transient lazy vals in constructor












0















I would like to declare a @transient lazy val as a constructor parameter. Example:



class Foo(@transient lazy val foo: FooFoo).



Scala 2.11 does not yet seem to have support for this. The suggested way in the issue linked above is to declare another lazy val as a class member, and have it point to the call-by-name constructor parameter.



Example (from the issue):



def f[a](lazy t: a) = {
..
}


should be equivalent to:



def f[a](t': => a) = {
lazy val t: a = t'
..
}


My question is: Will the second method ensure that the lazy val is correctly initialized upon deserialization on being referenced for the first time?










share|improve this question





























    0















    I would like to declare a @transient lazy val as a constructor parameter. Example:



    class Foo(@transient lazy val foo: FooFoo).



    Scala 2.11 does not yet seem to have support for this. The suggested way in the issue linked above is to declare another lazy val as a class member, and have it point to the call-by-name constructor parameter.



    Example (from the issue):



    def f[a](lazy t: a) = {
    ..
    }


    should be equivalent to:



    def f[a](t': => a) = {
    lazy val t: a = t'
    ..
    }


    My question is: Will the second method ensure that the lazy val is correctly initialized upon deserialization on being referenced for the first time?










    share|improve this question



























      0












      0








      0








      I would like to declare a @transient lazy val as a constructor parameter. Example:



      class Foo(@transient lazy val foo: FooFoo).



      Scala 2.11 does not yet seem to have support for this. The suggested way in the issue linked above is to declare another lazy val as a class member, and have it point to the call-by-name constructor parameter.



      Example (from the issue):



      def f[a](lazy t: a) = {
      ..
      }


      should be equivalent to:



      def f[a](t': => a) = {
      lazy val t: a = t'
      ..
      }


      My question is: Will the second method ensure that the lazy val is correctly initialized upon deserialization on being referenced for the first time?










      share|improve this question
















      I would like to declare a @transient lazy val as a constructor parameter. Example:



      class Foo(@transient lazy val foo: FooFoo).



      Scala 2.11 does not yet seem to have support for this. The suggested way in the issue linked above is to declare another lazy val as a class member, and have it point to the call-by-name constructor parameter.



      Example (from the issue):



      def f[a](lazy t: a) = {
      ..
      }


      should be equivalent to:



      def f[a](t': => a) = {
      lazy val t: a = t'
      ..
      }


      My question is: Will the second method ensure that the lazy val is correctly initialized upon deserialization on being referenced for the first time?







      scala lazy-evaluation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 0:42







      lostsoul29

















      asked Nov 14 '18 at 0:35









      lostsoul29lostsoul29

      3451515




      3451515
























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