Selenium FileUpload accept() is not clicking button
Having opened the file chooser dialog in IE,
self.webDiver.switch_to_alert().accept()
Tried the above line but does not click the open button.
IE Version 11.2580.14393.0;
Windows Server 2016 Standard
The dialog that gets displayed is "Choose File to Upload", this dialog has a File name text box with a Combobox + Open button as well as an Open button that is a SplitButtonControl with options to Open/Open readonly or save as previous version.
python-3.x selenium selenium-iedriver iedriverserver
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Having opened the file chooser dialog in IE,
self.webDiver.switch_to_alert().accept()
Tried the above line but does not click the open button.
IE Version 11.2580.14393.0;
Windows Server 2016 Standard
The dialog that gets displayed is "Choose File to Upload", this dialog has a File name text box with a Combobox + Open button as well as an Open button that is a SplitButtonControl with options to Open/Open readonly or save as previous version.
python-3.x selenium selenium-iedriver iedriverserver
3
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24
add a comment |
Having opened the file chooser dialog in IE,
self.webDiver.switch_to_alert().accept()
Tried the above line but does not click the open button.
IE Version 11.2580.14393.0;
Windows Server 2016 Standard
The dialog that gets displayed is "Choose File to Upload", this dialog has a File name text box with a Combobox + Open button as well as an Open button that is a SplitButtonControl with options to Open/Open readonly or save as previous version.
python-3.x selenium selenium-iedriver iedriverserver
Having opened the file chooser dialog in IE,
self.webDiver.switch_to_alert().accept()
Tried the above line but does not click the open button.
IE Version 11.2580.14393.0;
Windows Server 2016 Standard
The dialog that gets displayed is "Choose File to Upload", this dialog has a File name text box with a Combobox + Open button as well as an Open button that is a SplitButtonControl with options to Open/Open readonly or save as previous version.
python-3.x selenium selenium-iedriver iedriverserver
python-3.x selenium selenium-iedriver iedriverserver
edited Nov 19 '18 at 1:24
Dan
asked Nov 15 '18 at 6:32
DanDan
14218
14218
3
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24
add a comment |
3
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24
3
3
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24
add a comment |
1 Answer
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current Workaround is to use uiautomation:
import uiautomation as automation
print(automation.GetRootControl())
uiWindow = automation.WindowControl(searchDepth = 2, Name = 'Choose File to Upload')
print(uiWindow.Name)
uiWindow.SetTopmost(True)
fileName = uiWindow.EditControl(searchDepth = 4,Name = 'File name:')
fileName.SendKeys("State of testing.MicroFocus.pdf")
openFile = uiWindow.SplitButtonControl(searchDepth = 3,Name = 'Open')
openFile.Click()
Source: https://github.com/SeleniumHQ/selenium/issues/6140#issuecomment-426215154
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
current Workaround is to use uiautomation:
import uiautomation as automation
print(automation.GetRootControl())
uiWindow = automation.WindowControl(searchDepth = 2, Name = 'Choose File to Upload')
print(uiWindow.Name)
uiWindow.SetTopmost(True)
fileName = uiWindow.EditControl(searchDepth = 4,Name = 'File name:')
fileName.SendKeys("State of testing.MicroFocus.pdf")
openFile = uiWindow.SplitButtonControl(searchDepth = 3,Name = 'Open')
openFile.Click()
Source: https://github.com/SeleniumHQ/selenium/issues/6140#issuecomment-426215154
add a comment |
current Workaround is to use uiautomation:
import uiautomation as automation
print(automation.GetRootControl())
uiWindow = automation.WindowControl(searchDepth = 2, Name = 'Choose File to Upload')
print(uiWindow.Name)
uiWindow.SetTopmost(True)
fileName = uiWindow.EditControl(searchDepth = 4,Name = 'File name:')
fileName.SendKeys("State of testing.MicroFocus.pdf")
openFile = uiWindow.SplitButtonControl(searchDepth = 3,Name = 'Open')
openFile.Click()
Source: https://github.com/SeleniumHQ/selenium/issues/6140#issuecomment-426215154
add a comment |
current Workaround is to use uiautomation:
import uiautomation as automation
print(automation.GetRootControl())
uiWindow = automation.WindowControl(searchDepth = 2, Name = 'Choose File to Upload')
print(uiWindow.Name)
uiWindow.SetTopmost(True)
fileName = uiWindow.EditControl(searchDepth = 4,Name = 'File name:')
fileName.SendKeys("State of testing.MicroFocus.pdf")
openFile = uiWindow.SplitButtonControl(searchDepth = 3,Name = 'Open')
openFile.Click()
Source: https://github.com/SeleniumHQ/selenium/issues/6140#issuecomment-426215154
current Workaround is to use uiautomation:
import uiautomation as automation
print(automation.GetRootControl())
uiWindow = automation.WindowControl(searchDepth = 2, Name = 'Choose File to Upload')
print(uiWindow.Name)
uiWindow.SetTopmost(True)
fileName = uiWindow.EditControl(searchDepth = 4,Name = 'File name:')
fileName.SendKeys("State of testing.MicroFocus.pdf")
openFile = uiWindow.SplitButtonControl(searchDepth = 3,Name = 'Open')
openFile.Click()
Source: https://github.com/SeleniumHQ/selenium/issues/6140#issuecomment-426215154
answered Nov 19 '18 at 1:23
DanDan
14218
14218
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3
Is this a question or an answer?
– Guy
Nov 15 '18 at 6:36
Fixed question and answer.
– Dan
Nov 19 '18 at 1:24