Hive query with sum analytical function





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I have data in the below format in a hive table.
enter image description here



Can some one help me to write a hive query which will give me the below result.



enter image description here



The Result is the sum of previous 6 months without skipping months.



Here is the query I have tried, But it gives only the running totals.



SELECT t.key, 
t.tran_date,
Date_add(Add_months(t.tran_date, 1), 1 - Day(Add_months(t.tran_date, 1)))
run_date,
month(t.tran_date)
month,
Year(t.tran_date)
year,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Month(t.tran_date))
current_month_agg_incoming_amt,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Ceil(Month(t.tran_date) / 6.0)
ORDER BY Month(t.tran_date))
Result
FROM transaction_denorm_hist_tmp1 t
order by tran_date desc;


enter image description here










share|improve this question

























  • Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

    – Joseph Cho
    Nov 16 '18 at 18:24











  • Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

    – user10664315
    Nov 16 '18 at 18:37


















0















I have data in the below format in a hive table.
enter image description here



Can some one help me to write a hive query which will give me the below result.



enter image description here



The Result is the sum of previous 6 months without skipping months.



Here is the query I have tried, But it gives only the running totals.



SELECT t.key, 
t.tran_date,
Date_add(Add_months(t.tran_date, 1), 1 - Day(Add_months(t.tran_date, 1)))
run_date,
month(t.tran_date)
month,
Year(t.tran_date)
year,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Month(t.tran_date))
current_month_agg_incoming_amt,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Ceil(Month(t.tran_date) / 6.0)
ORDER BY Month(t.tran_date))
Result
FROM transaction_denorm_hist_tmp1 t
order by tran_date desc;


enter image description here










share|improve this question

























  • Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

    – Joseph Cho
    Nov 16 '18 at 18:24











  • Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

    – user10664315
    Nov 16 '18 at 18:37














0












0








0








I have data in the below format in a hive table.
enter image description here



Can some one help me to write a hive query which will give me the below result.



enter image description here



The Result is the sum of previous 6 months without skipping months.



Here is the query I have tried, But it gives only the running totals.



SELECT t.key, 
t.tran_date,
Date_add(Add_months(t.tran_date, 1), 1 - Day(Add_months(t.tran_date, 1)))
run_date,
month(t.tran_date)
month,
Year(t.tran_date)
year,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Month(t.tran_date))
current_month_agg_incoming_amt,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Ceil(Month(t.tran_date) / 6.0)
ORDER BY Month(t.tran_date))
Result
FROM transaction_denorm_hist_tmp1 t
order by tran_date desc;


enter image description here










share|improve this question
















I have data in the below format in a hive table.
enter image description here



Can some one help me to write a hive query which will give me the below result.



enter image description here



The Result is the sum of previous 6 months without skipping months.



Here is the query I have tried, But it gives only the running totals.



SELECT t.key, 
t.tran_date,
Date_add(Add_months(t.tran_date, 1), 1 - Day(Add_months(t.tran_date, 1)))
run_date,
month(t.tran_date)
month,
Year(t.tran_date)
year,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Month(t.tran_date))
current_month_agg_incoming_amt,
Sum(t.usd_amt)
OVER(
partition BY t.acct_key, Ceil(Month(t.tran_date) / 6.0)
ORDER BY Month(t.tran_date))
Result
FROM transaction_denorm_hist_tmp1 t
order by tran_date desc;


enter image description here







hive






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 18 '18 at 10:27







user10664315

















asked Nov 16 '18 at 18:11









user10664315user10664315

12




12













  • Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

    – Joseph Cho
    Nov 16 '18 at 18:24











  • Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

    – user10664315
    Nov 16 '18 at 18:37



















  • Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

    – Joseph Cho
    Nov 16 '18 at 18:24











  • Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

    – user10664315
    Nov 16 '18 at 18:37

















Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

– Joseph Cho
Nov 16 '18 at 18:24





Welcome to StackOverflow! Please provide a Minimal, Complete, and Verifiable example of what you've tried so far so we can reproduce your issue.

– Joseph Cho
Nov 16 '18 at 18:24













Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

– user10664315
Nov 16 '18 at 18:37





Hi Joseph, Thanks for your response, I have edited the post. Could you please help me out.

– user10664315
Nov 16 '18 at 18:37












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