Python - Substituting regex matches in byte file
Struggling to automate a text file cleanup for some subsequent data analysis. I have a text to tab file where I need to remove instances of t" text (remove the " but keep the tab).
I then want to remove instances of n where the character before is nor r. i.e. rn is OK xn is not. I have the first part working but not the second part any help appreciated. I appreciate there are probably way better ways to do this given I'm writing then opening in a byte format simply because I can't seem to detect /r in 'r' mode.
import re
import sys
import time
originalFile = '14-09 - Copy.txt'
amendedFile = '14-09 - amended.txt'
with open(originalFile, 'r') as content_file:
content = content_file.read()
content = content.replace('t"','t')
with open(amendedFile,'w') as f:
f.write(content)
with open(amendedFile, 'rb') as content_file:
content = content_file.read()
content = re.sub(b"(?<!r)n","", content)
with open(amendedFile,'wb') as f:
f.write(content)
print("Done")
For clarity or completion, the python 2 code below identifies the positions that I'm interested in (I'm just looking to automate their removal now). i.e.
rnText should equal rnText
tnText should equal tText
TextnText should equal TextText
import re
import sys
import time
with open('14-09 - Copy.txt', 'rb') as content_file:
content = content_file.read()
newLinePos = [m.start() for m in re.finditer('n', content)]
for line in newLinePos:
if (content[line-1]) != 'r':
print (repr(content[line-20:line]))
Thanks as always!
python regex python-3.x
asked Nov 14 '18 at 1:03
BrodieBrodie
353
add a comment |
Struggling to automate a text file cleanup for some subsequent data analysis. I have a text to tab file where I need to remove instances of t" text (remove the " but keep the tab).
I then want to remove instances of n where the character before is nor r. i.e. rn is OK xn is not. I have the first part working but not the second part any help appreciated. I appreciate there are probably way better ways to do this given I'm writing then opening in a byte format simply because I can't seem to detect /r in 'r' mode.
import re
import sys
import time
originalFile = '14-09 - Copy.txt'
amendedFile = '14-09 - amended.txt'
with open(originalFile, 'r') as content_file:
content = content_file.read()
content = content.replace('t"','t')
with open(amendedFile,'w') as f:
f.write(content)
with open(amendedFile, 'rb') as content_file:
content = content_file.read()
content = re.sub(b"(?<!r)n","", content)
with open(amendedFile,'wb') as f:
f.write(content)
print("Done")
For clarity or completion, the python 2 code below identifies the positions that I'm interested in (I'm just looking to automate their removal now). i.e.
rnText should equal rnText
tnText should equal tText
TextnText should equal TextText
import re
import sys
import time
with open('14-09 - Copy.txt', 'rb') as content_file:
content = content_file.read()
newLinePos = [m.start() for m in re.finditer('n', content)]
for line in newLinePos:
if (content[line-1]) != 'r':
print (repr(content[line-20:line]))
Thanks as always!
python regex python-3.x
asked Nov 14 '18 at 1:03
BrodieBrodie
353
add a comment |
Struggling to automate a text file cleanup for some subsequent data analysis. I have a text to tab file where I need to remove instances of t" text (remove the " but keep the tab).
I then want to remove instances of n where the character before is nor r. i.e. rn is OK xn is not. I have the first part working but not the second part any help appreciated. I appreciate there are probably way better ways to do this given I'm writing then opening in a byte format simply because I can't seem to detect /r in 'r' mode.
import re
import sys
import time
originalFile = '14-09 - Copy.txt'
amendedFile = '14-09 - amended.txt'
with open(originalFile, 'r') as content_file:
content = content_file.read()
content = content.replace('t"','t')
with open(amendedFile,'w') as f:
f.write(content)
with open(amendedFile, 'rb') as content_file:
content = content_file.read()
content = re.sub(b"(?<!r)n","", content)
with open(amendedFile,'wb') as f:
f.write(content)
print("Done")
For clarity or completion, the python 2 code below identifies the positions that I'm interested in (I'm just looking to automate their removal now). i.e.
rnText should equal rnText
tnText should equal tText
TextnText should equal TextText
import re
import sys
import time
with open('14-09 - Copy.txt', 'rb') as content_file:
content = content_file.read()
newLinePos = [m.start() for m in re.finditer('n', content)]
for line in newLinePos:
if (content[line-1]) != 'r':
print (repr(content[line-20:line]))
Thanks as always!
python regex python-3.x
asked Nov 14 '18 at 1:03
BrodieBrodie
353
Struggling to automate a text file cleanup for some subsequent data analysis. I have a text to tab file where I need to remove instances of t" text (remove the " but keep the tab).
I then want to remove instances of n where the character before is nor r. i.e. rn is OK xn is not. I have the first part working but not the second part any help appreciated. I appreciate there are probably way better ways to do this given I'm writing then opening in a byte format simply because I can't seem to detect /r in 'r' mode.
import re
import sys
import time
originalFile = '14-09 - Copy.txt'
amendedFile = '14-09 - amended.txt'
with open(originalFile, 'r') as content_file:
content = content_file.read()
content = content.replace('t"','t')
with open(amendedFile,'w') as f:
f.write(content)
with open(amendedFile, 'rb') as content_file:
content = content_file.read()
content = re.sub(b"(?<!r)n","", content)
with open(amendedFile,'wb') as f:
f.write(content)
print("Done")
For clarity or completion, the python 2 code below identifies the positions that I'm interested in (I'm just looking to automate their removal now). i.e.
rnText should equal rnText
tnText should equal tText
TextnText should equal TextText
import re
import sys
import time
with open('14-09 - Copy.txt', 'rb') as content_file:
content = content_file.read()
newLinePos = [m.start() for m in re.finditer('n', content)]
for line in newLinePos:
if (content[line-1]) != 'r':
print (repr(content[line-20:line]))
Thanks as always!
python regex python-3.x
python regex python-3.x
asked Nov 14 '18 at 1:03
BrodieBrodie
353
asked Nov 14 '18 at 1:03
BrodieBrodie
353
asked Nov 14 '18 at 1:03
BrodieBrodie
353
asked Nov 14 '18 at 1:03
BrodieBrodie
353
asked Nov 14 '18 at 1:03
BrodieBrodie
353
353
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You probably want to use ([^r])n as your pattern, and then substitute 1 to keep the character before.
So your line would be
content = re.sub(b"([^r])n",r"1", content)
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You probably want to use ([^r])n as your pattern, and then substitute 1 to keep the character before.
So your line would be
content = re.sub(b"([^r])n",r"1", content)
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
add a comment |
You probably want to use ([^r])n as your pattern, and then substitute 1 to keep the character before.
So your line would be
content = re.sub(b"([^r])n",r"1", content)
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
add a comment |
You probably want to use ([^r])n as your pattern, and then substitute 1 to keep the character before.
So your line would be
content = re.sub(b"([^r])n",r"1", content)
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
You probably want to use ([^r])n as your pattern, and then substitute 1 to keep the character before.
So your line would be
content = re.sub(b"([^r])n",r"1", content)
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
answered Nov 14 '18 at 1:35
B. MorrisB. Morris
1718
1718
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
add a comment |
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
This is really close but I'm looking to remove the char. I can see it in notepad++ as CRLF - equiv to /r/n (as opposed to the original CR /r). I'm guessing when I write out via 'w' that it changes CR to CRLF so switched the code around although I exhibit same behaviour. Any ideas? ie detect /r not proceed by /n and remove the /r?
– Brodie
Nov 14 '18 at 5:25
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
Thanks - ignore last comment. This works perfectly provided I execute the write rb first as otherwise it automatically appends n as rn! I was executing one of the opens in the wrong order.
– Brodie
Nov 14 '18 at 5:41
add a comment |
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