create unique index multiple columns with one is columns value is zero












0















I have a table users with following columns and attributes



users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0
)


foreigner values is 0 and 1 default 0
how I can create unique index on column ssn, when checked foreigner value is 0.



id     ssn    foreigner
1 55 0 true
2 60 1 true
3 60 1 true
----------------------------------
4 55 0 false
----------------------------------
5 77 0 true









share|improve this question

























  • Can there be multiple rows possible with (55,1) ?

    – Madhur Bhaiya
    Nov 15 '18 at 11:44
















0















I have a table users with following columns and attributes



users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0
)


foreigner values is 0 and 1 default 0
how I can create unique index on column ssn, when checked foreigner value is 0.



id     ssn    foreigner
1 55 0 true
2 60 1 true
3 60 1 true
----------------------------------
4 55 0 false
----------------------------------
5 77 0 true









share|improve this question

























  • Can there be multiple rows possible with (55,1) ?

    – Madhur Bhaiya
    Nov 15 '18 at 11:44














0












0








0


0






I have a table users with following columns and attributes



users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0
)


foreigner values is 0 and 1 default 0
how I can create unique index on column ssn, when checked foreigner value is 0.



id     ssn    foreigner
1 55 0 true
2 60 1 true
3 60 1 true
----------------------------------
4 55 0 false
----------------------------------
5 77 0 true









share|improve this question
















I have a table users with following columns and attributes



users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0
)


foreigner values is 0 and 1 default 0
how I can create unique index on column ssn, when checked foreigner value is 0.



id     ssn    foreigner
1 55 0 true
2 60 1 true
3 60 1 true
----------------------------------
4 55 0 false
----------------------------------
5 77 0 true






mysql sql database






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 12:23









Raza Rafaideen

5981519




5981519










asked Nov 15 '18 at 11:43









Meqenaneri VacharqMeqenaneri Vacharq

217




217













  • Can there be multiple rows possible with (55,1) ?

    – Madhur Bhaiya
    Nov 15 '18 at 11:44



















  • Can there be multiple rows possible with (55,1) ?

    – Madhur Bhaiya
    Nov 15 '18 at 11:44

















Can there be multiple rows possible with (55,1) ?

– Madhur Bhaiya
Nov 15 '18 at 11:44





Can there be multiple rows possible with (55,1) ?

– Madhur Bhaiya
Nov 15 '18 at 11:44












1 Answer
1






active

oldest

votes


















1














You can only do this without a trigger in MySQL using the most recent versions of MySQL.



create table users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0,
foreigner_ssn tinyint generated always as (case when foreigner = 0 then ssn end) store unique
);


This creates a new generated column. MySQL unique indexes to repeat NULL values, so the condition is really only on foreigner = 0.



You could possibly simplify this, just by having ssn be NULL when foreigner = 0 and declaring that to be unique.






share|improve this answer


























  • topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

    – Raymond Nijland
    Nov 15 '18 at 12:20













  • thank you for your response. I am using 5.5.56-MariaDB

    – Meqenaneri Vacharq
    Nov 15 '18 at 12:29











  • [Err] 1904 - Key/Index cannot be defined on a non-stored computed column

    – Meqenaneri Vacharq
    Nov 15 '18 at 13:05











  • @MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

    – Gordon Linoff
    Nov 15 '18 at 13:24











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1 Answer
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1 Answer
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active

oldest

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active

oldest

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active

oldest

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1














You can only do this without a trigger in MySQL using the most recent versions of MySQL.



create table users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0,
foreigner_ssn tinyint generated always as (case when foreigner = 0 then ssn end) store unique
);


This creates a new generated column. MySQL unique indexes to repeat NULL values, so the condition is really only on foreigner = 0.



You could possibly simplify this, just by having ssn be NULL when foreigner = 0 and declaring that to be unique.






share|improve this answer


























  • topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

    – Raymond Nijland
    Nov 15 '18 at 12:20













  • thank you for your response. I am using 5.5.56-MariaDB

    – Meqenaneri Vacharq
    Nov 15 '18 at 12:29











  • [Err] 1904 - Key/Index cannot be defined on a non-stored computed column

    – Meqenaneri Vacharq
    Nov 15 '18 at 13:05











  • @MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

    – Gordon Linoff
    Nov 15 '18 at 13:24
















1














You can only do this without a trigger in MySQL using the most recent versions of MySQL.



create table users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0,
foreigner_ssn tinyint generated always as (case when foreigner = 0 then ssn end) store unique
);


This creates a new generated column. MySQL unique indexes to repeat NULL values, so the condition is really only on foreigner = 0.



You could possibly simplify this, just by having ssn be NULL when foreigner = 0 and declaring that to be unique.






share|improve this answer


























  • topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

    – Raymond Nijland
    Nov 15 '18 at 12:20













  • thank you for your response. I am using 5.5.56-MariaDB

    – Meqenaneri Vacharq
    Nov 15 '18 at 12:29











  • [Err] 1904 - Key/Index cannot be defined on a non-stored computed column

    – Meqenaneri Vacharq
    Nov 15 '18 at 13:05











  • @MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

    – Gordon Linoff
    Nov 15 '18 at 13:24














1












1








1







You can only do this without a trigger in MySQL using the most recent versions of MySQL.



create table users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0,
foreigner_ssn tinyint generated always as (case when foreigner = 0 then ssn end) store unique
);


This creates a new generated column. MySQL unique indexes to repeat NULL values, so the condition is really only on foreigner = 0.



You could possibly simplify this, just by having ssn be NULL when foreigner = 0 and declaring that to be unique.






share|improve this answer















You can only do this without a trigger in MySQL using the most recent versions of MySQL.



create table users (
id int(11),
ssn varchar(100),
foreigner tinyint(1) default 0,
foreigner_ssn tinyint generated always as (case when foreigner = 0 then ssn end) store unique
);


This creates a new generated column. MySQL unique indexes to repeat NULL values, so the condition is really only on foreigner = 0.



You could possibly simplify this, just by having ssn be NULL when foreigner = 0 and declaring that to be unique.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 15 '18 at 13:24

























answered Nov 15 '18 at 11:50









Gordon LinoffGordon Linoff

784k35310415




784k35310415













  • topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

    – Raymond Nijland
    Nov 15 '18 at 12:20













  • thank you for your response. I am using 5.5.56-MariaDB

    – Meqenaneri Vacharq
    Nov 15 '18 at 12:29











  • [Err] 1904 - Key/Index cannot be defined on a non-stored computed column

    – Meqenaneri Vacharq
    Nov 15 '18 at 13:05











  • @MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

    – Gordon Linoff
    Nov 15 '18 at 13:24



















  • topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

    – Raymond Nijland
    Nov 15 '18 at 12:20













  • thank you for your response. I am using 5.5.56-MariaDB

    – Meqenaneri Vacharq
    Nov 15 '18 at 12:29











  • [Err] 1904 - Key/Index cannot be defined on a non-stored computed column

    – Meqenaneri Vacharq
    Nov 15 '18 at 13:05











  • @MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

    – Gordon Linoff
    Nov 15 '18 at 13:24

















topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

– Raymond Nijland
Nov 15 '18 at 12:20







topicstarter and or future readers but keep in mind this query only works on a InnoDB table engine which supports indexing on virtaul columns like this.. MyISAM only supports it when you use stored see demos InnoDB db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/1 and MyISAM db-fiddle.com/f/5EFMpZn1czkM5rM8rJPb3V/0 .. But who is using MyISAM nowadays all modern MySQL versions run InnoDB table engine as default now..

– Raymond Nijland
Nov 15 '18 at 12:20















thank you for your response. I am using 5.5.56-MariaDB

– Meqenaneri Vacharq
Nov 15 '18 at 12:29





thank you for your response. I am using 5.5.56-MariaDB

– Meqenaneri Vacharq
Nov 15 '18 at 12:29













[Err] 1904 - Key/Index cannot be defined on a non-stored computed column

– Meqenaneri Vacharq
Nov 15 '18 at 13:05





[Err] 1904 - Key/Index cannot be defined on a non-stored computed column

– Meqenaneri Vacharq
Nov 15 '18 at 13:05













@MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

– Gordon Linoff
Nov 15 '18 at 13:24





@MeqenaneriVacharq . . . So store the value (the store keyword). I wasn't sure if that would be necessary.

– Gordon Linoff
Nov 15 '18 at 13:24




















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