Reversing an entered numbers in C language
I just want to ask on why is there a need to write sum = sum*10+digit instead of just sum = 0+digit? since the result of sum*10 is just 0. This is a code in C language for reversing an entered number. Thanks!
#include <stdio.h>
int main()
{
int number, x = 0, digit, temporary, div = 10, sum = 0;
printf("Enter numbersn");
scanf("%d", &number);
temporary = number;
START:
digit = number%div;
sum = sum*10+digit;
number = number/div;
if(number>0)
goto START;
printf("Reversed Number = %dn", temporary);
printf("Reversed Number = %dn", sum);
return 0;
}
c
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
add a comment |
I just want to ask on why is there a need to write sum = sum*10+digit instead of just sum = 0+digit? since the result of sum*10 is just 0. This is a code in C language for reversing an entered number. Thanks!
#include <stdio.h>
int main()
{
int number, x = 0, digit, temporary, div = 10, sum = 0;
printf("Enter numbersn");
scanf("%d", &number);
temporary = number;
START:
digit = number%div;
sum = sum*10+digit;
number = number/div;
if(number>0)
goto START;
printf("Reversed Number = %dn", temporary);
printf("Reversed Number = %dn", sum);
return 0;
}
c
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
1
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
It issum * 10because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.
– luci88filter
Nov 14 '18 at 7:56
add a comment |
I just want to ask on why is there a need to write sum = sum*10+digit instead of just sum = 0+digit? since the result of sum*10 is just 0. This is a code in C language for reversing an entered number. Thanks!
#include <stdio.h>
int main()
{
int number, x = 0, digit, temporary, div = 10, sum = 0;
printf("Enter numbersn");
scanf("%d", &number);
temporary = number;
START:
digit = number%div;
sum = sum*10+digit;
number = number/div;
if(number>0)
goto START;
printf("Reversed Number = %dn", temporary);
printf("Reversed Number = %dn", sum);
return 0;
}
c
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
I just want to ask on why is there a need to write sum = sum*10+digit instead of just sum = 0+digit? since the result of sum*10 is just 0. This is a code in C language for reversing an entered number. Thanks!
#include <stdio.h>
int main()
{
int number, x = 0, digit, temporary, div = 10, sum = 0;
printf("Enter numbersn");
scanf("%d", &number);
temporary = number;
START:
digit = number%div;
sum = sum*10+digit;
number = number/div;
if(number>0)
goto START;
printf("Reversed Number = %dn", temporary);
printf("Reversed Number = %dn", sum);
return 0;
}
c
c
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
edited Nov 14 '18 at 0:59
Yunnosch
11.2k52033
11.2k52033
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
asked Nov 14 '18 at 0:52
Mark ReyesMark Reyes
1
1
1
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
It issum * 10because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.
– luci88filter
Nov 14 '18 at 7:56
add a comment |
1
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
It issum * 10because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.
– luci88filter
Nov 14 '18 at 7:56
1
1
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
It is
sum * 10 because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.– luci88filter
Nov 14 '18 at 7:56
It is
sum * 10 because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.– luci88filter
Nov 14 '18 at 7:56
add a comment |
1 Answer
1
active
oldest
votes
In a situation like this it is a very good thing to examine what is happening with simple printouts. If you insert printf("sum: %d digit: %d number: %dn", sum, digit, number); before the if statement, it will become obvious what's going on.
$ ./a.out
Enter numbers
2345
sum: 5 digit: 5 number: 234
sum: 54 digit: 4 number: 23
sum: 543 digit: 3 number: 2
sum: 5432 digit: 2 number: 0
Reversed Number = 2345
Reversed Number = 5432
Sidenote: There are "approved" ways of using goto. This is not one of them. You should switch
START:
...
if(number>0)
goto START;
to
do {
...
} while(number>0)
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
In a situation like this it is a very good thing to examine what is happening with simple printouts. If you insert printf("sum: %d digit: %d number: %dn", sum, digit, number); before the if statement, it will become obvious what's going on.
$ ./a.out
Enter numbers
2345
sum: 5 digit: 5 number: 234
sum: 54 digit: 4 number: 23
sum: 543 digit: 3 number: 2
sum: 5432 digit: 2 number: 0
Reversed Number = 2345
Reversed Number = 5432
Sidenote: There are "approved" ways of using goto. This is not one of them. You should switch
START:
...
if(number>0)
goto START;
to
do {
...
} while(number>0)
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
add a comment |
In a situation like this it is a very good thing to examine what is happening with simple printouts. If you insert printf("sum: %d digit: %d number: %dn", sum, digit, number); before the if statement, it will become obvious what's going on.
$ ./a.out
Enter numbers
2345
sum: 5 digit: 5 number: 234
sum: 54 digit: 4 number: 23
sum: 543 digit: 3 number: 2
sum: 5432 digit: 2 number: 0
Reversed Number = 2345
Reversed Number = 5432
Sidenote: There are "approved" ways of using goto. This is not one of them. You should switch
START:
...
if(number>0)
goto START;
to
do {
...
} while(number>0)
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
add a comment |
In a situation like this it is a very good thing to examine what is happening with simple printouts. If you insert printf("sum: %d digit: %d number: %dn", sum, digit, number); before the if statement, it will become obvious what's going on.
$ ./a.out
Enter numbers
2345
sum: 5 digit: 5 number: 234
sum: 54 digit: 4 number: 23
sum: 543 digit: 3 number: 2
sum: 5432 digit: 2 number: 0
Reversed Number = 2345
Reversed Number = 5432
Sidenote: There are "approved" ways of using goto. This is not one of them. You should switch
START:
...
if(number>0)
goto START;
to
do {
...
} while(number>0)
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
In a situation like this it is a very good thing to examine what is happening with simple printouts. If you insert printf("sum: %d digit: %d number: %dn", sum, digit, number); before the if statement, it will become obvious what's going on.
$ ./a.out
Enter numbers
2345
sum: 5 digit: 5 number: 234
sum: 54 digit: 4 number: 23
sum: 543 digit: 3 number: 2
sum: 5432 digit: 2 number: 0
Reversed Number = 2345
Reversed Number = 5432
Sidenote: There are "approved" ways of using goto. This is not one of them. You should switch
START:
...
if(number>0)
goto START;
to
do {
...
} while(number>0)
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
edited Nov 14 '18 at 1:03
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
answered Nov 14 '18 at 0:57
BromanBroman
6,317112341
6,317112341
add a comment |
add a comment |
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1
After the first time, sum is not 0 anymore. So what happens if sum is the first used digit?
– Yunnosch
Nov 14 '18 at 0:56
It is
sum * 10because each iteration you need to shift everything to the left just like when multiplying by 2 in binary you shift everything to the left.– luci88filter
Nov 14 '18 at 7:56