobalKey<State<BottomNavigationBar>>();
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
key: key,
items: [
const BottomNavigationBarItem(
icon: Icon(Icons.home), title: Text('Home')),
const BottomNavigationBarItem(
icon: Icon(Icons.book), title: Text('Second')),
const BottomNavigationBarItem(
icon: Icon(Icons.add), title: Text('more')),
],
currentIndex: 0,
onTap: (index) async {
final position = buttonMenuPosition(key.currentContext);
if (index == 2) {
final result = await showMenu(
context: context,
position: position,
items: <PopupMenuItem<String>>[
const PopupMenuItem<String>(
child: Text('test1'), value: 'test1'),
const PopupMenuItem<String>(
child: Text('test2'), value: 'test2'),
],
);
}
},
),
body: Container()));
}
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
Here's an attempt that uses the showMenu directly and calling the function buttonMenuPosition to get the position for the menu. It's fairly fragile, but you can change the location of the button to the middle for example with bar.size.center instead of bar.size.bottomRight. With some MATH and by manually manipulating Offset objects (if/when you have more than 3 items), you can change the location to have the menu on one that isn't the center or at the end).
RelativeRect buttonMenuPosition(BuildContext c) {
final RenderBox bar = c.findRenderObject();
final RenderBox overlay = Overlay.of(c).context.findRenderObject();
final RelativeRect position = RelativeRect.fromRect(
Rect.fromPoints(
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
bar.localToGlobal(bar.size.bottomRight(Offset.zero), ancestor: overlay),
),
Offset.zero & overlay.size,
);
return position;
}
@override
Widget build(BuildContext context) {
final key = GlobalKey<State<BottomNavigationBar>>();
return DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
key: key,
items: [
const BottomNavigationBarItem(
icon: Icon(Icons.home), title: Text('Home')),
const BottomNavigationBarItem(
icon: Icon(Icons.book), title: Text('Second')),
const BottomNavigationBarItem(
icon: Icon(Icons.add), title: Text('more')),
],
currentIndex: 0,
onTap: (index) async {
final position = buttonMenuPosition(key.currentContext);
if (index == 2) {
final result = await showMenu(
context: context,
position: position,
items: <PopupMenuItem<String>>[
const PopupMenuItem<String>(
child: Text('test1'), value: 'test1'),
const PopupMenuItem<String>(
child: Text('test2'), value: 'test2'),
],
);
}
},
),
body: Container()));
}
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
edited Nov 16 '18 at 16:16
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
answered Nov 16 '18 at 16:11
RingilRingil
3,85321227
3,85321227
add a comment |
add a comment |
Here's my attempt at it:
@override
Widget build(BuildContext context) {
return Material(
child: DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new Icon(Icons.add),
title: Text('More')),
],
currentIndex: 0,
onTap: (int index) async {
if(index == 2){
await showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(1000.0, 1000.0, 0.0, 0.0),
items: <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
elevation: 8.0,
);
}
},
),
body: new Container())));
}
Basically using the showMenu method as you said except I've put the values for the RelativeRect as 1000.0 so that it'll be in the bottom right of any device. You could mess around with these values to get a position more right above the icon but I think having it like this works well:
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
add a comment |
Here's my attempt at it:
@override
Widget build(BuildContext context) {
return Material(
child: DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new Icon(Icons.add),
title: Text('More')),
],
currentIndex: 0,
onTap: (int index) async {
if(index == 2){
await showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(1000.0, 1000.0, 0.0, 0.0),
items: <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
elevation: 8.0,
);
}
},
),
body: new Container())));
}
Basically using the showMenu method as you said except I've put the values for the RelativeRect as 1000.0 so that it'll be in the bottom right of any device. You could mess around with these values to get a position more right above the icon but I think having it like this works well:
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
add a comment |
Here's my attempt at it:
@override
Widget build(BuildContext context) {
return Material(
child: DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new Icon(Icons.add),
title: Text('More')),
],
currentIndex: 0,
onTap: (int index) async {
if(index == 2){
await showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(1000.0, 1000.0, 0.0, 0.0),
items: <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
elevation: 8.0,
);
}
},
),
body: new Container())));
}
Basically using the showMenu method as you said except I've put the values for the RelativeRect as 1000.0 so that it'll be in the bottom right of any device. You could mess around with these values to get a position more right above the icon but I think having it like this works well:
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
Here's my attempt at it:
@override
Widget build(BuildContext context) {
return Material(
child: DefaultTabController(
length: 3,
child: Scaffold(
appBar: AppBar(
title: Text("Home"),
),
bottomNavigationBar: BottomNavigationBar(
items: [
BottomNavigationBarItem(
icon: new Icon(Icons.home), title: Text('Home')),
BottomNavigationBarItem(
icon: new Icon(Icons.book), title: Text('Second')),
BottomNavigationBarItem(
icon: new Icon(Icons.add),
title: Text('More')),
],
currentIndex: 0,
onTap: (int index) async {
if(index == 2){
await showMenu<String>(
context: context,
position: RelativeRect.fromLTRB(1000.0, 1000.0, 0.0, 0.0),
items: <PopupMenuItem<String>>[
new PopupMenuItem<String>(
child: const Text('test1'), value: 'test1'),
new PopupMenuItem<String>(
child: const Text('test2'), value: 'test2'),
],
elevation: 8.0,
);
}
},
),
body: new Container())));
}
Basically using the showMenu method as you said except I've put the values for the RelativeRect as 1000.0 so that it'll be in the bottom right of any device. You could mess around with these values to get a position more right above the icon but I think having it like this works well:
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
answered Nov 16 '18 at 15:13
SnakeyHipsSnakeyHips
696116
696116
add a comment |
add a comment |
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