Search Registry and create New-Item
I want to create a New-Item in the registry with a pre check what already exists.
This code
$items = get-item "HKCU:SOFTWAREMicrosoftOffice16.0ExcelOptions"
$items.Property -match "OPEN"
returns the following
OPEN
OPEN1
OPEN2
OPEN3
OPEN4
Now I know I need to create a New-Item with the name OPEN5, but how do I count through this? Maybe with a While-Loop?
powershell while-loop registry new-item
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
add a comment |
I want to create a New-Item in the registry with a pre check what already exists.
This code
$items = get-item "HKCU:SOFTWAREMicrosoftOffice16.0ExcelOptions"
$items.Property -match "OPEN"
returns the following
OPEN
OPEN1
OPEN2
OPEN3
OPEN4
Now I know I need to create a New-Item with the name OPEN5, but how do I count through this? Maybe with a While-Loop?
powershell while-loop registry new-item
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
You could do something likefor ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }
– trebleCode
Nov 13 '18 at 15:34
add a comment |
I want to create a New-Item in the registry with a pre check what already exists.
This code
$items = get-item "HKCU:SOFTWAREMicrosoftOffice16.0ExcelOptions"
$items.Property -match "OPEN"
returns the following
OPEN
OPEN1
OPEN2
OPEN3
OPEN4
Now I know I need to create a New-Item with the name OPEN5, but how do I count through this? Maybe with a While-Loop?
powershell while-loop registry new-item
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
I want to create a New-Item in the registry with a pre check what already exists.
This code
$items = get-item "HKCU:SOFTWAREMicrosoftOffice16.0ExcelOptions"
$items.Property -match "OPEN"
returns the following
OPEN
OPEN1
OPEN2
OPEN3
OPEN4
Now I know I need to create a New-Item with the name OPEN5, but how do I count through this? Maybe with a While-Loop?
powershell while-loop registry new-item
powershell while-loop registry new-item
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
asked Nov 13 '18 at 14:52
aston_zhaston_zh
1,93331119
1,93331119
You could do something likefor ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }
– trebleCode
Nov 13 '18 at 15:34
add a comment |
You could do something likefor ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }
– trebleCode
Nov 13 '18 at 15:34
You could do something like
for ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }– trebleCode
Nov 13 '18 at 15:34
You could do something like
for ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }– trebleCode
Nov 13 '18 at 15:34
add a comment |
1 Answer
1
active
oldest
votes
The most robust approach is to extract the embedded numbers, sort them numerically, and add 1 to the highest index to date:
$nextNdx = 1 +
([int] ($items.Property -match '^OPEN' -replace 'D') | Sort-Object)[-1]
$items.Property -match '^OPEN' -replace 'D'returns all property names that start withOPENand removes all non-digit characters from them (-replace 'D').[int]converts the resulting "number strings" to actual numbers ([int]); note that casting''or$nullto[int]in PowerShell yields0.Sort-Objectsorts these numbers, and[-1]grabs the last number from the resulting array, i.e., the highest number.
The above is convenient, but not fast, due to use of the pipeline and the Sort-Object cmdlet.
If you want to avoid the pipeline for performance reasons:
$indices = [int] ($items.Property -match '^OPEN' -replace 'D')
[Array]::Sort($indices) # sort in place
$nextNdx = 1 + $indices[-1]
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The most robust approach is to extract the embedded numbers, sort them numerically, and add 1 to the highest index to date:
$nextNdx = 1 +
([int] ($items.Property -match '^OPEN' -replace 'D') | Sort-Object)[-1]
$items.Property -match '^OPEN' -replace 'D'returns all property names that start withOPENand removes all non-digit characters from them (-replace 'D').[int]converts the resulting "number strings" to actual numbers ([int]); note that casting''or$nullto[int]in PowerShell yields0.Sort-Objectsorts these numbers, and[-1]grabs the last number from the resulting array, i.e., the highest number.
The above is convenient, but not fast, due to use of the pipeline and the Sort-Object cmdlet.
If you want to avoid the pipeline for performance reasons:
$indices = [int] ($items.Property -match '^OPEN' -replace 'D')
[Array]::Sort($indices) # sort in place
$nextNdx = 1 + $indices[-1]
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
add a comment |
The most robust approach is to extract the embedded numbers, sort them numerically, and add 1 to the highest index to date:
$nextNdx = 1 +
([int] ($items.Property -match '^OPEN' -replace 'D') | Sort-Object)[-1]
$items.Property -match '^OPEN' -replace 'D'returns all property names that start withOPENand removes all non-digit characters from them (-replace 'D').[int]converts the resulting "number strings" to actual numbers ([int]); note that casting''or$nullto[int]in PowerShell yields0.Sort-Objectsorts these numbers, and[-1]grabs the last number from the resulting array, i.e., the highest number.
The above is convenient, but not fast, due to use of the pipeline and the Sort-Object cmdlet.
If you want to avoid the pipeline for performance reasons:
$indices = [int] ($items.Property -match '^OPEN' -replace 'D')
[Array]::Sort($indices) # sort in place
$nextNdx = 1 + $indices[-1]
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
add a comment |
The most robust approach is to extract the embedded numbers, sort them numerically, and add 1 to the highest index to date:
$nextNdx = 1 +
([int] ($items.Property -match '^OPEN' -replace 'D') | Sort-Object)[-1]
$items.Property -match '^OPEN' -replace 'D'returns all property names that start withOPENand removes all non-digit characters from them (-replace 'D').[int]converts the resulting "number strings" to actual numbers ([int]); note that casting''or$nullto[int]in PowerShell yields0.Sort-Objectsorts these numbers, and[-1]grabs the last number from the resulting array, i.e., the highest number.
The above is convenient, but not fast, due to use of the pipeline and the Sort-Object cmdlet.
If you want to avoid the pipeline for performance reasons:
$indices = [int] ($items.Property -match '^OPEN' -replace 'D')
[Array]::Sort($indices) # sort in place
$nextNdx = 1 + $indices[-1]
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
The most robust approach is to extract the embedded numbers, sort them numerically, and add 1 to the highest index to date:
$nextNdx = 1 +
([int] ($items.Property -match '^OPEN' -replace 'D') | Sort-Object)[-1]
$items.Property -match '^OPEN' -replace 'D'returns all property names that start withOPENand removes all non-digit characters from them (-replace 'D').[int]converts the resulting "number strings" to actual numbers ([int]); note that casting''or$nullto[int]in PowerShell yields0.Sort-Objectsorts these numbers, and[-1]grabs the last number from the resulting array, i.e., the highest number.
The above is convenient, but not fast, due to use of the pipeline and the Sort-Object cmdlet.
If you want to avoid the pipeline for performance reasons:
$indices = [int] ($items.Property -match '^OPEN' -replace 'D')
[Array]::Sort($indices) # sort in place
$nextNdx = 1 + $indices[-1]
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
edited Nov 13 '18 at 16:03
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
answered Nov 13 '18 at 15:46
mklement0mklement0
128k20242271
128k20242271
add a comment |
add a comment |
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You could do something like
for ($i = 0; $i -lt $items.Count; $i++ { # implementation code here }– trebleCode
Nov 13 '18 at 15:34