XML_FILES_COMPARISON
I am doing a task in which I need to compare two xml files. Currently, I load the data in a table and then compare.
I want to automate this process.
Need different ways/suggestions that how can I do that if the rows in both files are in a shuffled way and without using primary key or if there is no primary key.
Thanks in advance.
xml automation comparison file-comparison javascript-automation
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I am doing a task in which I need to compare two xml files. Currently, I load the data in a table and then compare.
I want to automate this process.
Need different ways/suggestions that how can I do that if the rows in both files are in a shuffled way and without using primary key or if there is no primary key.
Thanks in advance.
xml automation comparison file-comparison javascript-automation
In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48
add a comment |
I am doing a task in which I need to compare two xml files. Currently, I load the data in a table and then compare.
I want to automate this process.
Need different ways/suggestions that how can I do that if the rows in both files are in a shuffled way and without using primary key or if there is no primary key.
Thanks in advance.
xml automation comparison file-comparison javascript-automation
I am doing a task in which I need to compare two xml files. Currently, I load the data in a table and then compare.
I want to automate this process.
Need different ways/suggestions that how can I do that if the rows in both files are in a shuffled way and without using primary key or if there is no primary key.
Thanks in advance.
xml automation comparison file-comparison javascript-automation
xml automation comparison file-comparison javascript-automation
asked Nov 16 '18 at 4:45
user8203393user8203393
1
1
In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48
add a comment |
In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48
In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48
In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48
add a comment |
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In order to compare two files, we must compare each entry. There must be some indicator that two entries are the same but the way you state it is that there are none. Things we could compare by are tagName, nodeName, certain attributes or the textContent. However, there must be some way to compare. Then there are algorithms. To compare two files with variable amount of entries in a naive fashion is n^m (nodes vs correspondents). There are also indexing, where-by nodes of each stack are sorted by their features (attribs, node name, etc..) and these sub-groups are then compared.
– Patrick Sturm
Nov 16 '18 at 4:48