Moving array elements to the left












1














Writing a code that shifts array elements left by an int n (keyboard input) and replaces space with zeros.



Ex. int data = { -1, 1, 3, 7, 5} and I want to see { 3, 7, 5, 0, 0}.
Suppose I have:



public static void shiftLeft( int data, int n )
{
System.arraycopy( data, 1, data, 0, data.length - 1 );
data[data.length - 1] = 0;
}


Any quick help would be great.










share|improve this question
























  • You are not using n. You've hard-coded 1 instead.
    – Johnny Mopp
    Nov 12 '18 at 18:11
















1














Writing a code that shifts array elements left by an int n (keyboard input) and replaces space with zeros.



Ex. int data = { -1, 1, 3, 7, 5} and I want to see { 3, 7, 5, 0, 0}.
Suppose I have:



public static void shiftLeft( int data, int n )
{
System.arraycopy( data, 1, data, 0, data.length - 1 );
data[data.length - 1] = 0;
}


Any quick help would be great.










share|improve this question
























  • You are not using n. You've hard-coded 1 instead.
    – Johnny Mopp
    Nov 12 '18 at 18:11














1












1








1







Writing a code that shifts array elements left by an int n (keyboard input) and replaces space with zeros.



Ex. int data = { -1, 1, 3, 7, 5} and I want to see { 3, 7, 5, 0, 0}.
Suppose I have:



public static void shiftLeft( int data, int n )
{
System.arraycopy( data, 1, data, 0, data.length - 1 );
data[data.length - 1] = 0;
}


Any quick help would be great.










share|improve this question















Writing a code that shifts array elements left by an int n (keyboard input) and replaces space with zeros.



Ex. int data = { -1, 1, 3, 7, 5} and I want to see { 3, 7, 5, 0, 0}.
Suppose I have:



public static void shiftLeft( int data, int n )
{
System.arraycopy( data, 1, data, 0, data.length - 1 );
data[data.length - 1] = 0;
}


Any quick help would be great.







java arrays






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edited Nov 12 '18 at 18:19









Gayan Mettananda

780510




780510










asked Nov 12 '18 at 18:07









KoopaMarkley

1710




1710












  • You are not using n. You've hard-coded 1 instead.
    – Johnny Mopp
    Nov 12 '18 at 18:11


















  • You are not using n. You've hard-coded 1 instead.
    – Johnny Mopp
    Nov 12 '18 at 18:11
















You are not using n. You've hard-coded 1 instead.
– Johnny Mopp
Nov 12 '18 at 18:11




You are not using n. You've hard-coded 1 instead.
– Johnny Mopp
Nov 12 '18 at 18:11












1 Answer
1






active

oldest

votes


















1














You were close, but your srcPos argument should be n and the length argument should be data.length - n. You can then use the overloaded Arrays#fill method that accepts a start/end index to fill the rest of the array with 0:



public static void shiftLeft(int data, int n) {
System.arraycopy(data, n, data, 0, data.length - n);
Arrays.fill(data, data.length - n, data.length, 0);
}


Testing this with your example input yields the following:



int data = { -1, 1, 3, 7, 5};
shiftLeft(data, 2);
System.out.println(Arrays.toString(data));


Output:



[3, 7, 5, 0, 0]





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    1














    You were close, but your srcPos argument should be n and the length argument should be data.length - n. You can then use the overloaded Arrays#fill method that accepts a start/end index to fill the rest of the array with 0:



    public static void shiftLeft(int data, int n) {
    System.arraycopy(data, n, data, 0, data.length - n);
    Arrays.fill(data, data.length - n, data.length, 0);
    }


    Testing this with your example input yields the following:



    int data = { -1, 1, 3, 7, 5};
    shiftLeft(data, 2);
    System.out.println(Arrays.toString(data));


    Output:



    [3, 7, 5, 0, 0]





    share|improve this answer


























      1














      You were close, but your srcPos argument should be n and the length argument should be data.length - n. You can then use the overloaded Arrays#fill method that accepts a start/end index to fill the rest of the array with 0:



      public static void shiftLeft(int data, int n) {
      System.arraycopy(data, n, data, 0, data.length - n);
      Arrays.fill(data, data.length - n, data.length, 0);
      }


      Testing this with your example input yields the following:



      int data = { -1, 1, 3, 7, 5};
      shiftLeft(data, 2);
      System.out.println(Arrays.toString(data));


      Output:



      [3, 7, 5, 0, 0]





      share|improve this answer
























        1












        1








        1






        You were close, but your srcPos argument should be n and the length argument should be data.length - n. You can then use the overloaded Arrays#fill method that accepts a start/end index to fill the rest of the array with 0:



        public static void shiftLeft(int data, int n) {
        System.arraycopy(data, n, data, 0, data.length - n);
        Arrays.fill(data, data.length - n, data.length, 0);
        }


        Testing this with your example input yields the following:



        int data = { -1, 1, 3, 7, 5};
        shiftLeft(data, 2);
        System.out.println(Arrays.toString(data));


        Output:



        [3, 7, 5, 0, 0]





        share|improve this answer












        You were close, but your srcPos argument should be n and the length argument should be data.length - n. You can then use the overloaded Arrays#fill method that accepts a start/end index to fill the rest of the array with 0:



        public static void shiftLeft(int data, int n) {
        System.arraycopy(data, n, data, 0, data.length - n);
        Arrays.fill(data, data.length - n, data.length, 0);
        }


        Testing this with your example input yields the following:



        int data = { -1, 1, 3, 7, 5};
        shiftLeft(data, 2);
        System.out.println(Arrays.toString(data));


        Output:



        [3, 7, 5, 0, 0]






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 18:16









        Jacob G.

        15.2k52162




        15.2k52162






























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